Physics HW help please Solution We have two equations v y = v o sin (theta) - ---- (1) v x = v o cos (theta) ------ (2) we are given v x and v y , so we can find theta from this dividing 1 by 2 we get tan (theta) = v y / v x theta = tan - 1 (v y / v x ) theta = 53.13 degree so, Original velcoity, v o = v x / cos (theta) v o = 30 / cos 53.13 v o = 49.99 m/s ( 50 m/s - approx) Mamimum height can be found out using standard formula H = v o 2 sin 2 (theta) / 2g Similarly, Range R = v o 2 sin (2*theta) / g .