sorry for unformatted question, but advanced editor doesn\'t seem to be working atm let p > 0 and X_n be from a random sample with distribution f(x)=p(1-x)^(p-1), 0 <= x <= 1 Find the log likelihood of p. What I\'ve got: L(p) = prod(f(x)) = p(1-x_1)^(p-1)*p(1-x_2)^(p-1)...= p^n(1-x)^n(p-1) l(p) = ln(L(p)) = ln(p^n)(1-x)^(n*ln(p)-n) Solution ln L(p) = ln f(xi) = ln(p(1-xi)^(p-1)) = (ln p + (p-1)ln(1-xi)) = ln p + (p-1)ln(1-xi) = n ln p + (p-1) ln(1-xi) = n ln p + (p-1)(ln(1-x_1) + ln(1-x_2) + ln(1-x_3) + ..... + ln(1-x_n)).