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Part-9
The Gibbs Free Energy
and equilibria
• “Gibbs Free Energy” is energy that is still useful.
• A chemical reaction will occur if the Gibbs would decrease.
G = H - TS
Gibbs free energy is a measure of chemical energyGibbs free energy is a measure of chemical energy
All chemical systems tend naturally toward states of minimum
Gibbs free energy
G = Gibbs Free Energy
H = Enthalpy (heat content)
T = Temperature in Kelvins
S = Entropy (can think of as
randomness)
Gibbs free energy also known as the free enthalpy
Is a thermodynamic potential that measures the maximum or reversible work
that may be performed by a system at a constant temperature and pressure
(Isothermal, Isobaric)
Spontaneity and Gibbs Free Energy
• Gibbs Free energy is a measure of the spontaneity of a process
• ΔG is the free energy change for a reaction under standard state
conditions
• At constant temperature and pressure: ΔG = ΔH – TΔS
– an increase in ΔS leads to a decrease in ΔG
–– ifif ΔΔG < 0, the forward reaction is spontaneousG < 0, the forward reaction is spontaneous
–– ifif ΔΔG > 0, the forward reaction is nonspontaneousG > 0, the forward reaction is nonspontaneous
–– ifif ΔΔG = 0, the process is in equilibriumG = 0, the process is in equilibrium
• The Gibbs Free Energy is generally agreed to be the
“weapon of choice” for describing (a) chemical reactions
and (b) equilibria between phases. It is defined as:
• G = H – TS = U + PV – TS (1)
Where H = Enthalpy
• U = Total internal energy
• T = [Absolute] Temperature
• S = Entropy
• Obviously dG = dU + PdV +VdP – TdS – SdT
The Gibbs Free Energy and equilibria
• Remember that thermodynamic variables come in pairs
One is “intrinsic” (does not depend on system size)
The other is “extrinsic” (depends on system size)
• Examples: P and V, T and S…
• Also G and n, the number of moles of stuff in the system.
• Hence G is the appropriate variable when material is moving between
phases
Note:
From the First Law of Thermodynamics
• dU = TdS – PdV
since dS = dQ/T and the mechanical work done on a system
when it expands is –PdV.
• Substituting into
• dG = dU + PdV +VdP – TdS – SdT
• Leaves: dG = -SdT + VdP
Clapeyron’s Equation
Closed System
• Closed system contains pure substance
– vapor
– condensed phase
• Phases co-exist in equilibrium.
Write the Free Energy Equation twice
• Once for each phase
• dGc = -ScdT + VcdP c refers to the condensed phase
• dGv = -SvdT + VvdP v refers to the vapor phase
Definition of chemical equilibrium between two phases
• Free energy is the same in both phases Gc = Gv
• Changes in free energy when some independent variable is
changed must be the same if they are to remain in equilibrium
dGc = dGv
-ScdT + VcdP = -SvdT + VvdP
(Sv - Sc )dT = (Vv- Vc)dP
• (Sv - Sc ) is the entropy change that takes place when material moves from
the condensed phase to the vapor
•ΔS = ΔQ/T where ΔQ is the amount of heat required per mole of material
moved between the phases
•ΔQ is just the heat of vaporization!
• dP/dT = (Sv – Sc)/(Vv – Vc) = ΔHv/(TΔV)
This is the Clapeyron equation
• It relates the change in pressure of a vapor to the temperature
in a closed, mono-component system to the heat of
vaporization, system temperature and molar volume change of
the material on vaporization.
dP S
or
dT V
∆
=
∆
From the Clapeyron’s Equation we can calculate phase
diagrams.
H=U+PV=Q
Creating of an Ideal Gas
• For lack of a better model, we treat most vapors as ideal gases, whose
molar volume is given by:
• V/n = RT/P
• Alternatively, equation of state is needed
• Molar volume of gas is typically factor of 500 larger than condensed phase
• Hence Vc is negligible in comparison
Substituting and Integrating
dP = (ΔHv/Vv)dT/T = (PΔHv/RT)dT/T
dP/P = ΔHv/R)dT/T2
ln(P(T)/ P0) = -(ΔHv/R)(1/T – 1/T0)
P(T) = P0 exp(-ΔHv/R(1/T – 1/T0))
Integrating
• The vapor pressure in equilibrium with a condensed phase
increases exponentially (sort of: exp(-1/T) isn’t exactly an
exponential!) with temperature from zero up to the critical
temperature.
• Deviations from linearity on the log-log plot
– Temperature dependence of the heat of vaporization
– exp (-1/T) isn’t really linear in the exponent.
Heat of Vaporization from CRC Data
Log10p(Torr) = -0.2185*A/T + B
Vapor Pressure of Water
Temperature (C)
-20 0 20 40 60 80 100 120
VaporPressure(Torr)
0.1
1
10
100
1000
10000
"Normal boiling point"
1. Determine the vapor pressure at 77 K for
a. Water
b. Carbon monoxide
2. What is the boiling point of water in a vacuum system at 10-6
Torr?
