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Invention Journal of Research Technology in Engineering & Management (IJRTEM)
ISSN: 2455-3689
www.ijrtem.com Volume 2 Issue 3 ǁ March. 2018 ǁ PP 17-29
|Volume 2| Issue 3 | www.ijrtem.com | 17 |
Solvability of Fractionlq -Difference Equations of
Order 32  Involving The P-Laplacian Operator
Yawen Yan Chengmin Hou
(Department of mathematics,Yanbian University,Yanji 133002,P.R.China)
ABSTRACT : In this paper, we study the existence of solutions for non-linear fractional q-difference
equations of order 32  involving the p-Laplacian operator with various boundary value conditions. By
using the Banach contraction mapping principle, we prove that, under certain conditions, the suggested
non-linear fractional boundary value problem involving the p-Laplacian operator has a unique solution. Finally,
we illustrate our results with some examples.
KEYWORDS: p-Laplacian operators; Caputo fractional derivative; Caputo fractional boundary value
problem
I. INTRODUCTION
In recent years, the topic of q-calculus has attracted the attention of several researchers and a variety of new
results can be found in the papers [2-10] and the references cited therein. In 2010, Ferreira [1] considered the
existence of nontrivial solutions to the fractional q-difference equation
.0)1()0(
,10)),(,()(0,


xx
ttxtftxDq

In [15], Aktuğlu and Özarslan dealt with the following Caputo q-fractional boundary value problem involving
the p-Laplacian operator:
,)1()0(),1()0(,1,,3,2,0)0(
,10)),(,()))(((
10 xDaxDxaxnkxD
ttxtftxDD
qq
k
q
q
c
pq





where 0, 10 aa , 1 , and ),]1,0([ RRCf  . Under some conditions, the authors obtained the
existence and uniqueness of the solution for the above boundary value problem by using the Banach contraction
mapping principle.
In this paper, we focus on the solvability of the following non-linear fractional differential equations of
order  3,2 involving the p-Laplacian operator with boundary conditions:












),1()0(
),1()0(
),1()0(
,0)0(
)),(,()))(((
2
2
2
1
0
xDaxD
xDaxD
xax
xD
txtftxDD
qq
qq
q
c
q
c
pq



Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 18 |
where ),]1,0([ RRCf  and ),,]1,0([)( 2
RRCtx  ,)(
2
sss
p
p

 ,1p vp  1
, 1
11

vp
,

q
c
D is the fractional q-derivative of the Caputo type,
2
, qq DD is the fractional q-derivative
and 10 a , 11 a ,
2
1
2


v
a , ]1,0[t ,

D ,

D is the conformable fractional derivative.
2 Preliminaries on fractional q-calculus
In this section, we present basic definitions and results that will be needed in the rest of the paper. More
detailed information about the theory of fractional q-calculus can be found in [6,7,8].
Let )1,0(q and define
 
q
q
a
a
q



1
1
: , Ra .
The q-analogue of the power function
 n
ba )(  with ],2,1,0[:0  Nn is
 
,1:)( 0
 ba  
 



1
0
:)(
n
k
kn
bqaba , Rba , .
More generally, if R , then
 
 






0
)(
/1
/1
:)(
n
n
n
qab
qab
aba 

, 0a .
In particular, if 0b then

aa )(
. We also use the notation

00 )(
 for 0 . The q-gamma function
is defined by
1
)1(
)1(
)1(
:)( 



 x
x
q
q
q
x ,  ,2,1,0  Rx ,
and satisfies   )()1( xxx qqq  .
Remark 2 ([14]) If 0 and ,tba  then
   
)()( btat  .
It is well known that the beta function ),( stBq has the following integral representation:for any 0, st ,
.)()1()1(
)1(),(
0
)1()1(1
)1(
1
0
)1(

 





n
tnsnn
q
st
q
qqqq
dqstB 
Moreover, ),( stBq can be expressed in terms of )(t , the gamma function, as follows:
Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 19 |
.
)(
)()(
),(
st
st
stB
q
qq
q



Definition 2.1 Let 0 and f be a function defined on T,0 . The fractional q-integral of the
Remann-Liouville type is given by )())(( 0
tftfIq  and
 
.)()1(
)(
)1(
)()(
)(
1
)(
0
)1(1
0
)1(













n
nnn
q
q
t
q
q
tqfqq
qt
sdsfqsttfI





)1.2(
Definition 2.2 The fractional q-derivative of Riemann-Liouville type of order 0 is defined by
  )()(0
tftfDq  and
  ),()( tfIDtfD l
q
l
qq
 
 )2.2(,0
where l is the smallest integer greater than or equal to v.
Definition 2.3 ([6]) The fractional q-derivative of the Caputo type of order 0 is defined by
     
 
  )3.2(,0,)()(
1
)()(
0
1


 




sdsfDqst
n
tfDItfD q
n
q
t
n
q
qqq
c
where   is the smallest integer greater than or equal to .
Recall that )],,([ RbaCn
is the space of all real-valued function )(tx which have continuous derivatives up
to order 1n on ba, . In the following lemmas, we give some auxiliary results which will be used in the
sequel.
Lemma 2.1 ([6]) Let 0 , then the following equality holds:
    )4.2().0(
)1(
)()(
1
0
fD
k
t
tftfDI k
q
k q
k
q
c
q 

 



