Knitting calculation for garments math

1. Find out the production per day of 24hrs in kg at 85% efficiency when machine gauge = 24, machine diameter
= 30″ yarn count = 30Ne; RPM = 30; stitch length = 2.60 mm. Number of feeder = 54
Solution:
Here data given, Efficiency = 85%
Machine diameter = 30″
M/c gauge = 24 needles per inch
Yarn count = 30Ne
M/c rpm = 30
Stitch length = 2.60 mm
Number of feeder = 54
Machine circumference = π × d
Number of needle = π × d × G
Length of yarn in a course = π × d× G× Stitch length
Length of yarn used to produce courses in a minute = π × d× G× Stitch length × m/c rpm
= (π × 30× 24 × 2.6 × 30) mm/minute
= 176342.4 mm/minute
= 176.342 m/minute
= 176.342 × 1.09 yards /minute
= 192.21 yard/minute
=
30x840
192.21
pounds/minute
= 0.0076 pounds/minute
= 0.0076 × 60 × 24 pounds/day
= 10.944 pounds/day
=
2.2
10.944
kg /day
= 4.97 kg /day
Now with 54 feeders, the production will be, (4.97 × 54) = 268.38 kg/day
Production/m/c/day at 85% efficiency = 268.38 × 0.85 kg /day
= 228.123 kg /day
Alternate solution:
Here data given, Efficiency = 85% Machine diameter = 30″
M/c gauge = 24 needles per inch Yarn count = 30Ne
M/c rpm = 30 Stitch length = 2.60 mm
Production in Kg/day =
2.2(Ne)xCountx840x1000
Efficiency×feederofNumber×1.09×24×60×rpm×(mm)lengthStitch×G×(inch)d×π
=
2.2x30x840x1000
0.85×54×1.09×24×60×30×2.6×24×30×π
= 228.123 kg /day

2. For Practice…………….
1. Find out the production per hour in pounds at 70% efficiency when machine gauge = 32, machine diameter
= 30″ yarn count = 40 Ne; RPM = 24; stitch length = 2.20 mm. [Number of feeder = 90]
2. What will be the production per shift (8 hrs) in kg at 95% efficiency when machine gauge = 24, machine
diameter = 30″ yarn count = 30 Ne; RPM = 30; stitch length = 2.45 mm. [Number of feeder = 50]
3. Find out the stitch length of a fabric if that is produced from a machine 5 kg per day at 80% efficiency. And
machine gauge = 24, machine diameter = 28″ yarn count = 27Ne; and machine RPM = 26. [Number of feeder =
60]
4. In a knitting factory, Fabric will be produced tomorrow from 28 Ne Yarn. It has 50 machines, all of them
have 24 gauge, 30″ diameter, 60 feeders and stitch length should be = 3.00 mm. But 25 machines have an rpm
of 24, and other 25 machines have an rpm of 28. What will be the production of that factory tomorrow?