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AP Physics Rapid Learning Series - 21
© Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 1
Rapid Learning Center
Chemistry :: Biology :: Physics :: Math
Rapid Learning Center Presents …Rapid Learning Center Presents …
Teach Yourself
AP Physics in 24 Hours
1/50
*AP is a registered trademark of the College Board, which does not endorse, nor is
affiliated in any way with the Rapid Learning courses.
Ph i l O tiPhysical Optics
Physics Rapid Learning Series
Rapid Learning Center
www.RapidLearningCenter.com/
© Rapid Learning Inc. All rights reserved.
Wayne Huang, Ph.D.
Keith Duda, M.Ed.
Peddi Prasad, Ph.D.
Gary Zhou, Ph.D.
Michelle Wedemeyer, Ph.D.
Sarah Hedges, Ph.D.
AP Physics Rapid Learning Series - 21
© Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 2
Learning Objectives
Describe the electromagnetic
spectr m and the nat re of
By completing this tutorial, you can:
spectrum and the nature of
light.
Understand constructive and
destructive interference.
Understand the concept of
diffraction and solve related
3/50
problems.
Describe the polarization of
light.
Concept Map
Physics
Studies
Previous content
New content Polarized
Light
Acts as a
Travels at
experiences
Speed of
light
Transverse
wave
Electro-
magnetic
spectrum Wave
May be
4/50
gspectrum Wave
Interference
Constructive
Interference
Destructive
Interference
In vacuum
3x108m/s
AP Physics Rapid Learning Series - 21
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TheThe
Electromagnetic
Spectrum
5/50
Electromagnetic Spectrum
The electromagnetic spectrum can be considered a
catalog or map of all the various frequencies of light.
I f d Ult i l tR di GInfrared UltravioletRadio waves Gamma
rays
6/50
Visible lightMicro waves X rays
Obviously our eyes perceive only a small amount of
the EM spectrum, visible light.
AP Physics Rapid Learning Series - 21
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EM Spectrum Observations
Note the highest frequencies/lowest
wavelengths are to the right.
7/50
Also note the lowest
frequencies/highest wavelengths
are to the left.
Electromagnetic Waves
An electromagnetic wave is an oscillating
combination of a magnetic and an electric field.
It can be visualized as two perpendicular waves
(electric and magnetic).
8/50
This view shows the light wave coming right
at you.
AP Physics Rapid Learning Series - 21
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Speed of Light
In a vacuum, all electromagnetic waves have a
velocity of 300,000,000 m/s! ( 3x108m/s)
Later we will see that this speed can vary
That’s 186,000 miles per second!
9/50
depending on the medium.
First Calculation of Light Speed
The approximate speed of light was first calculated in
1675 by Danish astronomer Olaus Roemer.
He had no computers, calculators, or other
sophisticated instruments...
10/50
AP Physics Rapid Learning Series - 21
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Observations
He used careful telescopic observations of the
motions of Jupiter’s moons.
11/50
Jupiter Moons
revolving
around planet
The Jupiter’s moon could be
observed from either side of
the Earth orbit around the
Sun
Orbital Difference
Sun.
This yielded a substantial
difference in distance for
the light to travel.
12/50
Roemer measured a 16.5
minute time difference.
AP Physics Rapid Learning Series - 21
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Calculation of Light Speed
At the time, it was known that the diameter of
Earth’s orbit was 3 x 1011m.
Roemer used this information, and his time
difference, to calculate the speed of light:
t
d
v =
990s
m3x10
v
11
=
16.5
minutes
t d
13/50
990s
m/s3.03x10v 8
=
This is surprisingly accurate for the time period.
converted
into
seconds.
Michelson’s Measurement
Fixed flat
mirror far
away
light
14/50
American physicist Albert Michelson used a rotating
mirror with fixed mirror on a distant mountain.
The speed of the mirror was used to “time” the trip
that light took to obtain a more accurate value.