On the other hand, the operator sss
p
p
2
)(

 , where 1p , is called the p-Laplacian operator. It is easy to
see that ,1
vp  
where .1
11

vp
The following properties of the p-Laplacian operator will play an
important role in the rest of the paper.
Lemma 2.2 ([19])Let p be a p-Lplacian operator.
Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 20 |
(i) If 21  p , 0xy , and 0,  myx , then
  yxmpyx p
pp  2
1)()(  .
(ii) If 2p , and Myx , , then
  yxMpyx p
pp  2
1)()(  .
Lemma 2.3 Assume that  3,2 , 10 a , 11 a ,
2
1
2


q
a , ]1,0[t and   1,0Ch . Then the
solution )(tx of the boundary value problem
)6.2(
),1()0(
),1()0(
),1()0(
,0)0(
),()))(((
2
2
2
1
0












xDaxD
xDaxD
xax
xD
thtxDD
qq
qq
q
c
q
c
pq



can be represented by the following integral equation:
)7.2(,))(()1()(
))(()1()(
))(()1(
)(
))(()(
)(
1
)(
1
0 0
)3(
1
0 0
)2(
1
0 0
)1(0
0 0
)1(
 
 
 
 






















ddsshqt
ddsshqt
ddsshq
A
ddsshqttx
v
v
v
q
t
v
q
where
0
0
0
1 a
a
A

 ,
1
1
1
1 a
a
A

 ,
2
2
2
21
)1(
aq
qa
A


 ,and
)1(
)( 110



q
tAAA
t ,
 
.
)2()1(
])1([
)(
2
02021





qq
tqAAtAAA
t
Proof Using (2.4) and the fact that 0))0(( xDq
c
p

 , we have
,)())((
0
t
qq
c
p sdshtxD

or equivalently,
)8.2(,))(()(
0
t
qvq
c
sdshtxD 
where 1
11

vp
. Applying the fractional integral operator

qI to both sides of (2.8), we get
Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 21 |
  






t
qqv
qq
q
q dsdshqtt
xD
txDxtx
0 0
)1(2
2
))((
)(
1
)3(
)0(
)0()0()( 


,
or equivalently,
  )9.2(,
1
)0(
)0()0())((
)(
1
)( 2
2
0 0
)1(
t
q
xD
txDxdsdshqttx
q
q
t
qqv
q 


  




  )10.2(,2
1
)0(
)0())((
)1(
1
)(
2
0 0
)2(
t
q
xD
xDdsdshqttxD
q
q
t
qqv
q
q



  




  )11.2(.
1
)0(2
))((
)2(
1
)(
2
0 0
)3(2
q
xD
dsdshqttxD
qt
qqv
q
q



  




Taking 1t on both sides of (2.9), (2.10) and (2.11), we have
  )12.2(,
1
)0(
)0()0())((1
)(
1
)1(
2
1
0 0
)1(
q
xD
xDxdsdshqx
q
qqqv
q 


  




  )13.2(,
1
)0(2
)0())((1
)1(
1
)1(
2
1
0 0
)2(
q
xD
xDdsdshqxD
q
qqqv
q
q



  




  )14.2(.
1
)0(2
))((1
)2(
1
)1(
2
1
0 0
)3(2
q
xD
dsdshqxD
q
qqv
q
q



  




Using
(2.12), (2.13), (2.14) and the boundary value conditions in (2.6) we can get that
  )15.2(,))((1
)2(
)0(
1
0 0
)3(22
 



 


qqv
q
q dsdshq
A
xD
 
  )16.2(,))((1
)2(1
2
))((1
)1(
)0(
1
0 0
)3(12
1
0 0
)2(1
 
 














qqv
q
qqv
q
q
dsdshq
A
q
A
dsdshq
A
xD
and
)17.2(.))(()1()(
))(()1()(
))(()1(
)1(
))(()1(
)(
)0(
1
0 0
)3(
1
0 0
)3(
1
0 0
)2(10
1
0 0
)1(0
 
 
 
 






















qqv
qqv
qqv
q
qqv
q
dsdshqt
dsdshqt
dsdshq
AA
dsdshq
A
x
Substituting (2.15), (2.16) and (2.17) into (2.9) gives (2.7) and this completes the proof. □
Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 22 |
II. SOLVABILITY OF THE FRACTIONAL BOUNDARY VALUE PROBLEM
This section is devoted to the solvability of the fractional boundary value problem given in (2.5). First, we
obtain conditions for existence and uniqueness of the solution )(tx of the fractional boundary value problem
given in (2.5). Then, each result obtained here is illustrated by examples. Recall that ,]1,0[C the space of
continuous functions on  1,0 is a Banach space with the norm )(max ]1,0[ txx t . Now
consider ,1,0],1,0[]1,0[:  iCCTi with




  sdsxsftxT q
t
v
0
0 ))(,(:)( 
and

 








1
0
)2(
1
0
)2(
0
1
0
)1(0)1(
1
)()1()()()1()(
)()1(
)(
)()(
)(
1
)(







qq
t
q
q
q
q
dxqtdxqt
dxq
A
dxqttxT
Then the operator ]1,0[]1,0[: CCT  , defined by 01 TTT  , is continuous and compact.
Theorem 3.1 Suppose 21  v , 10 a , 11 a , ,
2
1
2


v
a )1,0(q and the following conditions
hold: 0 ,
v

2
2
0  and d with
 
 
     )1.3(,)2(1)2()2)1()1((2
)1)2(1)(1()2)2(()1(/
)1)(2)2((
0012
10
2
qq
qq
q
v
vvqAAAA
vAAvv
qvd





 
such that
  ),(1
xtftq 
 for any   )2.3(,1,0),( Rxt 
and
yxdytfxtf  ),(),( for  1,0t and )3.3(., Ryx 
Then boundary value problem (2.5) has a unique solution.
Proof Using inequality (3.3), we get
dsxsft
t

0
),(
 for any   .1,0),( Rxt 
By Lemma 2.2 (i) and (3.3), we have
Solvability of Fractionl q -Difference Equations of…
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)4.3(.)1(
)()()1(
))(,())(,()1(
))(,())(,())(1(
))(,())(,(
)()(
1)2(2
0
)2(2
0
)2(2
00
2
00
00
yxtvd
sdsysxtvd
sdsysfsxsftv
sdsysfsdsxsftv
sdsysfsdsxsf
tyTtxT
vv
q
t
vv
q
t
vv
q
t
q
t
v
q
t
vq
t
v































