The class mean and the standard deviation on test A are 60 and 8 respectively, while the class mean and the standard deviation on test B are 80 and 8. If a student scores 80 on test A and 92 on test B, Which test score is higher relative to its respective class? Solution We assume that the scores follow normal distribution 80 on test A: proportion of people who get less that 80 = No((80-60)/8))=P(A) prop of who get less than 92 in B= No((92- 80))/8)=P(B) Where No is the standard normal distribution table. It is clear that P(A)>P(B) Here\'s such a table So, a 80 score in relatively higher compared to 92 in B http://training.ce.washington.edu/pgi/Modules/08_specifications_qa/Images/main_pictures/norm al_table.gif.

1. The class mean and the standard deviation on test A are 60 and 8 respectively, while the class
mean and the standard deviation on test B are 80 and 8. If a student scores 80 on test A and 92 on
test B, Which test score is higher relative to its respective class?
Solution
We assume that the scores follow normal distribution 80 on test A: proportion of
people who get less that 80 = No((80-60)/8))=P(A) prop of who get less than 92 in B= No((92-
80))/8)=P(B) Where No is the standard normal distribution table. It is clear that P(A)>P(B)
Here's such a table So, a 80 score in relatively higher compared to 92 in B
http://training.ce.washington.edu/pgi/Modules/08_specifications_qa/Images/main_pictures/norm
al_table.gif