AP Physics Rapid Learning Series - 21
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Constructive and
Destructive Interference
Waves often superimpose, or interfere
with each other when they overlap
15/50
with each other when they overlap.
Principle of Superposition
When two or more waves occupy the same region
of space simultaneously, the resulting wave
disturbance is the sum of separate waves.
Wave #1 Wave #2
16/50
Resulting wave due to superposition.
AP Physics Rapid Learning Series - 21
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Constructive Interference
When waves overlap or superimpose, they may
create a larger amplitude wave as a result.
wave 1
+ wave 2
Notice how
the wave
crests and
troughs line
up perfectly.
17/50
equals
Greater
amplitude
wave.
Destructive Interference
When waves overlap or superimpose, they may
create a smaller amplitude wave as a result.
Notice how
wave 1
+ wave 2
Notice how
the wave
crests and
troughs are
perfectly out
of phase.
18/50
equals
A zero
amplitude wave.
AP Physics Rapid Learning Series - 21
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Thin Film Interference
Soap bubbles and thin films of gasoline or oil often
produce pretty colored patterns.
This results from some light penetrating the film,
19/50
g p g ,
then reflecting backwards.
This light interferes with light reflecting off the
surface and creates certain colors depending on
the thickness of the film.
Coherent Light
Light waves that are all in phase, or in step with
each other, are called coherent.
This basically means that the waves don’t shift with
20/50
y
respect to each other as time passes.
AP Physics Rapid Learning Series - 21
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Monochromatic Light
Light waves that have all the same frequency/
wavelength/color are called monochromatic.
Laser light is both monochromatic and coherent.
21/50
Diffraction
Diffraction is the bending of waves
around obstacles corners or openings
22/50
around obstacles, corners, or openings.
AP Physics Rapid Learning Series - 21
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Young’s Double Slit Experiment
In 1801 Thomas Young was the first person to
measure the wavelength of light.
He sent light originating from one location incidentg g g
upon a pair of slits in a barrier and observed.
Viewing
???
23/50 Top view
screen
Coherent
light
source
???
Particle Result
If light had behaved like a particle, two spots of
light on the screen would have been observed.
Viewing
screen
Coherent
24/50
However, in this experiment, this did not happen.
In this case, light behaves like a wave!
Top view
light
source
AP Physics Rapid Learning Series - 21
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Wave Result
Instead, alternating spots of brightness and
darkness occur. This is quite strange!
Coherent
25/50
Top view
Viewing
screen
light
source
An explanation of this depends on the wave
behavior of light.
Constructive Interference Spot
A set of light waves each goes through an open
slit.
26/50
Viewing
screen
When there are bright spots, the two waves arrive
in phase, and constructively interfere, giving a
bright central spot.
AP Physics Rapid Learning Series - 21
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Different Path Lengths
Even if the two sets of wave have different distances
to travel, they can still constructively interfere to
produce a bright spot, or maxima. 1st bright
fringe
Central
spot
fringe
27/50
In these spots, the path difference between the
two waves is a whole value of wavelength, λ.
1 λ extra
Different Path Lengths Again
For area of darkness, or minima, destructive
interference occurs.
1st bright
fringe
Central
spot
g
1st dark
area
28/50
In these spots, the path difference between the
two waves is a half value of wavelength, λ/2.
1/2 λ extra
AP Physics Rapid Learning Series - 21
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Relevant Variables
Diagramed below are the relevant quantities that
will be used in problems.
1st bright
fringe
Distance
between
slits, d Length to
screen
Central
spot
θ
Distance
from
center
29/50
screen spot
Bright Spot Formula
The following formula describes the bright
fringes created by constructive interference.
d
λ
msinθ =
Wavelength,
m
Integer
m=0,1,2,3…
30/50
d
Angle between
bright spot and
central spot
Distance
between
slits, m
AP Physics Rapid Learning Series - 21
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Dark Spot Formula
The following formula describes the dark areas
created by destructive interference.