Moreover,
    
    
    
     )5.3(.)()()1()(
)()()1()(
)()()1(
)(
)()()(
)(
1
))(())((
)()(
1
0
00
)2(
1
0
00
)2(
1
0
00
)1(0
0
00
)1(
0101




























q
q
q
q
t
q
q
dyTxTqt
dyTxTqt
dyTxTq
A
dyTxTqt
tyTTtxTT
tTytTx
Finally, substituting (3.4) in (3.5), we get
 
)6.3(.)1()(
)1()(
)1(
)(
)(
)(
1
1
)()(
1
0
1)2()3(
1
0
1)2()2(
1
0
1)2()1(0
0
1)2()1(2

































q
v
q
v
q
v
q
t
q
v
q
v
dqt
dqt
dq
A
dqtyxvd
tTytTx
Using the equality
  
,
)2)2((
)()2)2((
),2)2(( 1)2(1)2(
0
1)2(1













v
v
tvBt
dqt
q
qqv
q
v
t
q
v
in (3.6) one can write that
 
)2,2)2(()()1,2)2(()(
),2)2((
)(
),2)2((
)(
1
)()(
0
1)2(
2





















vBtvBt
vB
A
vB
t
yxvd
tTytTx
q
q
v
v
Solvability of Fractionl q -Difference Equations of…
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 
 
 
       
   
,
12
1)2()2(
)2()1(
2)1(2
1
1)2(
)1(
)(
)()(
),2)2((1
2
02021
010
1)2(
2



























qq
qq
q
q
q
qqq
v
v
vv
q
tqAAtAAA
vtAAAt
vByxvd








using (1), we get that
 
 
   
   
      
  
    
,
)2(1)2(
)1(
2)1(12
1)2(11
)2)2((
)2)2((
1
)2(1)2(
)()1(
2)1(12
1)2(
)(
)1(
)()(
1
)2)2((
)()2)2((
1
)()(
0012
10
2
02021
010
2
yxK
yxvv
q
qAAAA
vAA
v
v
vd
vv
q
qAAAAA
v
AAA
v
v
yxvd
tTytTx
qq
q
q
qv
qq
q
q
qqq
q
qqv















































where
      
  
     )7.3(,)2(1)2(
)1(
2)1(12
1)2(11
)2)2((
)2)2((
1
0012
10
2
qq
q
q
qv
vv
q
qAAAA
vAA
v
v
vdK












 
Combining (3.7) with (3.1) implies that ,10  K thereforeT is a contraction. As a consequence of the
Banach contraction mapping theorem [22] the boundary value problem given in (2.5) has a unique solution.
□
Theorem 3.2 Suppose 21  v , 0a , 11 a , ,
2
1
2


v
a )1,0(q and the following conditions
hold: 0 ,
v

2
2
0  , and d satisfies (3.1).
such that
  1
),( 
 
 txtf q , for any   .1,0),( Rxt 
and
yxdytfxtf  ),(),( , for  1,0t and ., Ryx 
Solvability of Fractionl q -Difference Equations of…
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Then boundary value problem (2.5) has a unique solution.
Proof The inequality
1
),( 
 
 txtf implies that ),(1
xtft 
 . Therefore replace
),( xtf by ),( xtf in the proof of Theorem 1, we can get the proof of this theorem. □
Theorem 3.3 Suppose 2v , 0a , 11 a ,
2
1
2


v
a . There exists a non-negative function
 1,0)( Lxg  , with 0)(:
1
0
   dgM such that
)(),( tgxtf  for any   )8.3(,1,0),( Rxt 
and there exists a constant d with
 
 
     )9.3(,1)2)1()1((2
)11)(1()1(/
)1)(2(
0012
10
2
qq
q
q
v
qAAAA
AAv
qMd





 
and
yxdytfxtf  ),(),( for  1,0t and ., Ryx 
Then boundary value problem (2.5) has a unique solution.
Proof Using (3.8), we get that
)10.3(.)())(,(
1
00
Mdgdxf q
t
  
For all  1,0t . By the definition of the operator 0T , one can write that
)11.3(.))(,())(,(
)()(
00
00










 sdsysfsdsxsf
tyTtxT
q
t
vq
t
v 
As a consequence of (2.4), (3.10) and (3.11), we have
.)1(
)()()1(
))(,())(,()1(
))(,())(,()1(
)()(
2
0
2
0
2
00
2
00
yxtMv
sdsysxMvd
sdsysfsxsfMv
sdsysfsdsxsfMv
tyTtxT
v
q
t
v
q
t
v
q
t
q
t
v












Moreover,
Solvability of Fractionl q -Difference Equations of…
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    
    
    
 
     .)()()1(
)2()1(
]2)1([2
)()()1(
)1(
)()()1(
)(
)()()(
)(
1
))(())((
)()(
1
0
00
)3(
2
02021
1
0
00
)2(110
1
0
00
)1(0
0
00
)1(
0101




































q
q
q
q
q
q
t
q
q
dyTxTq
q
tqAAtAAA
dyTxTq
tAAA
dyTxTq
A
dyTxTqt
tyTTtxTT
tTytTx
Since the equality
  
  



1
0
11
0
1
1  
q
t
q dqtdqt ,
we have
 
  



























1
0
)3(
2
00121
0
)2(01
1
0
)1(01
0
)1(
1
2
)1(
)2()1(
)2)1((2
)1(
)1(
)(
)1(
)(
)1(
)(
1
)()(












q
q
q
q
q
q
q
q
v
dq
q
tqAtAAA
dq
tAA
dq
A
dq
t
yxMvd
tTytTx
   
 
   



















 
qq
q
q
qqq
q
v
q
qAAAA
AAA
yxBMvd





1
)()1(
]2)1(1[2
1
)(
)1(
)()(
1
),2(1
0012
0102
      
  
    
