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Probability
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Glue is a student in School A. He has an average score of 90 percent.
Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75
Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86.
Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school?
Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school? Which school has a better performance, School A or School B?
Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school? Which school has a better performance, School A or School B? Solution
To find the mean:
To find the mean: First, you must add all the score of each school.
To find the mean: First, you must add all the score of each school. Second, divide it by the total score.
To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75.
To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75. - so by adding it all, it is equal to 388.
To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75. - so by adding it all, it is equal to 388. - then divide it by 5, is equal to 77.6 .
Just the same as School B, it has score of :85, 87, 81, 83, 86.
Just the same as School B, it has score of :85, 87, 81, 83, 86. - so adding it all is equal to 422.
Just the same as School B, it has score of :85, 87, 81, 83, 86. - so adding it all is equal to 422. - divide it by 5 is equal to 84.4.
Standard Deviation
In finding the standard deviation:
In finding the standard deviation: First, subtract the scores to the mean and squared it like this:
In finding the standard deviation: First, subtract the scores to the mean and squared it like this:
In finding the standard deviation: Second, average the value and take the square root :
In finding the standard deviation: Second, average the value and take the square root : Standard Deviation
In finding the standard deviation: Second, average the value and take the square root : In finding the mean and Standard deviation in school B is just the same procedure in school A.
In finding the standard deviation: Second, average the value and take the square root : In finding the mean and Standard deviation in school B is just the same procedure in school A. - so, School B has mean of 84.4 and standard deviation of 2.154065923.
School A has : Mean = 77.6 Standard Deviation = 7.84 School B has : Mean = 84.4 Standard Deviation = 2.15
When it comes to performance, it depends:
When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent.
When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent. - in a matter of fact, when it comes to team work of grades School B would be the winner because of its standard deviation.
When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent. - in a matter of fact, when it comes to team work of grades School B would be the winner because of its standard deviation. Standard Deviation tells how spread out the grades or very close to the same value or (the mean).

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My Marvelous Project in Applied Math

  • 2.
  • 3. Glue is a student in School A. He has an average score of 90 percent.
  • 4. Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75
  • 5. Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86.
  • 6. Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school?
  • 7. Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school? Which school has a better performance, School A or School B?
  • 8. Glue is a student in School A. He has an average score of 90 percent. His classmate Paint, Brush, Paper and Stand has score of : 83, 71, 69, 75 School B has 5 students with score of : 85, 87, 81, 83 and 86. Find the mean and standard deviation of each school? Which school has a better performance, School A or School B? Solution
  • 9. To find the mean:
  • 10. To find the mean: First, you must add all the score of each school.
  • 11. To find the mean: First, you must add all the score of each school. Second, divide it by the total score.
  • 12. To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75.
  • 13. To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75. - so by adding it all, it is equal to 388.
  • 14. To find the mean: First, you must add all the score of each school. Second, divide it by the total score. School A has score of 90, 83, 71, 69, 75. - so by adding it all, it is equal to 388. - then divide it by 5, is equal to 77.6 .
  • 15. Just the same as School B, it has score of :85, 87, 81, 83, 86.
  • 16. Just the same as School B, it has score of :85, 87, 81, 83, 86. - so adding it all is equal to 422.
  • 17. Just the same as School B, it has score of :85, 87, 81, 83, 86. - so adding it all is equal to 422. - divide it by 5 is equal to 84.4.
  • 19. In finding the standard deviation:
  • 20. In finding the standard deviation: First, subtract the scores to the mean and squared it like this:
  • 21. In finding the standard deviation: First, subtract the scores to the mean and squared it like this:
  • 22. In finding the standard deviation: Second, average the value and take the square root :
  • 23. In finding the standard deviation: Second, average the value and take the square root : Standard Deviation
  • 24. In finding the standard deviation: Second, average the value and take the square root : In finding the mean and Standard deviation in school B is just the same procedure in school A.
  • 25. In finding the standard deviation: Second, average the value and take the square root : In finding the mean and Standard deviation in school B is just the same procedure in school A. - so, School B has mean of 84.4 and standard deviation of 2.154065923.
  • 26. School A has : Mean = 77.6 Standard Deviation = 7.84 School B has : Mean = 84.4 Standard Deviation = 2.15
  • 27. When it comes to performance, it depends:
  • 28. When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent.
  • 29. When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent. - in a matter of fact, when it comes to team work of grades School B would be the winner because of its standard deviation.
  • 30. When it comes to performance, it depends: - because when you ask who’s school has higher grade, School A has 90 percent and School B has only 87 percent. - in a matter of fact, when it comes to team work of grades School B would be the winner because of its standard deviation. Standard Deviation tells how spread out the grades or very close to the same value or (the mean).