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Discrete and Continuous  Probability Distributions
Chapter Goals ,[object Object],[object Object],[object Object],[object Object],[object Object]
Probability Distributions Continuous   Probability Distributions Binomial Hypergeometric Poisson Probability Distributions Discrete   Probability Distributions Normal Uniform Exponential
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Discrete Probability Distributions
Continuous Probability Distributions ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
The Binomial Distribution Binomial Hypergeometric Poisson Probability Distributions Discrete   Probability Distributions
The Binomial Distribution ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Binomial Distribution Settings ,[object Object],[object Object],[object Object],[object Object]
Counting Rule for Combinations ,[object Object],where: n! =n(n - 1)(n - 2) . . . (2)(1) x! = x(x - 1)(x - 2) . . . (2)(1)   0! = 1  (by definition)
Binomial Distribution Formula P(x) = probability of  x  successes in  n  trials,   with probability of success  p   on each trial x  =  number of ‘successes’ in sample,  (x = 0, 1, 2, ...,  n ) p  =  probability of “success” per trial q  =  probability of “failure” = (1 – p) n  =  number of trials (sample size) P(x) n x ! n x p q x n x ! ( ) !    Example:   Flip a coin four times, let  x = # heads: n  = 4 p  = 0.5 q  = (1 - .5) = .5 x = 0, 1, 2, 3, 4
Binomial Distribution ,[object Object],n = 5  p = 0.1 n = 5  p = 0.5 Mean 0 .2 .4 .6 0 1 2 3 4 5 X P(X) .2 .4 .6 0 1 2 3 4 5 X P(X) 0 Here, n = 5 and p = .1 Here, n = 5 and p = .5
Binomial Distribution Characteristics ,[object Object],Variance and Standard Deviation Where n = sample size p = probability of success q = (1 – p) = probability of failure
Binomial Characteristics n = 5  p = 0.1 n = 5  p = 0.5 Mean 0 .2 .4 .6 0 1 2 3 4 5 X P(X) .2 .4 .6 0 1 2 3 4 5 X P(X) 0 Examples
Using Binomial Tables Examples:  n = 10, p = .35, x = 3:  P(x = 3|n =10, p = .35) = .2522 n = 10, p = .75, x = 2:  P(x = 2|n =10, p = .75) = .0004 n = 10 x p=.15 p=.20 p=.25 p=.30 p=.35 p=.40 p=.45 p=.50 0 1 2 3 4 5 6 7 8 9 10 0.1969 0.3474 0.2759 0.1298 0.0401 0.0085 0.0012 0.0001 0.0000 0.0000 0.0000 0.1074 0.2684 0.3020 0.2013 0.0881 0.0264 0.0055 0.0008 0.0001 0.0000 0.0000 0.0563 0.1877 0.2816 0.2503 0.1460 0.0584 0.0162 0.0031 0.0004 0.0000 0.0000 0.0282 0.1211 0.2335 0.2668 0.2001 0.1029 0.0368 0.0090 0.0014 0.0001 0.0000 0.0135 0.0725 0.1757 0.2522 0.2377 0.1536 0.0689 0.0212 0.0043 0.0005 0.0000 0.0060 0.0403 0.1209 0.2150 0.2508 0.2007 0.1115 0.0425 0.0106 0.0016 0.0001 0.0025 0.0207 0.0763 0.1665 0.2384 0.2340 0.1596 0.0746 0.0229 0.0042 0.0003 0.0010 0.0098 0.0439 0.1172 0.2051 0.2461 0.2051 0.1172 0.0439 0.0098 0.0010 10 9 8 7 6 5 4 3 2 1 0 p=.85 p=.80 p=.75 p=.70 p=.65 p=.60 p=.55 p=.50 x
Using PHStat ,[object Object]
Using PHStat ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
PHStat Output P(x = 3 | n = 10, p = .35) = .2522 P(x > 5 | n = 10, p = .35) = .0949
The Poisson Distribution Binomial Hypergeometric Poisson Probability Distributions Discrete   Probability Distributions
The Poisson Distribution ,[object Object],[object Object],[object Object],[object Object],[object Object]
Poisson Distribution Formula where: t  = size of the segment of interest  x = number of successes in segment of interest    = expected number of successes in a segment of unit size e = base of the natural logarithm system (2.71828...)