,
1
)1(
2)1(12
111
)2(
1
0012
10
2
yxK
yx
q
qAAAA
AA
Mvd
qq
q
q
v













where
      
  
    .1
)1(
2)1(12
111
)2(
1
0012
10
2
qq
q
q
v
q
qAAAA
AA
Mvd
K












Solvability of Fractionl q -Difference Equations of…
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By (3.9), we get 1K , which implies thatT is a contraction,therefore the boundary value problem given in
(2.5) has a unique solution. □
In the present part, we illustrate our results by examples. We will use inequation in [18], one has
),()( ttq  for 10  t or 2t ; ),()( tt q for 21  t .
Example 1 Consider the following anti-periodic boundary value problem:
 
)12.3(
),1(
10
3
)0(),1()0(
),1()0(
,0)0(
1,0)),
32
cos(2(4)))(((
22
2
5
22
5
3
7













xDxDxDxD
xx
xD
t
x
ttxDD
qqqq
q
c
q
c
q 


where
3
7
p ,
2
5
 , and
10
3
,1 210  aaa .
Then
4
7
v ,
2
1
210  AAA , and take 4 , 1 and
8

d . because of )1,0(q ,
so we let
2
1
q , obviously,
  
    
      
,
8
)
2
3
(
4
1
)
2
3
(
4
1
)2(1)2(2)1(12
2)2(11
)2)2(()1()1)(2)2((
0012
10
2
d
vvqAAAA
vAA
vvqv
q
qq
q
qq
v








      
  
    
.1
64
55
)23(128
55
)23(128
55
)2(1)2(
)1(
2)1(12
1)2(11
)2)2((
)2)2((
1
0012
10
2












 






q
qq
q
q
qv
vv
q
qAAAA
vAA
v
v
vdK
Moreover, it
can be easy see that
    ).,())
32
cos(2(44 231
xtf
x
ttt qq 


 
Finally,
.
8
)
32
()
32
(4
)
32
cos()
32
cos(4
))
32
cos(2(4))
32
cos(2(4
),(),(
2
22
yx
yx
yxt
ytxt
ytfxtf


















Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 28 |
There fore as a consequence of Theorem 3.1, boundary value problem given in (3.12) has a unique solution.
Example 2 Consider the following boundary value problem:
 
)13.3(
),1(
10
3
)0(),1()0(
),1()0(
,.0)0(
1,0),
40
(sin)))(((
22
2
5
22
5
4
7













xDxDxDxD
xx
xD
t
x
txDD
qqqq
q
c
q
c
q 


where
4
7
p ,
2
5
 , and
10
3
,1 210  aaa .
Then
3
7
v ,
2
1
210  AAA , and take 1 and
20

d . Because of  1,0q , so
we let
2
1
q , taking 1)( tg , we get 1M ,
        
      
,
20
1
12)1(12
2111)1)(2(
0012
10
2
d
qAAAA
AAvqM
qq
qq
v






      
  
    
.1
27
11
1
)1(
2)1(12
111
)2(
1
0012
10
2










qq
q
q
v
q
qAAAA
AA
Mvd
K



On the other hand,
.
20
))
40
(s))
40
(s
),(),(
22
yx
yinxin
ytfxtf








For  1,0t and ., Ryx 
Therefore by Theorem 3.3, the antiperiodic boundary value problem given in (3.13) has a unique solution.
REFERENCES
[1] Jackson, FH: q-Difference equations. Am. J. Math. 32, 305-314 (1910)
[2] Al-Salam, WA: Some fractional q-integrals and q-derivatives. Proc. Edinb. Math. Soc. 15(2), 135-140
(1966/1967)
[3] Agarwal, RP: Certain fractional q-integrals and q-derivatives. Proc. Camb. Philos. Soc. 66, 365-370
Solvability of Fractionl q -Difference Equations of…
|Volume 2| Issue 3 | www.ijrtem.com | 29 |
(1969)
[4] Ernst, T: The history of q-calculus and a new method. UUDM Report 2000:16. Department of
Mathematics, Uppsala University (2000)
[5] Ahmad B, Ntouyas S K, Purnaras I K. Existence results for nonlocal boundary value problems of
nonlinear fractional q-difference equations[J]. Advances in Difference Equations, 2012, 2012(1):140.
[6] Annaby, MH, Mansour, ZS: Fractional q-Calculus and Equations. Lecture Notes in Mathematics, vol.
2056. Springer, Berlin (2012)
[7] Rajkovic, PM, Marinkovic, SD, Stankovic, MS: Fractional integrals and derivatives in q-calculus. Appl.
Anal. Discrete Math. 1, 311-323 (2007)
[8] Dobrogowska, A, Odzijewicz, A: Second order q-difference equations solvable by factorization method.
J. Comput. Appl. Math. 193, 319-346 (2006)
[9] Gasper, G, Rahman, M: Some systems of multivariable orthogonal q-Racah polynomials. Ramanujan J.
13, 389-405 (2007)
[10] Ismail, MEH, Simeonov, P: q-Difference operators for orthogonal polynomials. J. Comput. Appl. Math.
233, 749-761 (2009)
[11] El-Shahed, M, Hassan, HA: Positive solutions of q-difference equation. Proc. Am. Math. Soc. 138,
1733-1738 (2010)
[12] Ahmad, B: Boundary-value problems for nonlinear third-order q-difference equations. Electron. J.
Differ. Equ. 2011, 94 (2011)
[13] Ahmad, B, Alsaedi, A, Ntouyas, SK: A study of second-order q-difference equations with boundary
conditions. Adv. Differ. Equ. 2012, 35 (2012)
[14] Tariboon J, Ntouyas S K, Agarwal P. New concepts of fractional quantum calculus and applications to
impulsive fractional q-difference equations[J]. Advances in Difference Equations, 2015, 2015(1):1-19.
[15] Ma K, Sun S, Han Z. Existence of solutions of boundary value problems for singular fractional
q-difference equations[J]. Journal of Applied Mathematics & Computing, 2017, 54(1-2): 23-40.
[16] Jleli M, Samet B. Solvability of a q-fractional integral equation arising in the study of an epidemic
model[J]. Advances in Difference Equations, 2017, 2017(1):21.
[17] Zhai C, Ren J. Positive and negative solutions of a boundary value problem for a fractional,
q-difference e quation[J]. Advances in Difference Equations, 2017, 2017(1):82.
[18] Aktuğlu H, Özarslan, Mehmet Ali. On the Solvability of Caputo q-Fractional Boundary Value Problem
Involving p-Laplacian Operator[J]. Abstract and Applied Analysis,2013, (2013-6-2 7),
Analysis,2013,(2013-6-27), 2013, 2013(6):-880203.

