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Systems of Linear
Equations
Solving Systems of Linear Equation
Using Elimination Method
Jessebel G. Bautista
Antonio J. Villegas Voc’l High School
My
Profile
Objectives:
• recall inverse property of addition
• recall addition property of equality
• recall multiplication property of
equality
• recall substitution method
• use elimination method
• find the solution of the systems of
linear equations
Steps in eliminating of the unknowns:
1. Compare the coefficients of
the variable you wish to
eliminate. If they have the same
coefficients, then eliminate
them by either adding or
subtracting.
2. If the coefficients of the
variable to be eliminated are
different. Multiply one equation
or both equations with an
appropriate number that would
make the coefficients the same.
Then eliminate the variable
either by adding or subtracting.
3. Solve the resulting linear
equation in one unknown.
4. Substitute the value obtained
into any of the original
equations to solve for the other
variable.
5. Check whether or not the
values satisfy both equations.
Examples1:
Solution:
Step 1: Add the two equations to
eliminate y. (The coefficients of y
are opposites.)Then solve for x.
x + 2y = 8
+ 3x – 2y = 8
4x = 16
x = 4
Solve the system using
the elimination method.
x+ 2y =8 Equation 1
3x – 2y = 8 Equation 2
Examples1:
Solution:
Step 2: Substitute 4 for x in either
of the equations, then solve for y.
Equation 1: x + 2y = 8
4 + 2y = 8
2y = 4
y = 2
The solution is (4, 2)
Solve the system using
the elimination method.
x+ 2y =8 Equation 1
3x – 2y = 8 Equation 2
Examples 2:
Solution:
Step 1. Multiply eq.1 by 3 and equation 2 by -2 to make the coefficient of
x opposites.
(2x + 3y = 15) 6x + 9y = 45
(3x + 2y = 5) -6x – 4y = -10
Solve the system using the elimination method.
2x + 3y = 15 Equation 1
3x + 2y = 5 Equation 2
Step 2. Add the two equations to eliminate x, then solve for y.
6x + 9y = 45
+ -6x – 4y = -10
5y = 35
y = 7
Examples 2:
Solution:
Step 3. Substitute 7 for y in either of the equations 1 or 2, then solve for x.
Equation 1: 2x + 3y = 15
2x + 3(7) = 15
2x + 21 = 15
2x = 15 – 21
2x = -6
x = -3
The solution is ( -3, 7 )
Solve the system using the elimination method.
2x + 3y = 15 Equation 1
3x + 2y = 5 Equation 2
To Do…
Solve the following systems of linear equations by
eliminations:
1. x + y = 14 and x – y = 2
2. 2m – n = 3 and m + n = 9
3. x + y = 2 and 2x – y = 10
Thank you!
Learning Resources:
Grade 8 Math Time
k-to-12-grade-8-math-learner-module

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elimination

  • 1. Systems of Linear Equations Solving Systems of Linear Equation Using Elimination Method
  • 2. Jessebel G. Bautista Antonio J. Villegas Voc’l High School My Profile
  • 3. Objectives: • recall inverse property of addition • recall addition property of equality • recall multiplication property of equality • recall substitution method • use elimination method • find the solution of the systems of linear equations
  • 4. Steps in eliminating of the unknowns: 1. Compare the coefficients of the variable you wish to eliminate. If they have the same coefficients, then eliminate them by either adding or subtracting. 2. If the coefficients of the variable to be eliminated are different. Multiply one equation or both equations with an appropriate number that would make the coefficients the same. Then eliminate the variable either by adding or subtracting. 3. Solve the resulting linear equation in one unknown. 4. Substitute the value obtained into any of the original equations to solve for the other variable. 5. Check whether or not the values satisfy both equations.
  • 5. Examples1: Solution: Step 1: Add the two equations to eliminate y. (The coefficients of y are opposites.)Then solve for x. x + 2y = 8 + 3x – 2y = 8 4x = 16 x = 4 Solve the system using the elimination method. x+ 2y =8 Equation 1 3x – 2y = 8 Equation 2
  • 6. Examples1: Solution: Step 2: Substitute 4 for x in either of the equations, then solve for y. Equation 1: x + 2y = 8 4 + 2y = 8 2y = 4 y = 2 The solution is (4, 2) Solve the system using the elimination method. x+ 2y =8 Equation 1 3x – 2y = 8 Equation 2
  • 7. Examples 2: Solution: Step 1. Multiply eq.1 by 3 and equation 2 by -2 to make the coefficient of x opposites. (2x + 3y = 15) 6x + 9y = 45 (3x + 2y = 5) -6x – 4y = -10 Solve the system using the elimination method. 2x + 3y = 15 Equation 1 3x + 2y = 5 Equation 2 Step 2. Add the two equations to eliminate x, then solve for y. 6x + 9y = 45 + -6x – 4y = -10 5y = 35 y = 7
  • 8. Examples 2: Solution: Step 3. Substitute 7 for y in either of the equations 1 or 2, then solve for x. Equation 1: 2x + 3y = 15 2x + 3(7) = 15 2x + 21 = 15 2x = 15 – 21 2x = -6 x = -3 The solution is ( -3, 7 ) Solve the system using the elimination method. 2x + 3y = 15 Equation 1 3x + 2y = 5 Equation 2
  • 9. To Do… Solve the following systems of linear equations by eliminations: 1. x + y = 14 and x – y = 2 2. 2m – n = 3 and m + n = 9 3. x + y = 2 and 2x – y = 10
  • 11. Learning Resources: Grade 8 Math Time k-to-12-grade-8-math-learner-module