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Chemical Kinetics (Pt. 4)
The First-Order Integrated
Rate Law
By Shawn P. Shields, Ph.D.
This work is licensed by Shawn P. Shields-Maxwell under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0
International License.
Differential Rate Laws
(Differential) Rate Laws for 3 common
reaction orders:
First Order: Rate = k [A]1
Second Order: Rate = k [A]2
Zero Order: Rate = k [A]0
(No dependence of reaction rate on [A].)
Integrated Rate Laws
Use calculus to integrate the
(differential) rate law for each of
three common reaction orders.
Now, we have a practical way to
determine the order of a reaction.
Determining Reaction Order using
Integrated Rate Laws
1) In an experiment, collect
concentration data versus time.
2) To determine if the reaction is
first order, calculate the ln[A] of
each concentration.
3) Plot ln[A] versus time. If it’s a
straight line, it’s first order! 
First-Order Integrated Rate Law
Using calculus to integrate the differential rate
law for a first-order process gives us
ln
A t
A 0
= −𝑘t
Where,
[A]0 is the initial concentration of A, and
[A]t is the concentration of A at some time, t, during the
course of the reaction.
First-Order Integrated Rate Law
Rearrange this equation…
ln
A t
A 0
= −𝑘t
ln A t − ln A 0 = −𝑘t
ln A t = −𝑘t + ln A 0
This is a linear equation!
Use log rule:
𝐥𝐧
𝐱
𝐲
= 𝐥𝐧 𝐱 − 𝐥𝐧 𝐲
First-Order Integrated Rate Law
A first-order reaction is an exponential
decay (in terms of reactant).
A t = A 0 𝑒−𝑘t
The concentration of reactant A decreases
exponentially over time.
First-Order Plots
Graphs for a first-order reaction:
Graphs for a First Order Reaction from http://2012books.lardbucket.org/books/principles-of-general-chemistry-
v1.0m/s18-03-methods-of-determining-reactio.html
𝑨 𝒕 = 𝑨 𝟎 𝒆−𝒌𝐭 𝐥𝐧 𝑨 𝒕 = −𝒌𝐭 + 𝐥𝐧 𝑨 𝟎
Determining Reaction Order using
Integrated Rate Laws
Step 1: Collect
concentration versus
time data.
Step 2: Calculate
the natural log for
each concentration
measured. (ln [A])
Time [A] ln[A]
0 0.25 -1.38629
60 0.218 -1.52326
90 0.204 -1.58964
120 0.19 -1.66073
180 0.166 -1.79577
Determining Rxn Order using Integrated Rate Laws
Step 3: Graph ln [A] vs. time
The plot shows a
straight line.
The reaction
fits 1st order
kinetics.
Determining Rxn Order using Integrated Rate Laws
𝐥𝐧 𝑨 𝒕 = −𝒌𝐭 + 𝐥𝐧 𝑨 𝟎
k is the “rate
constant”
The slope of the
line is k.
k = 0.0023 s1
Half Life for First-Order Reactions
Half-life is defined as
the time required for
one-half of a
reactant to react.
Because [A] at t1/2 is
one-half of the
original concentration
of A,
[A]t = 0.5 [A]0
The Half Life of a First Order Reaction from http://2012books.lardbucket.org/books/principles-of-general-chemistry-
v1.0m/s18-05-half-lives-and-radioactive-dec.html
Half-Life for a First Order Process
Deriving an expression for the half-life of a
first-order process:
Let [A]t = 0.5[A]0
ln 0.5 A 0 = −𝑘t + ln A 0
ln 0.5 A 0 − ln A 0 = −𝑘t
Use log rule: 𝐥𝐧
𝐱
𝐲
= 𝐥𝐧 𝐱 − 𝐥𝐧 𝐲
Half-Life for a First Order Process
ln 0.5 A 0 − ln A 0 = −𝑘t
ln
0.5 A 0
A 0
= −𝑘t1
2
ln
0.5 A 0
A 0
= −𝑘t1
2
𝐥𝐧 𝟎. 𝟓 = −𝒌𝐭 𝟏
𝟐
Time is now labeled
for half life with a
subscript (t1/2)
Half-Life for a First Order Process
𝐥𝐧 𝟎. 𝟓 = −𝒌𝐭 𝟏
𝟐
−0.693 = −𝑘t1
2
Cancel negative signs and solve for t1/2
𝒕 𝟏
𝟐
=
𝟎. 𝟔𝟗𝟑
𝒌
Ln 0.5 is just a
number (put it in
your calculator!)
Half-Life for a First Order Process
𝒕 𝟏
𝟐
=
𝟎. 𝟔𝟗𝟑
𝒌
Note that the half life for a first-order process
does not depend on the initial concentration [A]0
Example Problems
will be posted separately.