λ
1/2)(msinθ +=
Wavelength,
m
Integer
m=0,1,2,3…
31/50
d
)(
Angle between
dark spot and
central spot
Distance
between
slits, m
Double Slit Example Problem
The second dark area in an interference pattern is
noticed to be 2° away from the central bright spot.
The slits are 5x10-5 m apart. What is the wavelength
of the coherent light used?
d
λ
1/2)(msinθ +=
Use our formula for destructive interference fringes.
32/50
d
In this case, since the second dark area is being
used, m = 2.
AP Physics Rapid Learning Series - 21
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Double Slit Solution
d
λ
1/2)(msinθ += λ
1/2)(m
sinθd
=
+
1/2)(2
)sin(2m5x10
λ
-5
+
=
Calculate carefully.
Be sure to use the
correct order of
33/50
m7x10λ 7−
=
correct order of
operations. Use
degrees for
angular units.
Diffraction
Diffraction also occurs in places other than a
double slit experiment.
If you yell to someone in another room that isn’t
in a direct path, they still hear you. Your sound
waves diffract around the doorways.
34/50
Wave front
AP Physics Rapid Learning Series - 21
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Diffraction Gratings
Diffraction also occurs for multiple small
openings.
d
λ
msinθ =
The same formula applies as with Young’s double
slit experiment.
35/50
In this case, d is the distance between in
individual gratings, or slits.
Diffraction Grating Problem
A 570 nm wavelength laser beam is aimed at a vinyl
record. The tiny grooves act like a diffraction
grating and produce a pattern.g g p p
The first maxima is 5.0 cm away from the
central spot. The distance from the record to
that central spot is 200 cm.
36/50
5.0
cm
200cm
What is the distance between the grooves
on the vinyl record?
AP Physics Rapid Learning Series - 21
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Diffraction Grating Solution
5.0
cm
First, find the angle between the central spot and
the first fringe.
θ adj
opp
tanθ =
cm
200cm
θ adj
200cm
5.0cm
tanθ = .025= 1.4(.025)tan-1
=
Now use this value in our maxima/bright
37/50
fringe formula.
d
λ
msinθ =
Diffraction Solution Continued
d
λ
msinθ =
sinθ
λ
md =
In this case, since we’re using the first bright
fringe, m=1.
The wavelength of 570 nm should be converted.
m570x10
1m
x570nm 9
9
−
=
38/50
)sin(1.4
mx10570
1d
-9
=
m570x10
nm1x10
x570nm 9
m2.3x10d 5−
=
AP Physics Rapid Learning Series - 21
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Polarization of
Light
Because light is a transverse wave, it can
vibrate in a variety of directions
39/50
vibrate in a variety of directions
compared to its direction of motion.
Unpolarized Light
In unpolarized light, the fluctuations in the electric
field occur in all directions. It’s random.
Direction of
wave
motion
Random and
40/50
Random and
varied electric
field directions
Most of the light we see is unpolarized.
AP Physics Rapid Learning Series - 21
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Polarized Light
Because light is a transverse wave, it can be
polarized. Longitudinal waves cannot be
polarized.
In polarized light, the electric field oscillates in only
one direction.
41/50
Direction of
wave
motion
Field varies in only
one direction
Polarizers
Unpolarized, random light can be made to be
polarized with the aid of a type of filter.
42/50
Unpolarized
light
Polarizing
filter
The polarizing filter acts like a grate or strain that
allows only one direction of motion.
Polarized
light
AP Physics Rapid Learning Series - 21
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Pairs of Polarizers
A pair of polarizers can be used to precisely
adjust the intensity of a light source.
U l i d 1 t P l i d
2nd P l i d
43/50
Unpolarized
light
1st
Polarizing
filter
Polarized
light
2nd
Polarizing
filter
Polarized
light with
reduced
intensity
The end result is polarized light of a particular
reduced intensity.