Poisson Distribution Characteristics ,[object Object],Variance and Standard Deviation where   = number of successes in a segment of unit size t = the size of the segment of interest
Using Poisson Tables Example:  Find P(x = 2)  if    = .05  and  t = 100 X  t 0.10 0.20 0.30 0.40 0.50 0.60 0.70 0.80 0.90 0 1 2 3 4 5 6 7 0.9048 0.0905 0.0045 0.0002 0.0000 0.0000 0.0000 0.0000 0.8187 0.1637 0.0164 0.0011 0.0001 0.0000 0.0000 0.0000 0.7408 0.2222 0.0333 0.0033 0.0003 0.0000 0.0000 0.0000 0.6703 0.2681 0.0536 0.0072 0.0007 0.0001 0.0000 0.0000 0.6065 0.3033 0.0758 0.0126 0.0016 0.0002 0.0000 0.0000 0.5488 0.3293 0.0988 0.0198 0.0030 0.0004 0.0000 0.0000 0.4966 0.3476 0.1217 0.0284 0.0050 0.0007 0.0001 0.0000 0.4493 0.3595 0.1438 0.0383 0.0077 0.0012 0.0002 0.0000 0.4066 0.3659 0.1647 0.0494 0.0111 0.0020 0.0003 0.0000
Graph of Poisson Probabilities P(x = 2) = .0758   Graphically:    = .05  and  t = 100 X  t = 0.50 0 1 2 3 4 5 6 7 0.6065 0.3033 0.0758 0.0126 0.0016 0.0002 0.0000 0.0000
Poisson Distribution Shape ,[object Object], t = 0.50  t = 3.0
The Hypergeometric Distribution Binomial Poisson Probability Distributions Discrete   Probability Distributions Hypergeometric
The Hypergeometric Distribution ,[object Object],[object Object],[object Object],[object Object]
Hypergeometric Distribution Formula . Where N = Population size X = number of successes in the population n = sample size x = number of successes in the sample n – x = number of failures in the sample (Two possible outcomes per trial)
Hypergeometric Distribution Formula ,[object Object],[object Object],[object Object]
Hypergeometric Distribution  in PHStat ,[object Object],[object Object]
Hypergeometric Distribution  in PHStat ,[object Object],[object Object],[object Object],P(x = 2) = 0.3 (continued)
The Normal Distribution Continuous   Probability Distributions Probability Distributions Normal Uniform Exponential
The Normal Distribution ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Mean  = Median  = Mode x f(x) μ σ
By varying the parameters   μ   and  σ , we obtain different normal distributions Many Normal Distributions
The Normal Distribution Shape x f(x) μ σ Changing  μ  shifts the distribution left or right . Changing   σ   increases or decreases the spread.
Finding Normal Probabilities   Probability is the  area under the curve! a b x f(x) P a x b ( )   Probability is measured by the area under the curve
Probability as  Area Under the Curve f(x) x μ 0.5 0.5 The  total area under the curve is 1.0 , and the curve is symmetric, so half is above the mean, half is below
Empirical Rules ,[object Object],f(x) x μ μ  σ μ  σ What can we say about the distribution of values around the mean?  There are some general rules: σ σ 68.26%
The Empirical Rule ,[object Object],[object Object],x μ 2σ 2σ x μ 3σ 3σ 95.44% 99.72% (continued)
Importance of the Rule ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
The Standard Normal Distribution ,[object Object],[object Object],[object Object],z f(z) 0 1 Values above the mean have  positive  z-values, values below the mean have  negative  z-values
The Standard Normal ,[object Object],[object Object]
Translation to the Standard Normal Distribution ,[object Object]
Example ,[object Object],[object Object]
Comparing  x  and  z  units z 100 3.0 0 250 x Note that the distribution is the same, only the scale has changed.  We can express the problem in original units (x) or in standardized units (z) μ   = 100 σ   = 50
The Standard Normal Table ,[object Object],[object Object],[object Object],z 0 2.00 .4772 Example:   P(0 < z < 2.00) = .4772
The Standard Normal Table ,[object Object],.4772 2.0 P(0 < z < 2.00) =  .4772 The  row  shows the value of z to the first decimal point The  column   gives the value of z to the second decimal point 2.0 . . . (continued)
General Procedure for Finding Probabilities ,[object Object],[object Object],[object Object],[object Object],To find  P(a < x < b)  when  x  is distributed normally:
Z Table example ,[object Object],P(8 < x < 8.6) =  P(0 < z < 0.12) Z 0.12 0 x 8.6 8 Calculate z-values:
Z Table example ,[object Object],P(0 < z < 0.12) z 0.12 0 x 8.6 8 P(8 < x < 8.6) ,[object Object],[object Object],[object Object],[object Object],(continued)
Solution: Finding P(0 < z < 0.12) Z 0.12 z .00 .01 0.0 .0000 .0040 .0080 .0398 .0438 0.2 .0793 .0832 .0871 0.3 .1179 .1217 .1255 .0478 .02 0.1 . 0478 Standard Normal Probability  Table (Portion) 0.00 = P(0 < z < 0.12) P(8 < x < 8.6)
Finding Normal Probabilities ,[object Object],[object Object],Z 8.6 8.0
Finding Normal Probabilities ,[object Object],[object Object],(continued) Z 0.12 .0478 0.00 .5000 P(x < 8.6)  = P(z < 0.12) = P(z < 0) + P(0 < z < 0.12) = .5 + .0478 =  .5478
Upper Tail Probabilities ,[object Object],[object Object],Z 8.6 8.0
[object Object],Upper Tail Probabilities (continued) Z 0.12 0 Z 0.12 .0478 0 .5000 .50 - .0478 = .4522 P(x > 8.6) = P(z > 0.12) = P(z > 0) - P(0 < z < 0.12) = .5 - .0478 =  .4522
Lower Tail Probabilities ,[object Object],[object Object],Z 7.4 8.0
Lower Tail Probabilities ,[object Object],Z 7.4 8.0 The Normal distribution is symmetric, so we use the same table even if z-values are negative:  P(7.4 < x < 8)  = P(-0.12 < z < 0) =  .0478 (continued) .0478
Normal Probabilities in PHStat ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
PHStat Dialogue Box Select desired options and enter values
PHStat Output
The Uniform Distribution Continuous   Probability Distributions Probability Distributions Normal Uniform Exponential
The Uniform Distribution ,[object Object]
The Uniform Distribution The Continuous Uniform Distribution: where f(x) = value of the density function at any x value a = lower limit of the interval b = upper limit of the interval (continued) f(x) =
Uniform Distribution Example:  Uniform Probability Distribution   Over the range  2 ≤ x ≤ 6: 2 6 .25 f(x) =  = .25  for  2 ≤ x ≤ 6 6 - 2 1 x f(x)
The Exponential Distribution Continuous   Probability Distributions Probability Distributions Normal Uniform Exponential
The Exponential Distribution ,[object Object],[object Object],[object Object],[object Object],[object Object]
The Exponential Distribution ,[object Object],where 1/   is the mean time between events Note that if the  number of occurrences per time period  is Poisson with mean   , then the  time between occurrences  is exponential with mean time 1/  
Exponential Distribution ,[object Object],(continued) f(x) x    = 1.0 (mean = 1.0) ,[object Object],[object Object],   = 3.0 (mean = .333)
Example Example:  Customers arrive at the claims counter at the rate of 15 per hour (Poisson distributed).  What is the probability that the arrival time between consecutive customers is less than five minutes? ,[object Object],[object Object],[object Object]

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Discrete and continuous probability distributions ppt @ bec doms

  • 1. Discrete and Continuous Probability Distributions
  • 2.
  • 3. Probability Distributions Continuous Probability Distributions Binomial Hypergeometric Poisson Probability Distributions Discrete Probability Distributions Normal Uniform Exponential
  • 4.
  • 5.
  • 6. The Binomial Distribution Binomial Hypergeometric Poisson Probability Distributions Discrete Probability Distributions
  • 7.
  • 8.
  • 9.
  • 10. Binomial Distribution Formula P(x) = probability of x successes in n trials, with probability of success p on each trial x = number of ‘successes’ in sample, (x = 0, 1, 2, ..., n ) p = probability of “success” per trial q = probability of “failure” = (1 – p) n = number of trials (sample size) P(x) n x ! n x p q x n x ! ( ) !    Example: Flip a coin four times, let x = # heads: n = 4 p = 0.5 q = (1 - .5) = .5 x = 0, 1, 2, 3, 4
  • 11.
  • 12.
  • 13. Binomial Characteristics n = 5 p = 0.1 n = 5 p = 0.5 Mean 0 .2 .4 .6 0 1 2 3 4 5 X P(X) .2 .4 .6 0 1 2 3 4 5 X P(X) 0 Examples
  • 14. Using Binomial Tables Examples: n = 10, p = .35, x = 3: P(x = 3|n =10, p = .35) = .2522 n = 10, p = .75, x = 2: P(x = 2|n =10, p = .75) = .0004 n = 10 x p=.15 p=.20 p=.25 p=.30 p=.35 p=.40 p=.45 p=.50 0 1 2 3 4 5 6 7 8 9 10 0.1969 0.3474 0.2759 0.1298 0.0401 0.0085 0.0012 0.0001 0.0000 0.0000 0.0000 0.1074 0.2684 0.3020 0.2013 0.0881 0.0264 0.0055 0.0008 0.0001 0.0000 0.0000 0.0563 0.1877 0.2816 0.2503 0.1460 0.0584 0.0162 0.0031 0.0004 0.0000 0.0000 0.0282 0.1211 0.2335 0.2668 0.2001 0.1029 0.0368 0.0090 0.0014 0.0001 0.0000 0.0135 0.0725 0.1757 0.2522 0.2377 0.1536 0.0689 0.0212 0.0043 0.0005 0.0000 0.0060 0.0403 0.1209 0.2150 0.2508 0.2007 0.1115 0.0425 0.0106 0.0016 0.0001 0.0025 0.0207 0.0763 0.1665 0.2384 0.2340 0.1596 0.0746 0.0229 0.0042 0.0003 0.0010 0.0098 0.0439 0.1172 0.2051 0.2461 0.2051 0.1172 0.0439 0.0098 0.0010 10 9 8 7 6 5 4 3 2 1 0 p=.85 p=.80 p=.75 p=.70 p=.65 p=.60 p=.55 p=.50 x
  • 15.
  • 16.
  • 17. PHStat Output P(x = 3 | n = 10, p = .35) = .2522 P(x > 5 | n = 10, p = .35) = .0949
  • 18. The Poisson Distribution Binomial Hypergeometric Poisson Probability Distributions Discrete Probability Distributions
  • 19.
  • 20. Poisson Distribution Formula where: t = size of the segment of interest x = number of successes in segment of interest  = expected number of successes in a segment of unit size e = base of the natural logarithm system (2.71828...)
  • 21.
  • 22. Using Poisson Tables Example: Find P(x = 2) if  = .05 and t = 100 X  t 0.10 0.20 0.30 0.40 0.50 0.60 0.70 0.80 0.90 0 1 2 3 4 5 6 7 0.9048 0.0905 0.0045 0.0002 0.0000 0.0000 0.0000 0.0000 0.8187 0.1637 0.0164 0.0011 0.0001 0.0000 0.0000 0.0000 0.7408 0.2222 0.0333 0.0033 0.0003 0.0000 0.0000 0.0000 0.6703 0.2681 0.0536 0.0072 0.0007 0.0001 0.0000 0.0000 0.6065 0.3033 0.0758 0.0126 0.0016 0.0002 0.0000 0.0000 0.5488 0.3293 0.0988 0.0198 0.0030 0.0004 0.0000 0.0000 0.4966 0.3476 0.1217 0.0284 0.0050 0.0007 0.0001 0.0000 0.4493 0.3595 0.1438 0.0383 0.0077 0.0012 0.0002 0.0000 0.4066 0.3659 0.1647 0.0494 0.0111 0.0020 0.0003 0.0000
  • 23. Graph of Poisson Probabilities P(x = 2) = .0758 Graphically:  = .05 and t = 100 X  t = 0.50 0 1 2 3 4 5 6 7 0.6065 0.3033 0.0758 0.0126 0.0016 0.0002 0.0000 0.0000
  • 24.
  • 25. The Hypergeometric Distribution Binomial Poisson Probability Distributions Discrete Probability Distributions Hypergeometric
  • 26.
  • 27. Hypergeometric Distribution Formula . Where N = Population size X = number of successes in the population n = sample size x = number of successes in the sample n – x = number of failures in the sample (Two possible outcomes per trial)
  • 28.
  • 29.
  • 30.
  • 31. The Normal Distribution Continuous Probability Distributions Probability Distributions Normal Uniform Exponential
  • 32.
  • 33. By varying the parameters μ and σ , we obtain different normal distributions Many Normal Distributions
  • 34. The Normal Distribution Shape x f(x) μ σ Changing μ shifts the distribution left or right . Changing σ increases or decreases the spread.
  • 35. Finding Normal Probabilities Probability is the area under the curve! a b x f(x) P a x b ( )   Probability is measured by the area under the curve
  • 36. Probability as Area Under the Curve f(x) x μ 0.5 0.5 The total area under the curve is 1.0 , and the curve is symmetric, so half is above the mean, half is below
  • 37.
  • 38.
  • 39.
  • 40.
  • 41.
  • 42.
  • 43.
  • 44. Comparing x and z units z 100 3.0 0 250 x Note that the distribution is the same, only the scale has changed. We can express the problem in original units (x) or in standardized units (z) μ = 100 σ = 50
  • 45.
  • 46.
  • 47.
  • 48.
  • 49.
  • 50. Solution: Finding P(0 < z < 0.12) Z 0.12 z .00 .01 0.0 .0000 .0040 .0080 .0398 .0438 0.2 .0793 .0832 .0871 0.3 .1179 .1217 .1255 .0478 .02 0.1 . 0478 Standard Normal Probability Table (Portion) 0.00 = P(0 < z < 0.12) P(8 < x < 8.6)
  • 51.
  • 52.
  • 53.
  • 54.
  • 55.
  • 56.
  • 57.
  • 58. PHStat Dialogue Box Select desired options and enter values
  • 60. The Uniform Distribution Continuous Probability Distributions Probability Distributions Normal Uniform Exponential
  • 61.
  • 62. The Uniform Distribution The Continuous Uniform Distribution: where f(x) = value of the density function at any x value a = lower limit of the interval b = upper limit of the interval (continued) f(x) =
  • 63. Uniform Distribution Example: Uniform Probability Distribution Over the range 2 ≤ x ≤ 6: 2 6 .25 f(x) = = .25 for 2 ≤ x ≤ 6 6 - 2 1 x f(x)
  • 64. The Exponential Distribution Continuous Probability Distributions Probability Distributions Normal Uniform Exponential
  • 65.
  • 66.
  • 67.
  • 68.