Next up,
The Second Order Integrated
Rate Law (Pt 5)

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Chem 2 - Chemical Kinetics IV: The First-Order Integrated Rate Law

  • 1. Chemical Kinetics (Pt. 4) The First-Order Integrated Rate Law By Shawn P. Shields, Ph.D. This work is licensed by Shawn P. Shields-Maxwell under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
  • 2. Differential Rate Laws (Differential) Rate Laws for 3 common reaction orders: First Order: Rate = k [A]1 Second Order: Rate = k [A]2 Zero Order: Rate = k [A]0 (No dependence of reaction rate on [A].)
  • 3. Integrated Rate Laws Use calculus to integrate the (differential) rate law for each of three common reaction orders. Now, we have a practical way to determine the order of a reaction.
  • 4. Determining Reaction Order using Integrated Rate Laws 1) In an experiment, collect concentration data versus time. 2) To determine if the reaction is first order, calculate the ln[A] of each concentration. 3) Plot ln[A] versus time. If it’s a straight line, it’s first order! 
  • 5. First-Order Integrated Rate Law Using calculus to integrate the differential rate law for a first-order process gives us ln A t A 0 = −𝑘t Where, [A]0 is the initial concentration of A, and [A]t is the concentration of A at some time, t, during the course of the reaction.
  • 6. First-Order Integrated Rate Law Rearrange this equation… ln A t A 0 = −𝑘t ln A t − ln A 0 = −𝑘t ln A t = −𝑘t + ln A 0 This is a linear equation! Use log rule: 𝐥𝐧 𝐱 𝐲 = 𝐥𝐧 𝐱 − 𝐥𝐧 𝐲
  • 7. First-Order Integrated Rate Law A first-order reaction is an exponential decay (in terms of reactant). A t = A 0 𝑒−𝑘t The concentration of reactant A decreases exponentially over time.
  • 8. First-Order Plots Graphs for a first-order reaction: Graphs for a First Order Reaction from http://2012books.lardbucket.org/books/principles-of-general-chemistry- v1.0m/s18-03-methods-of-determining-reactio.html 𝑨 𝒕 = 𝑨 𝟎 𝒆−𝒌𝐭 𝐥𝐧 𝑨 𝒕 = −𝒌𝐭 + 𝐥𝐧 𝑨 𝟎
  • 9. Determining Reaction Order using Integrated Rate Laws Step 1: Collect concentration versus time data. Step 2: Calculate the natural log for each concentration measured. (ln [A]) Time [A] ln[A] 0 0.25 -1.38629 60 0.218 -1.52326 90 0.204 -1.58964 120 0.19 -1.66073 180 0.166 -1.79577
  • 10. Determining Rxn Order using Integrated Rate Laws Step 3: Graph ln [A] vs. time The plot shows a straight line. The reaction fits 1st order kinetics.
  • 11. Determining Rxn Order using Integrated Rate Laws 𝐥𝐧 𝑨 𝒕 = −𝒌𝐭 + 𝐥𝐧 𝑨 𝟎 k is the “rate constant” The slope of the line is k. k = 0.0023 s1
  • 12. Half Life for First-Order Reactions Half-life is defined as the time required for one-half of a reactant to react. Because [A] at t1/2 is one-half of the original concentration of A, [A]t = 0.5 [A]0 The Half Life of a First Order Reaction from http://2012books.lardbucket.org/books/principles-of-general-chemistry- v1.0m/s18-05-half-lives-and-radioactive-dec.html
  • 13. Half-Life for a First Order Process Deriving an expression for the half-life of a first-order process: Let [A]t = 0.5[A]0 ln 0.5 A 0 = −𝑘t + ln A 0 ln 0.5 A 0 − ln A 0 = −𝑘t Use log rule: 𝐥𝐧 𝐱 𝐲 = 𝐥𝐧 𝐱 − 𝐥𝐧 𝐲
  • 14. Half-Life for a First Order Process ln 0.5 A 0 − ln A 0 = −𝑘t ln 0.5 A 0 A 0 = −𝑘t1 2 ln 0.5 A 0 A 0 = −𝑘t1 2 𝐥𝐧 𝟎. 𝟓 = −𝒌𝐭 𝟏 𝟐 Time is now labeled for half life with a subscript (t1/2)
  • 15. Half-Life for a First Order Process 𝐥𝐧 𝟎. 𝟓 = −𝒌𝐭 𝟏 𝟐 −0.693 = −𝑘t1 2 Cancel negative signs and solve for t1/2 𝒕 𝟏 𝟐 = 𝟎. 𝟔𝟗𝟑 𝒌 Ln 0.5 is just a number (put it in your calculator!)
  • 16. Half-Life for a First Order Process 𝒕 𝟏 𝟐 = 𝟎. 𝟔𝟗𝟑 𝒌 Note that the half life for a first-order process does not depend on the initial concentration [A]0
  • 17. Example Problems will be posted separately. Next up, The Second Order Integrated Rate Law (Pt 5)