The inside diameter of a cylinder has specifications 1 +- .03 cm. T.pdf

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The inside diameter of a cylinder has specifications 1 +/- .03 cm. The machining process output follows a normal distribution with mean 1 cm and standard deviation .1 cm. Determine the percentage of production that will meet the specifications. Solution = 1 = .1 we will transform x to a standard normal distribution. P( .97 < x < 1.03) = P((.97-1)/.1 < (x-)/ < (1.03-1)/.1) = P(-3 < z < 3) = .9973.

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