SlideShare uma empresa Scribd logo
1 de 38
Differentiation
(DIFFERENTIATION OF ALGEBRAIC EXPRESSION,
THEOREMS OF DIFFERENTIATION,
CHAIN RULE)
REVIEW
• Consider the graph below:
A secant line is a straight line
joining two points on a
function.
A tangent line is a straight
line that touches a function at
only one point.
Secant Line. It is also
equivalent to the average rate
of change, or simply the slope
between two points.
REVIEW
• .
• The tangent line represents the
instantaneous rate of change of the
function at that one point.
• The slope of the tangent line at a point
on the function is equal to the derivative
of the function at the same point.
Ave speed= 100m/9.58s
=10.43 m/s
What is the speed of Bolt at 4 s?
Derivative comes in!
INTRODUCTION
• Consider the graph of a function 𝑓 and a point 𝑃 = (𝑎, 𝑓 𝑎 ) on the graph.
Tangent line
INTRODUCTION
• Let 𝑡 be an arbitrary nonzero real number, and consider the point 𝑄 𝑡 = 𝑎 + 𝑡, 𝑓 𝑎 + 𝑡 ,
which, together with 𝑃 = 𝑎, 𝑓 𝑎 , lies on the graph of 𝑓.
The slope of the secant line 𝐿1 containing 𝑃
and 𝑄 𝑡 is equal to
𝑚 𝑃, 𝑄 𝑡 =
𝑓 𝑎 + 𝑡 − 𝑓(𝑎)
𝑎 + 𝑡 − 𝑎
,
𝑚 𝑃, 𝑄 𝑡 =
𝑓 𝑎 + 𝑡 − 𝑓(𝑎)
𝑡
.
We would like to define the tangent line 𝐿 to
be the limit, as 𝑡 approaches zero, of the
line 𝐿𝑡.
Hence we can express the limit of the slope
of 𝐿𝑡 which is
𝑚 𝑃, 𝑄 𝑡 = lim
𝑡→𝑎
𝑓 𝑎+𝑡 −𝑓 𝑎
𝑡
.
TANGENT LINE
• An arbitrary real-valued function 𝑓 of a real variable is differentiable at a number 𝑎 in its
domain if
lim
𝑡→𝑎
𝑓 𝑎 + 𝑡 − 𝑓(𝑎)
𝑡
exist (i.e.., is finite).
The derivative of 𝑓 at 𝑎, denoted 𝑓′
𝑎 , is this limit. Thus
𝒇′ 𝒂 = 𝒍𝒊𝒎
𝒕→𝒂
𝒇 𝒂+𝒕 −𝒇(𝒂)
𝒕
.
𝑓′
𝑥 = lim
𝑡→0
2𝑥𝑡 + 𝑡2
𝑡
𝑓′ 𝑥 = lim
𝑡→0
𝑡(2𝑥 + 𝑡
𝑡
𝑓′ 𝑥 = lim
𝑡→0
2𝑥 + 𝑡
𝑓′ 𝑥 = 2𝑥 ∎
The derivative of 𝑓 𝑥 = 𝑥2 is 𝑓′ 𝑥 = 2𝑥 .
Example
1. Find the derivative of 𝑓 𝑥 = 𝑥2.
Solution:
Write the derivative formula
𝑓′ 𝑥 = lim
𝑡→0
𝑓(𝑥 + 𝑡)2
−𝑓(𝑥)
𝑡
Plug the function to the definition of
derivative. and do some algebra operations
𝑓′ 𝑥 = lim
𝑡→0
(𝑥 + 𝑡)2−𝑥2
𝑡
𝑓′ 𝑥 = lim
𝑡→0
𝑥2 + 2𝑥𝑡 + 𝑡2 − 𝑥2
𝑡
• Some other books are using Δ for the formula of slope (
𝛥𝑦
𝛥𝑥
).
Here we will be using
𝑑
𝑑𝑥
, which reads as “ the derivative of” and 𝑓′(𝑥) which reads as
“f prime of x”.
Example,
𝑑
𝑑𝑥
𝑥2 = 2𝑥.
"The derivative of x2 equals 2x"
or simply "d dx of x2 equals 2x“.
Solution:
Let h be the arbitrary nonzero number
𝑓′ 𝑥 = lim
ℎ→0
𝑓(𝑥 + ℎ)2
−𝑓(𝑥)
ℎ
𝑓′
𝑥 = lim
ℎ→0
2(𝑥 + ℎ)2
−16 𝑥 + ℎ + 35 − (2𝑥2
− 16𝑥 + 35)
ℎ
𝑓′
𝑥 = lim
ℎ→0
2(𝑥2
+2𝑥ℎ + ℎ2
) − 16 𝑥 + ℎ + 35 − (2𝑥2
− 16𝑥 + 35)
ℎ
𝑓′
𝑥 = lim
ℎ→0
2𝑥2 + 4𝑥ℎ + 2ℎ2 − 16𝑥 − 16ℎ + 35 − 2𝑥2 + 16𝑥 − 35)
ℎ
𝑓′ 𝑥 = lim
ℎ→0
2𝑥2
− 2𝑥2
+ 4𝑥ℎ + 2ℎ2
− 16𝑥 + 16𝑥 − 16ℎ + 35 − 35)
ℎ
𝑓′ 𝑥 = lim
ℎ→0
4𝑥ℎ + 2ℎ2
− 16ℎ
ℎ
𝑓′ 𝑥 = lim
ℎ→0
ℎ(4𝑥 + 2ℎ − 16)
ℎ
𝑓′ 𝑥 = lim
ℎ→0
4𝑥 + 2ℎ − 16
𝑓′
𝑥 = 4𝑥 − 16 ∎
POWER RULE
POWER RULE
THEOREMS ON DIFFERENTIATION
THEOREMS ON DIFFERENTIATION
Calculate
𝑑𝑦
𝑑𝑥
2x3 − 4x2 3x5 + x2 .
You can solve using power rule or using the product rule.
Using Product Rule:
=
𝑑
𝑑𝑥
2x3 − 4x2 3x5 + x2 + 2x3 − 4x2 [
𝑑
𝑑𝑥
3x5 + x2 ]
= (6𝑥2 − 8𝑥) 3x5 + x2 + 2x3 − 4x2 15x4 + 2x
= 18𝑥7
+ 6𝑥4
− 24𝑥6
− 8𝑥3
+ 30𝑥7
+ 4𝑥4
− 60𝑥6
− 8𝑥3
= 48𝑥7 − 84𝑥6 + 8𝑥4 − 16𝑥3 ∎
Using Power Rule:
=
𝑑
𝑑𝑥
(6𝑥8 + 2𝑥5 − 12𝑥7 − 4𝑥4
=
𝑑
𝑑𝑥
6𝑥8 +
𝑑
𝑑𝑥
2𝑥5 −
𝑑
𝑑𝑥
12𝑥7 −
𝑑
𝑑𝑥
4𝑥4
= 48𝑥7 − 84𝑥6 + 8𝑥4 − 16𝑥3 ∎
and
Differentiation