Intensity Adjusting Polarizers
With the pair of polarizing filters at a 0 degree angle
with each other, a maximum amount of light
emerges.
With the pair of polarizing filters at a 90 degree
angle with each other, a minimum amount of light
emerges, virtually 0 intensity.
By adjusting the angle between the direction of the
44/50
By adjusting the angle between the direction of the
two filters, the intensity of the light can be
controlled.
AP Physics Rapid Learning Series - 21
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Malus’ Law
Reduced average
Malus’ law describes how the angle between a pair
of polarizers affects the average intensity, or
strength, of the light.
θcosSS 2
o=
intensity of light,
W/m2
45/50
Original
average
intensity of
light, W/m2
Angle between
the two
polarizing filter
axes
Malus’ Law Example
If two polarizing filters were to be used to cut
the intensity of light to ½ of its original value,
how should they be arranged?
θcosSS 2
o=
We’ll be using Malus’ law, but we won’t be
finding the reduced intensity, that’s given in the
problem.
46/50
o
Instead we’ll be finding the angle that
achieves that reduced intensity.
AP Physics Rapid Learning Series - 21
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Malus’ Law Solution
θcosSS 2
o= θcos
S
S 2
o
=
o
cosθ
S
S
o
= θ
S
S
cos
o
1-
=
S 1/21
47/50
o
1-
S
S
cosθ = ==
1
1/2
cos 1-
45.5cos 1-
=
This should seem reasonable since it’s the angle that
is halfway between maximum and minimum
transmission.
The
electromagnetic,
EM spectrum
The
electromagnetic,
EM spectrum
Polarized light
oscillates in
Polarized light
oscillates in
Learning Summary
d
λ
msinθ =
maxima
In destructiveIn destructive
EM, spectrum
displays all types
of light.
EM, spectrum
displays all types
of light.
osc ates
only one
direction.
osc ates
only one
direction.
In constructiveIn constructive
maxima
d
λ
1/2)(msinθ +=
minima
48/50
In destructive
interference, a wave of
smaller amplitude is
created by adding
waves.
In destructive
interference, a wave of
smaller amplitude is
created by adding
waves.
In constructive
interference, a wave
of larger amplitude
is created by adding
waves.
In constructive
interference, a wave
of larger amplitude
is created by adding
waves.
AP Physics Rapid Learning Series - 21
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Congratulations
You have successfully completed
the tutorial
Physical Optics
Rapid Learning Center
Rapid Learning Center
Wh t’ N t
Chemistry :: Biology :: Physics :: Math
What’s Next …
Step 1: Concepts – Core Tutorial (Just Completed)
Step 2: Practice – Interactive Problem Drill
Step 3: Recap Super Review Cheat Sheet
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Physical Optics

  • 1. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 1 Rapid Learning Center Chemistry :: Biology :: Physics :: Math Rapid Learning Center Presents …Rapid Learning Center Presents … Teach Yourself AP Physics in 24 Hours 1/50 *AP is a registered trademark of the College Board, which does not endorse, nor is affiliated in any way with the Rapid Learning courses. Ph i l O tiPhysical Optics Physics Rapid Learning Series Rapid Learning Center www.RapidLearningCenter.com/ © Rapid Learning Inc. All rights reserved. Wayne Huang, Ph.D. Keith Duda, M.Ed. Peddi Prasad, Ph.D. Gary Zhou, Ph.D. Michelle Wedemeyer, Ph.D. Sarah Hedges, Ph.D.