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Solvability of Fractionl q -Difference Equations of Order 2   3 Involving The P-Laplacian Operator

  • 1. Invention Journal of Research Technology in Engineering & Management (IJRTEM) ISSN: 2455-3689 www.ijrtem.com Volume 2 Issue 3 ǁ March. 2018 ǁ PP 17-29 |Volume 2| Issue 3 | www.ijrtem.com | 17 | Solvability of Fractionlq -Difference Equations of Order 32  Involving The P-Laplacian Operator Yawen Yan Chengmin Hou (Department of mathematics,Yanbian University,Yanji 133002,P.R.China) ABSTRACT : In this paper, we study the existence of solutions for non-linear fractional q-difference equations of order 32  involving the p-Laplacian operator with various boundary value conditions. By using the Banach contraction mapping principle, we prove that, under certain conditions, the suggested non-linear fractional boundary value problem involving the p-Laplacian operator has a unique solution. Finally, we illustrate our results with some examples. KEYWORDS: p-Laplacian operators; Caputo fractional derivative; Caputo fractional boundary value problem I. INTRODUCTION In recent years, the topic of q-calculus has attracted the attention of several researchers and a variety of new results can be found in the papers [2-10] and the references cited therein. In 2010, Ferreira [1] considered the existence of nontrivial solutions to the fractional q-difference equation .0)1()0( ,10)),(,()(0,   xx ttxtftxDq  In [15], Aktuğlu and Özarslan dealt with the following Caputo q-fractional boundary value problem involving the p-Laplacian operator: ,)1()0(),1()0(,1,,3,2,0)0( ,10)),(,()))((( 10 xDaxDxaxnkxD ttxtftxDD qq k q q c pq      where 0, 10 aa , 1 , and ),]1,0([ RRCf  . Under some conditions, the authors obtained the existence and uniqueness of the solution for the above boundary value problem by using the Banach contraction mapping principle. In this paper, we focus on the solvability of the following non-linear fractional differential equations of order  3,2 involving the p-Laplacian operator with boundary conditions:             ),1()0( ),1()0( ),1()0( ,0)0( )),(,()))((( 2 2 2 1 0 xDaxD xDaxD xax xD txtftxDD qq qq q c q c pq   
  • 2. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 18 | where ),]1,0([ RRCf  and ),,]1,0([)( 2 RRCtx  ,)( 2 sss p p   ,1p vp  1 , 1 11  vp ,  q c D is the fractional q-derivative of the Caputo type, 2 , qq DD is the fractional q-derivative and 10 a , 11 a , 2 1 2   v a , ]1,0[t ,  D ,  D is the conformable fractional derivative. 2 Preliminaries on fractional q-calculus In this section, we present basic definitions and results that will be needed in the rest of the paper. More detailed information about the theory of fractional q-calculus can be found in [6,7,8]. Let )1,0(q and define   q q a a q    1 1 : , Ra . The q-analogue of the power function  n ba )(  with ],2,1,0[:0  Nn is   ,1:)( 0  ba        1 0 :)( n k kn bqaba , Rba , . More generally, if R , then           0 )( /1 /1 :)( n n n qab qab aba   , 0a . In particular, if 0b then  aa )( . We also use the notation  00 )(  for 0 . The q-gamma function is defined by 1 )1( )1( )1( :)(      x x q q q x ,  ,2,1,0  Rx , and satisfies   )()1( xxx qqq  . Remark 2 ([14]) If 0 and ,tba  then     )()( btat  . It is well known that the beta function ),( stBq has the following integral representation:for any 0, st , .)()1()1( )1(),( 0 )1()1(1 )1( 1 0 )1(         n tnsnn q st q qqqq dqstB  Moreover, ),( stBq can be expressed in terms of )(t , the gamma function, as follows:
  • 3. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 19 | . )( )()( ),( st st stB q qq q    Definition 2.1 Let 0 and f be a function defined on T,0 . The fractional q-integral of the Remann-Liouville type is given by )())(( 0 tftfIq  and   .)()1( )( )1( )()( )( 1 )( 0 )1(1 0 )1(              n nnn q q t q q tqfqq qt sdsfqsttfI      )1.2( Definition 2.2 The fractional q-derivative of Riemann-Liouville type of order 0 is defined by   )()(0 tftfDq  and   ),()( tfIDtfD l q l qq    )2.2(,0 where l is the smallest integer greater than or equal to v. Definition 2.3 ([6]) The fractional q-derivative of the Caputo type of order 0 is defined by           )3.2(,0,)()( 1 )()( 0 1         sdsfDqst n tfDItfD q n q t n q qqq c where   is the smallest integer greater than or equal to . Recall that )],,([ RbaCn is the space of all real-valued function )(tx which have continuous derivatives up to order 1n on ba, . In the following lemmas, we give some auxiliary results which will be used in the sequel. Lemma 2.1 ([6]) Let 0 , then the following equality holds:     )4.2().0( )1( )()( 1 0 fD k t tftfDI k q k q k q c q        On the other hand, the operator sss p p 2 )(   , where 1p , is called the p-Laplacian operator. It is easy to see that ,1 vp   where .1 11  vp The following properties of the p-Laplacian operator will play an important role in the rest of the paper. Lemma 2.2 ([19])Let p be a p-Lplacian operator.