Mais conteúdo relacionado

Mais procurados

Solving radical equations
Solving radical equationsSolving radical equations
Solving radical equations
DaisyListening
 
Linear function and slopes of a line
Linear function and slopes of a lineLinear function and slopes of a line
Linear function and slopes of a line
Jerlyn Fernandez
 
February 17 2015
February 17 2015February 17 2015
February 17 2015
khyps13
 
Linear Equations Ppt
Linear Equations PptLinear Equations Ppt
Linear Equations Ppt
Scott R
 
Graphing a line using Slope-Intercept form
Graphing a line using Slope-Intercept formGraphing a line using Slope-Intercept form
Graphing a line using Slope-Intercept form
shepieces
 
Graphing linear equations
Graphing linear equationsGraphing linear equations
Graphing linear equations
Terry Gastauer
 

Mais procurados (20)

Solving radical equations
Solving radical equationsSolving radical equations
Solving radical equations
 
Module9 the pearson correlation
Module9 the pearson correlationModule9 the pearson correlation
Module9 the pearson correlation
 
Linear function and slopes of a line
Linear function and slopes of a lineLinear function and slopes of a line
Linear function and slopes of a line
 
February 17 2015
February 17 2015February 17 2015
February 17 2015
 
Slope of a Line
Slope of a LineSlope of a Line
Slope of a Line
 
Tugas Aljabar Linear
Tugas Aljabar LinearTugas Aljabar Linear
Tugas Aljabar Linear
 
Lesson 7 antidifferentiation generalized power formula-simple substitution
Lesson 7 antidifferentiation generalized power formula-simple substitutionLesson 7 antidifferentiation generalized power formula-simple substitution
Lesson 7 antidifferentiation generalized power formula-simple substitution
 
Linear Equations Ppt
Linear Equations PptLinear Equations Ppt
Linear Equations Ppt
 
2.4 Linear Functions
2.4 Linear Functions2.4 Linear Functions
2.4 Linear Functions
 
Ch 5-integration-part-1
Ch 5-integration-part-1Ch 5-integration-part-1
Ch 5-integration-part-1
 
Linear Equation In one variable class 7
 Linear Equation In one variable class 7 Linear Equation In one variable class 7
Linear Equation In one variable class 7
 
K to 12 math
K to 12 mathK to 12 math
K to 12 math
 
Principle of Least Square, its Properties, Regression line and standard error...
Principle of Least Square, its Properties, Regression line and standard error...Principle of Least Square, its Properties, Regression line and standard error...
Principle of Least Square, its Properties, Regression line and standard error...
 