  • 2. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 2 Learning Objectives Describe the electromagnetic spectr m and the nat re of By completing this tutorial, you can: spectrum and the nature of light. Understand constructive and destructive interference. Understand the concept of diffraction and solve related 3/50 problems. Describe the polarization of light. Concept Map Physics Studies Previous content New content Polarized Light Acts as a Travels at experiences Speed of light Transverse wave Electro- magnetic spectrum Wave May be 4/50 gspectrum Wave Interference Constructive Interference Destructive Interference In vacuum 3x108m/s
  • 3. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 3 TheThe Electromagnetic Spectrum 5/50 Electromagnetic Spectrum The electromagnetic spectrum can be considered a catalog or map of all the various frequencies of light. I f d Ult i l tR di GInfrared UltravioletRadio waves Gamma rays 6/50 Visible lightMicro waves X rays Obviously our eyes perceive only a small amount of the EM spectrum, visible light.
  • 4. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 4 EM Spectrum Observations Note the highest frequencies/lowest wavelengths are to the right. 7/50 Also note the lowest frequencies/highest wavelengths are to the left. Electromagnetic Waves An electromagnetic wave is an oscillating combination of a magnetic and an electric field. It can be visualized as two perpendicular waves (electric and magnetic). 8/50 This view shows the light wave coming right at you.
  • 5. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 5 Speed of Light In a vacuum, all electromagnetic waves have a velocity of 300,000,000 m/s! ( 3x108m/s) Later we will see that this speed can vary That’s 186,000 miles per second! 9/50 depending on the medium. First Calculation of Light Speed The approximate speed of light was first calculated in 1675 by Danish astronomer Olaus Roemer. He had no computers, calculators, or other sophisticated instruments... 10/50
  • 6. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 6 Observations He used careful telescopic observations of the motions of Jupiter’s moons. 11/50 Jupiter Moons revolving around planet The Jupiter’s moon could be observed from either side of the Earth orbit around the Sun Orbital Difference Sun. This yielded a substantial difference in distance for the light to travel. 12/50 Roemer measured a 16.5 minute time difference.
  • 7. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 7 Calculation of Light Speed At the time, it was known that the diameter of Earth’s orbit was 3 x 1011m. Roemer used this information, and his time difference, to calculate the speed of light: t d v = 990s m3x10 v 11 = 16.5 minutes t d 13/50 990s m/s3.03x10v 8 = This is surprisingly accurate for the time period. converted into seconds. Michelson’s Measurement Fixed flat mirror far away light 14/50 American physicist Albert Michelson used a rotating mirror with fixed mirror on a distant mountain. The speed of the mirror was used to “time” the trip that light took to obtain a more accurate value.
  • 8. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 8 Constructive and Destructive Interference Waves often superimpose, or interfere with each other when they overlap 15/50 with each other when they overlap. Principle of Superposition When two or more waves occupy the same region of space simultaneously, the resulting wave disturbance is the sum of separate waves. Wave #1 Wave #2 16/50 Resulting wave due to superposition.
  • 9. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 9 Constructive Interference When waves overlap or superimpose, they may create a larger amplitude wave as a result. wave 1 + wave 2 Notice how the wave crests and troughs line up perfectly. 17/50 equals Greater amplitude wave. Destructive Interference When waves overlap or superimpose, they may create a smaller amplitude wave as a result. Notice how wave 1 + wave 2 Notice how the wave crests and troughs are perfectly out of phase. 18/50 equals A zero amplitude wave.
  • 10. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 10 Thin Film Interference Soap bubbles and thin films of gasoline or oil often produce pretty colored patterns. This results from some light penetrating the film, 19/50 g p g , then reflecting backwards. This light interferes with light reflecting off the surface and creates certain colors depending on the thickness of the film. Coherent Light Light waves that are all in phase, or in step with each other, are called coherent. This basically means that the waves don’t shift with 20/50 y respect to each other as time passes.
  • 11. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 11 Monochromatic Light Light waves that have all the same frequency/ wavelength/color are called monochromatic. Laser light is both monochromatic and coherent. 21/50 Diffraction Diffraction is the bending of waves around obstacles corners or openings 22/50 around obstacles, corners, or openings.
  • 12. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 12 Young’s Double Slit Experiment In 1801 Thomas Young was the first person to measure the wavelength of light. He sent light originating from one location incidentg g g upon a pair of slits in a barrier and observed. Viewing ??? 23/50 Top view screen Coherent light source ??? Particle Result If light had behaved like a particle, two spots of light on the screen would have been observed. Viewing screen Coherent 24/50 However, in this experiment, this did not happen. In this case, light behaves like a wave! Top view light source
  • 13. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 13 Wave Result Instead, alternating spots of brightness and darkness occur. This is quite strange! Coherent 25/50 Top view Viewing screen light source An explanation of this depends on the wave behavior of light. Constructive Interference Spot A set of light waves each goes through an open slit. 26/50 Viewing screen When there are bright spots, the two waves arrive in phase, and constructively interfere, giving a bright central spot.
  • 14. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 14 Different Path Lengths Even if the two sets of wave have different distances to travel, they can still constructively interfere to produce a bright spot, or maxima. 1st bright fringe Central spot fringe 27/50 In these spots, the path difference between the two waves is a whole value of wavelength, λ. 1 λ extra Different Path Lengths Again For area of darkness, or minima, destructive interference occurs. 1st bright fringe Central spot g 1st dark area 28/50 In these spots, the path difference between the two waves is a half value of wavelength, λ/2. 1/2 λ extra
  • 15. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 15 Relevant Variables Diagramed below are the relevant quantities that will be used in problems. 1st bright fringe Distance between slits, d Length to screen Central spot θ Distance from center 29/50 screen spot Bright Spot Formula The following formula describes the bright fringes created by constructive interference. d λ msinθ = Wavelength, m Integer m=0,1,2,3… 30/50 d Angle between bright spot and central spot Distance between slits, m
  • 16. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 16 Dark Spot Formula The following formula describes the dark areas created by destructive interference. λ 1/2)(msinθ += Wavelength, m Integer m=0,1,2,3… 31/50 d )( Angle between dark spot and central spot Distance between slits, m Double Slit Example Problem The second dark area in an interference pattern is noticed to be 2° away from the central bright spot. The slits are 5x10-5 m apart. What is the wavelength of the coherent light used? d λ 1/2)(msinθ += Use our formula for destructive interference fringes. 32/50 d In this case, since the second dark area is being used, m = 2.
  • 17. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 17 Double Slit Solution d λ 1/2)(msinθ += λ 1/2)(m sinθd = + 1/2)(2 )sin(2m5x10 λ -5 + = Calculate carefully. Be sure to use the correct order of 33/50 m7x10λ 7− = correct order of operations. Use degrees for angular units. Diffraction Diffraction also occurs in places other than a double slit experiment. If you yell to someone in another room that isn’t in a direct path, they still hear you. Your sound waves diffract around the doorways. 34/50 Wave front
  • 18. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 18 Diffraction Gratings Diffraction also occurs for multiple small openings. d λ msinθ = The same formula applies as with Young’s double slit experiment. 35/50 In this case, d is the distance between in individual gratings, or slits. Diffraction Grating Problem A 570 nm wavelength laser beam is aimed at a vinyl record. The tiny grooves act like a diffraction grating and produce a pattern.g g p p The first maxima is 5.0 cm away from the central spot. The distance from the record to that central spot is 200 cm. 36/50 5.0 cm 200cm What is the distance between the grooves on the vinyl record?