  • 4. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 20 | (i) If 21  p , 0xy , and 0,  myx , then   yxmpyx p pp  2 1)()(  . (ii) If 2p , and Myx , , then   yxMpyx p pp  2 1)()(  . Lemma 2.3 Assume that  3,2 , 10 a , 11 a , 2 1 2   q a , ]1,0[t and   1,0Ch . Then the solution )(tx of the boundary value problem )6.2( ),1()0( ),1()0( ),1()0( ,0)0( ),()))((( 2 2 2 1 0             xDaxD xDaxD xax xD thtxDD qq qq q c q c pq    can be represented by the following integral equation: )7.2(,))(()1()( ))(()1()( ))(()1( )( ))(()( )( 1 )( 1 0 0 )3( 1 0 0 )2( 1 0 0 )1(0 0 0 )1(                               ddsshqt ddsshqt ddsshq A ddsshqttx v v v q t v q where 0 0 0 1 a a A   , 1 1 1 1 a a A   , 2 2 2 21 )1( aq qa A    ,and )1( )( 110    q tAAA t ,   . )2()1( ])1([ )( 2 02021      qq tqAAtAAA t Proof Using (2.4) and the fact that 0))0(( xDq c p   , we have ,)())(( 0 t qq c p sdshtxD  or equivalently, )8.2(,))(()( 0 t qvq c sdshtxD  where 1 11  vp . Applying the fractional integral operator  qI to both sides of (2.8), we get
  • 5. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 21 |          t qqv qq q q dsdshqtt xD txDxtx 0 0 )1(2 2 ))(( )( 1 )3( )0( )0()0()(    , or equivalently,   )9.2(, 1 )0( )0()0())(( )( 1 )( 2 2 0 0 )1( t q xD txDxdsdshqttx q q t qqv q             )10.2(,2 1 )0( )0())(( )1( 1 )( 2 0 0 )2( t q xD xDdsdshqttxD q q t qqv q q             )11.2(. 1 )0(2 ))(( )2( 1 )( 2 0 0 )3(2 q xD dsdshqttxD qt qqv q q           Taking 1t on both sides of (2.9), (2.10) and (2.11), we have   )12.2(, 1 )0( )0()0())((1 )( 1 )1( 2 1 0 0 )1( q xD xDxdsdshqx q qqqv q             )13.2(, 1 )0(2 )0())((1 )1( 1 )1( 2 1 0 0 )2( q xD xDdsdshqxD q qqqv q q             )14.2(. 1 )0(2 ))((1 )2( 1 )1( 2 1 0 0 )3(2 q xD dsdshqxD q qqv q q           Using (2.12), (2.13), (2.14) and the boundary value conditions in (2.6) we can get that   )15.2(,))((1 )2( )0( 1 0 0 )3(22          qqv q q dsdshq A xD     )16.2(,))((1 )2(1 2 ))((1 )1( )0( 1 0 0 )3(12 1 0 0 )2(1                   qqv q qqv q q dsdshq A q A dsdshq A xD and )17.2(.))(()1()( ))(()1()( ))(()1( )1( ))(()1( )( )0( 1 0 0 )3( 1 0 0 )3( 1 0 0 )2(10 1 0 0 )1(0                               qqv qqv qqv q qqv q dsdshqt dsdshqt dsdshq AA dsdshq A x Substituting (2.15), (2.16) and (2.17) into (2.9) gives (2.7) and this completes the proof. □
  • 6. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 22 | II. SOLVABILITY OF THE FRACTIONAL BOUNDARY VALUE PROBLEM This section is devoted to the solvability of the fractional boundary value problem given in (2.5). First, we obtain conditions for existence and uniqueness of the solution )(tx of the fractional boundary value problem given in (2.5). Then, each result obtained here is illustrated by examples. Recall that ,]1,0[C the space of continuous functions on  1,0 is a Banach space with the norm )(max ]1,0[ txx t . Now consider ,1,0],1,0[]1,0[:  iCCTi with       sdsxsftxT q t v 0 0 ))(,(:)(  and            1 0 )2( 1 0 )2( 0 1 0 )1(0)1( 1 )()1()()()1()( )()1( )( )()( )( 1 )(        qq t q q q q dxqtdxqt dxq A dxqttxT Then the operator ]1,0[]1,0[: CCT  , defined by 01 TTT  , is continuous and compact. Theorem 3.1 Suppose 21  v , 10 a , 11 a , , 2 1 2   v a )1,0(q and the following conditions hold: 0 , v  2 2 0  and d with          )1.3(,)2(1)2()2)1()1((2 )1)2(1)(1()2)2(()1(/ )1)(2)2(( 0012 10 2 qq qq q v vvqAAAA vAAvv qvd        such that   ),(1 xtftq   for any   )2.3(,1,0),( Rxt  and yxdytfxtf  ),(),( for  1,0t and )3.3(., Ryx  Then boundary value problem (2.5) has a unique solution. Proof Using inequality (3.3), we get dsxsft t  0 ),(  for any   .1,0),( Rxt  By Lemma 2.2 (i) and (3.3), we have