Mohammad shoaib babar
Mohammad shoaib babarMohammad shoaib babar
Mohammad shoaib babar
 
Graphing a line using Slope-Intercept form
Graphing a line using Slope-Intercept formGraphing a line using Slope-Intercept form
Graphing a line using Slope-Intercept form
 
Concurrent force system
Concurrent force systemConcurrent force system
Concurrent force system
 
Analytical geometry slides
Analytical geometry slidesAnalytical geometry slides
Analytical geometry slides
 
Graphing linear equations
Graphing linear equationsGraphing linear equations
Graphing linear equations
 
Graphing linear equations
Graphing linear equationsGraphing linear equations
Graphing linear equations
 
Power series
Power seriesPower series
Power series
 

Semelhante a Differentiation

Engineering Analysis -Third Class.ppsx
Engineering Analysis -Third Class.ppsxEngineering Analysis -Third Class.ppsx
Engineering Analysis -Third Class.ppsx
HebaEng
 
4. Integral Calculus for gcse and other exams.pptx
4. Integral Calculus for gcse and other exams.pptx4. Integral Calculus for gcse and other exams.pptx
4. Integral Calculus for gcse and other exams.pptx
Happy Ladher
 

Semelhante a Differentiation (20)

Slope of the Tangent Line.pptx
Slope of the Tangent Line.pptxSlope of the Tangent Line.pptx
Slope of the Tangent Line.pptx
 
Engineering Analysis -Third Class.ppsx
Engineering Analysis -Third Class.ppsxEngineering Analysis -Third Class.ppsx
Engineering Analysis -Third Class.ppsx
 
Basic calculus (ii) recap
Basic calculus (ii) recapBasic calculus (ii) recap
Basic calculus (ii) recap
 
2 random variables notes 2p3
2 random variables notes 2p32 random variables notes 2p3
2 random variables notes 2p3
 
Linear regression, costs & gradient descent
Linear regression, costs & gradient descentLinear regression, costs & gradient descent
Linear regression, costs & gradient descent
 
Optimum Engineering Design - Day 2b. Classical Optimization methods
Optimum Engineering Design - Day 2b. Classical Optimization methodsOptimum Engineering Design - Day 2b. Classical Optimization methods
Optimum Engineering Design - Day 2b. Classical Optimization methods
 
Taller grupal parcial ii nrc 3246 sebastian fueltala_kevin sánchez
Taller grupal parcial ii nrc 3246  sebastian fueltala_kevin sánchezTaller grupal parcial ii nrc 3246  sebastian fueltala_kevin sánchez
Taller grupal parcial ii nrc 3246 sebastian fueltala_kevin sánchez
 
DIFFERENTAL CALCULUS DERIVATIVES FIRST PART
DIFFERENTAL CALCULUS DERIVATIVES FIRST PARTDIFFERENTAL CALCULUS DERIVATIVES FIRST PART
DIFFERENTAL CALCULUS DERIVATIVES FIRST PART
 
4. Integral Calculus for gcse and other exams.pptx
4. Integral Calculus for gcse and other exams.pptx4. Integral Calculus for gcse and other exams.pptx
4. Integral Calculus for gcse and other exams.pptx
 
Applied Algorithms and Structures week999
Applied Algorithms and Structures week999Applied Algorithms and Structures week999
Applied Algorithms and Structures week999
 
Laplace Transform and its applications
Laplace Transform and its applicationsLaplace Transform and its applications
Laplace Transform and its applications
 
Quadratic Function.pptx
Quadratic Function.pptxQuadratic Function.pptx
Quadratic Function.pptx
 
Basic calculus (i)
Basic calculus (i)Basic calculus (i)
Basic calculus (i)
 
Simple Linear Regression
Simple Linear RegressionSimple Linear Regression
Simple Linear Regression
 
Rational function 11
Rational function 11Rational function 11
Rational function 11
 
Differentiation
DifferentiationDifferentiation
Differentiation
 
Differential Calculus- differentiation
Differential Calculus- differentiationDifferential Calculus- differentiation
Differential Calculus- differentiation
 
Límites
LímitesLímites
Límites
 
MT102 Лекц 8
MT102 Лекц 8MT102 Лекц 8
MT102 Лекц 8
 
Lecture_10_SVD.pptx
Lecture_10_SVD.pptxLecture_10_SVD.pptx
Lecture_10_SVD.pptx
 

Mais de EFREN ARCHIDE

Mais de EFREN ARCHIDE (20)

Problem Solving with Patterns
Problem Solving with PatternsProblem Solving with Patterns
Problem Solving with Patterns
 
Introduction to Modular Arithmetic
Introduction to  Modular ArithmeticIntroduction to  Modular Arithmetic
Introduction to Modular Arithmetic
 