  • 19. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 19 Diffraction Grating Solution 5.0 cm First, find the angle between the central spot and the first fringe. θ adj opp tanθ = cm 200cm θ adj 200cm 5.0cm tanθ = .025= 1.4(.025)tan-1 = Now use this value in our maxima/bright 37/50 fringe formula. d λ msinθ = Diffraction Solution Continued d λ msinθ = sinθ λ md = In this case, since we’re using the first bright fringe, m=1. The wavelength of 570 nm should be converted. m570x10 1m x570nm 9 9 − = 38/50 )sin(1.4 mx10570 1d -9 = m570x10 nm1x10 x570nm 9 m2.3x10d 5− =
  • 20. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 20 Polarization of Light Because light is a transverse wave, it can vibrate in a variety of directions 39/50 vibrate in a variety of directions compared to its direction of motion. Unpolarized Light In unpolarized light, the fluctuations in the electric field occur in all directions. It’s random. Direction of wave motion Random and 40/50 Random and varied electric field directions Most of the light we see is unpolarized.
  • 21. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 21 Polarized Light Because light is a transverse wave, it can be polarized. Longitudinal waves cannot be polarized. In polarized light, the electric field oscillates in only one direction. 41/50 Direction of wave motion Field varies in only one direction Polarizers Unpolarized, random light can be made to be polarized with the aid of a type of filter. 42/50 Unpolarized light Polarizing filter The polarizing filter acts like a grate or strain that allows only one direction of motion. Polarized light
  • 22. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 22 Pairs of Polarizers A pair of polarizers can be used to precisely adjust the intensity of a light source. U l i d 1 t P l i d 2nd P l i d 43/50 Unpolarized light 1st Polarizing filter Polarized light 2nd Polarizing filter Polarized light with reduced intensity The end result is polarized light of a particular reduced intensity. Intensity Adjusting Polarizers With the pair of polarizing filters at a 0 degree angle with each other, a maximum amount of light emerges. With the pair of polarizing filters at a 90 degree angle with each other, a minimum amount of light emerges, virtually 0 intensity. By adjusting the angle between the direction of the 44/50 By adjusting the angle between the direction of the two filters, the intensity of the light can be controlled.
  • 23. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 23 Malus’ Law Reduced average Malus’ law describes how the angle between a pair of polarizers affects the average intensity, or strength, of the light. θcosSS 2 o= intensity of light, W/m2 45/50 Original average intensity of light, W/m2 Angle between the two polarizing filter axes Malus’ Law Example If two polarizing filters were to be used to cut the intensity of light to ½ of its original value, how should they be arranged? θcosSS 2 o= We’ll be using Malus’ law, but we won’t be finding the reduced intensity, that’s given in the problem. 46/50 o Instead we’ll be finding the angle that achieves that reduced intensity.
  • 24. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 24 Malus’ Law Solution θcosSS 2 o= θcos S S 2 o = o cosθ S S o = θ S S cos o 1- = S 1/21 47/50 o 1- S S cosθ = == 1 1/2 cos 1- 45.5cos 1- = This should seem reasonable since it’s the angle that is halfway between maximum and minimum transmission. The electromagnetic, EM spectrum The electromagnetic, EM spectrum Polarized light oscillates in Polarized light oscillates in Learning Summary d λ msinθ = maxima In destructiveIn destructive EM, spectrum displays all types of light. EM, spectrum displays all types of light. osc ates only one direction. osc ates only one direction. In constructiveIn constructive maxima d λ 1/2)(msinθ += minima 48/50 In destructive interference, a wave of smaller amplitude is created by adding waves. In destructive interference, a wave of smaller amplitude is created by adding waves. In constructive interference, a wave of larger amplitude is created by adding waves. In constructive interference, a wave of larger amplitude is created by adding waves.
  • 25. AP Physics Rapid Learning Series - 21 © Rapid Learning Inc. All rights reserved. - http://www.RapidLearningCenter.com 25 Congratulations You have successfully completed the tutorial Physical Optics Rapid Learning Center Rapid Learning Center Wh t’ N t Chemistry :: Biology :: Physics :: Math What’s Next … Step 1: Concepts – Core Tutorial (Just Completed) Step 2: Practice – Interactive Problem Drill Step 3: Recap Super Review Cheat Sheet 50/50 Step 3: Recap – Super Review Cheat Sheet Go for it! http://www.RapidLearningCenter.com