  • 7. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 23 | )4.3(.)1( )()()1( ))(,())(,()1( ))(,())(,())(1( ))(,())(,( )()( 1)2(2 0 )2(2 0 )2(2 00 2 00 00 yxtvd sdsysxtvd sdsysfsxsftv sdsysfsdsxsftv sdsysfsdsxsf tyTtxT vv q t vv q t vv q t q t v q t vq t v                                Moreover,                     )5.3(.)()()1()( )()()1()( )()()1( )( )()()( )( 1 ))(())(( )()( 1 0 00 )2( 1 0 00 )2( 1 0 00 )1(0 0 00 )1( 0101                             q q q q t q q dyTxTqt dyTxTqt dyTxTq A dyTxTqt tyTTtxTT tTytTx Finally, substituting (3.4) in (3.5), we get   )6.3(.)1()( )1()( )1( )( )( )( 1 1 )()( 1 0 1)2()3( 1 0 1)2()2( 1 0 1)2()1(0 0 1)2()1(2                                  q v q v q v q t q v q v dqt dqt dq A dqtyxvd tTytTx Using the equality    , )2)2(( )()2)2(( ),2)2(( 1)2(1)2( 0 1)2(1              v v tvBt dqt q qqv q v t q v in (3.6) one can write that   )2,2)2(()()1,2)2(()( ),2)2(( )( ),2)2(( )( 1 )()( 0 1)2( 2                      vBtvBt vB A vB t yxvd tTytTx q q v v
  • 8. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 24 |                   , 12 1)2()2( )2()1( 2)1(2 1 1)2( )1( )( )()( ),2)2((1 2 02021 010 1)2( 2                            qq qq q q q qqq v v vv q tqAAtAAA vtAAAt vByxvd         using (1), we get that                            , )2(1)2( )1( 2)1(12 1)2(11 )2)2(( )2)2(( 1 )2(1)2( )()1( 2)1(12 1)2( )( )1( )()( 1 )2)2(( )()2)2(( 1 )()( 0012 10 2 02021 010 2 yxK yxvv q qAAAA vAA v v vd vv q qAAAAA v AAA v v yxvd tTytTx qq q q qv qq q q qqq q qqv                                                where                )7.3(,)2(1)2( )1( 2)1(12 1)2(11 )2)2(( )2)2(( 1 0012 10 2 qq q q qv vv q qAAAA vAA v v vdK               Combining (3.7) with (3.1) implies that ,10  K thereforeT is a contraction. As a consequence of the Banach contraction mapping theorem [22] the boundary value problem given in (2.5) has a unique solution. □ Theorem 3.2 Suppose 21  v , 0a , 11 a , , 2 1 2   v a )1,0(q and the following conditions hold: 0 , v  2 2 0  , and d satisfies (3.1). such that   1 ),(     txtf q , for any   .1,0),( Rxt  and yxdytfxtf  ),(),( , for  1,0t and ., Ryx 
  • 9. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 25 | Then boundary value problem (2.5) has a unique solution. Proof The inequality 1 ),(     txtf implies that ),(1 xtft   . Therefore replace ),( xtf by ),( xtf in the proof of Theorem 1, we can get the proof of this theorem. □ Theorem 3.3 Suppose 2v , 0a , 11 a , 2 1 2   v a . There exists a non-negative function  1,0)( Lxg  , with 0)(: 1 0    dgM such that )(),( tgxtf  for any   )8.3(,1,0),( Rxt  and there exists a constant d with          )9.3(,1)2)1()1((2 )11)(1()1(/ )1)(2( 0012 10 2 qq q q v qAAAA AAv qMd        and yxdytfxtf  ),(),( for  1,0t and ., Ryx  Then boundary value problem (2.5) has a unique solution. Proof Using (3.8), we get that )10.3(.)())(,( 1 00 Mdgdxf q t    For all  1,0t . By the definition of the operator 0T , one can write that )11.3(.))(,())(,( )()( 00 00            sdsysfsdsxsf tyTtxT q t vq t v  As a consequence of (2.4), (3.10) and (3.11), we have .)1( )()()1( ))(,())(,()1( ))(,())(,()1( )()( 2 0 2 0 2 00 2 00 yxtMv sdsysxMvd sdsysfsxsfMv sdsysfsdsxsfMv tyTtxT v q t v q t v q t q t v             Moreover,
  • 10. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 26 |                       .)()()1( )2()1( ]2)1([2 )()()1( )1( )()()1( )( )()()( )( 1 ))(())(( )()( 1 0 00 )3( 2 02021 1 0 00 )2(110 1 0 00 )1(0 0 00 )1( 0101                                     q q q q q q t q q dyTxTq q tqAAtAAA dyTxTq tAAA dyTxTq A dyTxTqt tyTTtxTT tTytTx Since the equality          1 0 11 0 1 1   q t q dqtdqt , we have                                 1 0 )3( 2 00121 0 )2(01 1 0 )1(01 0 )1( 1 2 )1( )2()1( )2)1((2 )1( )1( )( )1( )( )1( )( 1 )()(             q q q q q q q q v dq q tqAtAAA dq tAA dq A dq t yxMvd tTytTx                                qq q q qqq q v q qAAAA AAA yxBMvd      1 )()1( ]2)1(1[2 1 )( )1( )()( 1 ),2(1 0012 0102                , 1 )1( 2)1(12 111 )2( 1 0012 10 2 yxK yx q qAAAA AA Mvd qq q q v              where               .1 )1( 2)1(12 111 )2( 1 0012 10 2 qq q q v q qAAAA AA Mvd K            
  • 11. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 27 | By (3.9), we get 1K , which implies thatT is a contraction,therefore the boundary value problem given in (2.5) has a unique solution. □ In the present part, we illustrate our results by examples. We will use inequation in [18], one has ),()( ttq  for 10  t or 2t ; ),()( tt q for 21  t . Example 1 Consider the following anti-periodic boundary value problem:   )12.3( ),1( 10 3 )0(),1()0( ),1()0( ,0)0( 1,0)), 32 cos(2(4)))((( 22 2 5 22 5 3 7              xDxDxDxD xx xD t x ttxDD qqqq q c q c q    where 3 7 p , 2 5  , and 10 3 ,1 210  aaa . Then 4 7 v , 2 1 210  AAA , and take 4 , 1 and 8  d . because of )1,0(q , so we let 2 1 q , obviously,                , 8 ) 2 3 ( 4 1 ) 2 3 ( 4 1 )2(1)2(2)1(12 2)2(11 )2)2(()1()1)(2)2(( 0012 10 2 d vvqAAAA vAA vvqv q qq q qq v                        .1 64 55 )23(128 55 )23(128 55 )2(1)2( )1( 2)1(12 1)2(11 )2)2(( )2)2(( 1 0012 10 2                     q qq q q qv vv q qAAAA vAA v v vdK Moreover, it can be easy see that     ).,()) 32 cos(2(44 231 xtf x ttt qq      Finally, . 8 ) 32 () 32 (4 ) 32 cos() 32 cos(4 )) 32 cos(2(4)) 32 cos(2(4 ),(),( 2 22 yx yx yxt ytxt ytfxtf                  
  • 12. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 28 | There fore as a consequence of Theorem 3.1, boundary value problem given in (3.12) has a unique solution. Example 2 Consider the following boundary value problem:   )13.3( ),1( 10 3 )0(),1()0( ),1()0( ,.0)0( 1,0), 40 (sin)))((( 22 2 5 22 5 4 7              xDxDxDxD xx xD t x txDD qqqq q c q c q    where 4 7 p , 2 5  , and 10 3 ,1 210  aaa . Then 3 7 v , 2 1 210  AAA , and take 1 and 20  d . Because of  1,0q , so we let 2 1 q , taking 1)( tg , we get 1M ,                 , 20 1 12)1(12 2111)1)(2( 0012 10 2 d qAAAA AAvqM qq qq v                      .1 27 11 1 )1( 2)1(12 111 )2( 1 0012 10 2           qq q q v q qAAAA AA Mvd K    On the other hand, . 20 )) 40 (s)) 40 (s ),(),( 22 yx yinxin ytfxtf         For  1,0t and ., Ryx  Therefore by Theorem 3.3, the antiperiodic boundary value problem given in (3.13) has a unique solution. REFERENCES [1] Jackson, FH: q-Difference equations. Am. J. Math. 32, 305-314 (1910) [2] Al-Salam, WA: Some fractional q-integrals and q-derivatives. Proc. Edinb. Math. Soc. 15(2), 135-140 (1966/1967) [3] Agarwal, RP: Certain fractional q-integrals and q-derivatives. Proc. Camb. Philos. Soc. 66, 365-370
  • 13. Solvability of Fractionl q -Difference Equations of… |Volume 2| Issue 3 | www.ijrtem.com | 29 | (1969) [4] Ernst, T: The history of q-calculus and a new method. UUDM Report 2000:16. Department of Mathematics, Uppsala University (2000) [5] Ahmad B, Ntouyas S K, Purnaras I K. Existence results for nonlocal boundary value problems of nonlinear fractional q-difference equations[J]. Advances in Difference Equations, 2012, 2012(1):140. [6] Annaby, MH, Mansour, ZS: Fractional q-Calculus and Equations. Lecture Notes in Mathematics, vol. 2056. Springer, Berlin (2012) [7] Rajkovic, PM, Marinkovic, SD, Stankovic, MS: Fractional integrals and derivatives in q-calculus. Appl. Anal. Discrete Math. 1, 311-323 (2007) [8] Dobrogowska, A, Odzijewicz, A: Second order q-difference equations solvable by factorization method. J. Comput. Appl. Math. 193, 319-346 (2006) [9] Gasper, G, Rahman, M: Some systems of multivariable orthogonal q-Racah polynomials. Ramanujan J. 13, 389-405 (2007) [10] Ismail, MEH, Simeonov, P: q-Difference operators for orthogonal polynomials. J. Comput. Appl. Math. 233, 749-761 (2009) [11] El-Shahed, M, Hassan, HA: Positive solutions of q-difference equation. Proc. Am. Math. Soc. 138, 1733-1738 (2010) [12] Ahmad, B: Boundary-value problems for nonlinear third-order q-difference equations. Electron. J. Differ. Equ. 2011, 94 (2011) [13] Ahmad, B, Alsaedi, A, Ntouyas, SK: A study of second-order q-difference equations with boundary conditions. Adv. Differ. Equ. 2012, 35 (2012) [14] Tariboon J, Ntouyas S K, Agarwal P. New concepts of fractional quantum calculus and applications to impulsive fractional q-difference equations[J]. Advances in Difference Equations, 2015, 2015(1):1-19. [15] Ma K, Sun S, Han Z. Existence of solutions of boundary value problems for singular fractional q-difference equations[J]. Journal of Applied Mathematics & Computing, 2017, 54(1-2): 23-40. [16] Jleli M, Samet B. Solvability of a q-fractional integral equation arising in the study of an epidemic model[J]. Advances in Difference Equations, 2017, 2017(1):21. [17] Zhai C, Ren J. Positive and negative solutions of a boundary value problem for a fractional, q-difference e quation[J]. Advances in Difference Equations, 2017, 2017(1):82. [18] Aktuğlu H, Özarslan, Mehmet Ali. On the Solvability of Caputo q-Fractional Boundary Value Problem Involving p-Laplacian Operator[J]. Abstract and Applied Analysis,2013, (2013-6-2 7), Analysis,2013,(2013-6-27), 2013, 2013(6):-880203.