HW
3. In the chemical equation G = H - TS, the term G stands for
A) entropy
B) the reactants
C) enthalpy
D) free energy
E) the products

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Thermodynamics, part 8

  • 1. Part-9 The Gibbs Free Energy and equilibria
  • 2. • “Gibbs Free Energy” is energy that is still useful. • A chemical reaction will occur if the Gibbs would decrease. G = H - TS Gibbs free energy is a measure of chemical energyGibbs free energy is a measure of chemical energy All chemical systems tend naturally toward states of minimum Gibbs free energy G = Gibbs Free Energy H = Enthalpy (heat content) T = Temperature in Kelvins S = Entropy (can think of as randomness) Gibbs free energy also known as the free enthalpy Is a thermodynamic potential that measures the maximum or reversible work that may be performed by a system at a constant temperature and pressure (Isothermal, Isobaric)
  • 3. Spontaneity and Gibbs Free Energy • Gibbs Free energy is a measure of the spontaneity of a process • ΔG is the free energy change for a reaction under standard state conditions • At constant temperature and pressure: ΔG = ΔH – TΔS – an increase in ΔS leads to a decrease in ΔG –– ifif ΔΔG < 0, the forward reaction is spontaneousG < 0, the forward reaction is spontaneous –– ifif ΔΔG > 0, the forward reaction is nonspontaneousG > 0, the forward reaction is nonspontaneous –– ifif ΔΔG = 0, the process is in equilibriumG = 0, the process is in equilibrium
  • 4. • The Gibbs Free Energy is generally agreed to be the “weapon of choice” for describing (a) chemical reactions and (b) equilibria between phases. It is defined as: • G = H – TS = U + PV – TS (1) Where H = Enthalpy • U = Total internal energy • T = [Absolute] Temperature • S = Entropy • Obviously dG = dU + PdV +VdP – TdS – SdT The Gibbs Free Energy and equilibria
  • 5. • Remember that thermodynamic variables come in pairs One is “intrinsic” (does not depend on system size) The other is “extrinsic” (depends on system size) • Examples: P and V, T and S… • Also G and n, the number of moles of stuff in the system. • Hence G is the appropriate variable when material is moving between phases Note:
  • 6. From the First Law of Thermodynamics • dU = TdS – PdV since dS = dQ/T and the mechanical work done on a system when it expands is –PdV. • Substituting into • dG = dU + PdV +VdP – TdS – SdT • Leaves: dG = -SdT + VdP Clapeyron’s Equation
  • 7. Closed System • Closed system contains pure substance – vapor – condensed phase • Phases co-exist in equilibrium. Write the Free Energy Equation twice • Once for each phase • dGc = -ScdT + VcdP c refers to the condensed phase • dGv = -SvdT + VvdP v refers to the vapor phase
  • 8. Definition of chemical equilibrium between two phases • Free energy is the same in both phases Gc = Gv • Changes in free energy when some independent variable is changed must be the same if they are to remain in equilibrium dGc = dGv -ScdT + VcdP = -SvdT + VvdP (Sv - Sc )dT = (Vv- Vc)dP • (Sv - Sc ) is the entropy change that takes place when material moves from the condensed phase to the vapor •ΔS = ΔQ/T where ΔQ is the amount of heat required per mole of material moved between the phases •ΔQ is just the heat of vaporization!
  • 9. • dP/dT = (Sv – Sc)/(Vv – Vc) = ΔHv/(TΔV) This is the Clapeyron equation • It relates the change in pressure of a vapor to the temperature in a closed, mono-component system to the heat of vaporization, system temperature and molar volume change of the material on vaporization. dP S or dT V ∆ = ∆ From the Clapeyron’s Equation we can calculate phase diagrams. H=U+PV=Q
  • 10. Creating of an Ideal Gas • For lack of a better model, we treat most vapors as ideal gases, whose molar volume is given by: • V/n = RT/P • Alternatively, equation of state is needed • Molar volume of gas is typically factor of 500 larger than condensed phase • Hence Vc is negligible in comparison Substituting and Integrating dP = (ΔHv/Vv)dT/T = (PΔHv/RT)dT/T dP/P = ΔHv/R)dT/T2 ln(P(T)/ P0) = -(ΔHv/R)(1/T – 1/T0) P(T) = P0 exp(-ΔHv/R(1/T – 1/T0)) Integrating
  • 11. • The vapor pressure in equilibrium with a condensed phase increases exponentially (sort of: exp(-1/T) isn’t exactly an exponential!) with temperature from zero up to the critical temperature. • Deviations from linearity on the log-log plot – Temperature dependence of the heat of vaporization – exp (-1/T) isn’t really linear in the exponent.
  • 12. Heat of Vaporization from CRC Data Log10p(Torr) = -0.2185*A/T + B Vapor Pressure of Water Temperature (C) -20 0 20 40 60 80 100 120 VaporPressure(Torr) 0.1 1 10 100 1000 10000 "Normal boiling point"
  • 13. 1. Determine the vapor pressure at 77 K for a. Water b. Carbon monoxide 2. What is the boiling point of water in a vacuum system at 10-6 Torr? HW 3. In the chemical equation G = H - TS, the term G stands for A) entropy B) the reactants C) enthalpy D) free energy E) the products