Polya's Problem - Solving Strategy
Polya's Problem - Solving StrategyPolya's Problem - Solving Strategy
Polya's Problem - Solving Strategy
 
Linear programming: A Geometric Approach
Linear programming: A Geometric ApproachLinear programming: A Geometric Approach
Linear programming: A Geometric Approach
 
Article 1 to 26 of the Family Code of the Philippines
Article 1 to 26 of the Family Code of the PhilippinesArticle 1 to 26 of the Family Code of the Philippines
Article 1 to 26 of the Family Code of the Philippines
 
Title XII. – CARE AND EDUCATION OF CHILDREN
Title XII. – CARE AND EDUCATION OF CHILDRENTitle XII. – CARE AND EDUCATION OF CHILDREN
Title XII. – CARE AND EDUCATION OF CHILDREN
 
Title X. – FUNERALS
Title X. – FUNERALSTitle X. – FUNERALS
Title X. – FUNERALS
 
Title XVI. – CIVIL REGISTER
Title XVI.   – CIVIL REGISTERTitle XVI.   – CIVIL REGISTER
Title XVI. – CIVIL REGISTER
 
Title XIV - Absence
Title XIV - AbsenceTitle XIV - Absence
Title XIV - Absence
 
Title XIII. USE OF SURNAMES
Title XIII.   USE OF SURNAMESTitle XIII.   USE OF SURNAMES
Title XIII. USE OF SURNAMES
 
Title II. – CITIZENSHIP* AND DOMICILE
Title II. – CITIZENSHIP* AND DOMICILETitle II. – CITIZENSHIP* AND DOMICILE
Title II. – CITIZENSHIP* AND DOMICILE
 
Article 37 to 47 - Persons - Civil Code of the Philippines
Article 37 to 47 - Persons - Civil Code of the PhilippinesArticle 37 to 47 - Persons - Civil Code of the Philippines
Article 37 to 47 - Persons - Civil Code of the Philippines
 
Article 19 to 36 of the civil code of the philippines (human relations)
Article 19 to 36 of the civil code of the philippines (human relations)Article 19 to 36 of the civil code of the philippines (human relations)
Article 19 to 36 of the civil code of the philippines (human relations)
 
Article 1 to 18 - Civil Code of the Philippines
Article 1 to 18 - Civil Code of the PhilippinesArticle 1 to 18 - Civil Code of the Philippines
Article 1 to 18 - Civil Code of the Philippines
 
Evaluating functions
Evaluating functionsEvaluating functions
Evaluating functions
 
Sample
SampleSample
Sample
 
Proposition (Logic)
Proposition (Logic)Proposition (Logic)
Proposition (Logic)
 
Polya's Problem-Solving Strategy
Polya's Problem-Solving StrategyPolya's Problem-Solving Strategy
Polya's Problem-Solving Strategy
 
Expository Teaching
Expository TeachingExpository Teaching
Expository Teaching
 
The Inverse of a Matrix
The Inverse of a Matrix  The Inverse of a Matrix
The Inverse of a Matrix
 

Último

The basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptxThe basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptx
heathfieldcps1
 
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
kauryashika82
 

Último (20)

2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
 
Measures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SDMeasures of Dispersion and Variability: Range, QD, AD and SD
Measures of Dispersion and Variability: Range, QD, AD and SD
 
Application orientated numerical on hev.ppt
Application orientated numerical on hev.pptApplication orientated numerical on hev.ppt
Application orientated numerical on hev.ppt
 
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
Presentation by Andreas Schleicher Tackling the School Absenteeism Crisis 30 ...
 
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
Basic Civil Engineering first year Notes- Chapter 4 Building.pptxBasic Civil Engineering first year Notes- Chapter 4 Building.pptx
Basic Civil Engineering first year Notes- Chapter 4 Building.pptx
 
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
 
Energy Resources. ( B. Pharmacy, 1st Year, Sem-II) Natural Resources
Energy Resources. ( B. Pharmacy, 1st Year, Sem-II) Natural ResourcesEnergy Resources. ( B. Pharmacy, 1st Year, Sem-II) Natural Resources
Energy Resources. ( B. Pharmacy, 1st Year, Sem-II) Natural Resources
 
Unit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptxUnit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptx
 
ICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptxICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptx
 
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptxINDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
INDIA QUIZ 2024 RLAC DELHI UNIVERSITY.pptx
 
The basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptxThe basics of sentences session 2pptx copy.pptx
The basics of sentences session 2pptx copy.pptx
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104
 
Unit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptxUnit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptx
 
Micro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdfMicro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdf
 
Advanced Views - Calendar View in Odoo 17
Advanced Views - Calendar View in Odoo 17Advanced Views - Calendar View in Odoo 17
Advanced Views - