Please show work. Thank you. Let f(x) = 4-3x. Find the following. a) f(2)= b) f(-3)= c) f(2) + f(-3)= d) f(2+3)= e) f(2x)= f) 2f(x)= g) f(x^2)= h) f(1/x)= i) f [f(x)]= j) x^2 f(x)= k) 1/f(x)= l) f(-x)= m) -f(x)= n) -f(-x)= Solution f(x) = 4 -3x now, put the values of x which is given for example f(2) here, 2 is the value of x i.e x = 2 f(2) = 4 -3 * 2 = -2 f(-3) = 4 - 3 * (-3) = 13 f(x) + f(-3) = -2 + 13 = 11 f(2 + 3) = f(5) = 4 - 3*(5) = -11 f(2x) = 4 - 3*(2x) = 4 - 6x 2f(x) = 2 (4 - 3x) = 8 - 6x f(x^2) = 4 - 3x^2 f(1/x) = 4 - (3/x) = (4x -3)/x f[f(x)] = 4 - 3(4 - 3x) = 9x - 8 x^2f(x) = x^2(4 - 3x) = 4x^2 - 3x^3 1/f(x) = 1/(4 - 3x) f(-x) = 4 -3(-x) = 4 +3x -f(x) = -(4 - 3x) = 3x - 4 -f(-x) = -(4 - 3(-x)) = -4 -3x.