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G.H.RAISONI COLLEGE OF ENGINEERING, NAGPUR
Department of First Year Engineering
Second Semester B.E: Summer 2016
Presentation on
Topic of PPT:- Projection Of Planar Surface
By
Subject: Engineering Graphics
Q NO.1 line AB 200 mm long has its end A 75mm above HP and 50 mm in front of
VP. Endpoint B is in 1st
quadrant. The line isparallel to HP and makes an inclination
of 40’ to VP. Draw the projection of straight line AB . Obtain HT and VT.
Solution:-
stage-1
1. draw XY line ,which represents FV region and TV of VP in TV region.
2. locate FV a’75mm above XY line as point A is 75 mm above HP.
3. locate TV a 50mm below Xyline as point A is 50mm in front of VP.
4. draw a line of 200 mm length parallel to HP and VP . Both the views show true
length.
stage-2
5.rotate the TL in TV to make an inclination of 40’to VP.
6. project B to obtain the FV of B as a’b’ represents an apparent length(AL).
Stage-3
7.extend the TV of line AB to meet XY line .
8.note the intersection point of extended line and XY line as v as v lies on xy line.
9.draw the projector line passing through point v.
10.extend the FV of line AB (a’b’) to meet the projector line passing through v.
11.note the intersection point of extended line and projector line as VT (or v’).
12.there is no HT as the line is parallel to HP.
Ques 2. A pentagonal plate of negligible thickness and having edge length 100 mm is resting on one
0f its sides on VP . The plate is inclined 40° to VP nd the resting sides makes an inclination of 50° to
HP. Draw projections of the plate.
Solution:
1.In the FV region , draw a pentagon of 100 mm side ,with line joining one corner to the center o og
the pentagon parallel to the xy line. Name the cornerr as a’,b’,c’,d’ and e’.
2.Project all the five points on the xy line as the plate in the stage 1 is lying on VP and obtain a line
view a,b-c,e-d of the plate coinciding with the xy line.
3.In the stage 2, copy the line view of stage 1 and place it on the xy line . Rotate the line view about
the corner point d through a given inclination of 40°.
4.Project all the four points from the TV of stage 2 to the FV of the stage2 . Project all the four points
from the FV of stage 1 to the FV of stage 2.
5.Join the respective intersecting points of the projectors lines to obtain the the final projection
points a’,b’,c’,d’ and e,.we get a reduced shape of the pentagon.
6.Copy the reduced shape of the pentagonal plate from FV region of stage 2 and place it in the FV
region of stage 2.
7.Rotate the copied view about b’ so that the resting side a’b’ makes 50° to HP.
8.Project all the five points from the FV of the stage 3 to the TV of stage 3. project all the five points
from the TV of stage 2 to the TV of stage 3 .
9.Join the respective intersecting points of the projector lines to obtain the final projection points
a,b,c,d and e and obtain an irregular pentagonal shape.
Projection of planar surfacE
Projection of planar surfacE

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Projection of planar surfacE

  • 1. G.H.RAISONI COLLEGE OF ENGINEERING, NAGPUR Department of First Year Engineering Second Semester B.E: Summer 2016 Presentation on Topic of PPT:- Projection Of Planar Surface By Subject: Engineering Graphics
  • 2. Q NO.1 line AB 200 mm long has its end A 75mm above HP and 50 mm in front of VP. Endpoint B is in 1st quadrant. The line isparallel to HP and makes an inclination of 40’ to VP. Draw the projection of straight line AB . Obtain HT and VT. Solution:- stage-1 1. draw XY line ,which represents FV region and TV of VP in TV region. 2. locate FV a’75mm above XY line as point A is 75 mm above HP. 3. locate TV a 50mm below Xyline as point A is 50mm in front of VP. 4. draw a line of 200 mm length parallel to HP and VP . Both the views show true length. stage-2 5.rotate the TL in TV to make an inclination of 40’to VP. 6. project B to obtain the FV of B as a’b’ represents an apparent length(AL). Stage-3 7.extend the TV of line AB to meet XY line . 8.note the intersection point of extended line and XY line as v as v lies on xy line. 9.draw the projector line passing through point v. 10.extend the FV of line AB (a’b’) to meet the projector line passing through v. 11.note the intersection point of extended line and projector line as VT (or v’). 12.there is no HT as the line is parallel to HP.
  • 3.
  • 4. Ques 2. A pentagonal plate of negligible thickness and having edge length 100 mm is resting on one 0f its sides on VP . The plate is inclined 40° to VP nd the resting sides makes an inclination of 50° to HP. Draw projections of the plate. Solution: 1.In the FV region , draw a pentagon of 100 mm side ,with line joining one corner to the center o og the pentagon parallel to the xy line. Name the cornerr as a’,b’,c’,d’ and e’. 2.Project all the five points on the xy line as the plate in the stage 1 is lying on VP and obtain a line view a,b-c,e-d of the plate coinciding with the xy line. 3.In the stage 2, copy the line view of stage 1 and place it on the xy line . Rotate the line view about the corner point d through a given inclination of 40°. 4.Project all the four points from the TV of stage 2 to the FV of the stage2 . Project all the four points from the FV of stage 1 to the FV of stage 2. 5.Join the respective intersecting points of the projectors lines to obtain the the final projection points a’,b’,c’,d’ and e,.we get a reduced shape of the pentagon. 6.Copy the reduced shape of the pentagonal plate from FV region of stage 2 and place it in the FV region of stage 2. 7.Rotate the copied view about b’ so that the resting side a’b’ makes 50° to HP. 8.Project all the five points from the FV of the stage 3 to the TV of stage 3. project all the five points from the TV of stage 2 to the TV of stage 3 . 9.Join the respective intersecting points of the projector lines to obtain the final projection points a,b,c,d and e and obtain an irregular pentagonal shape.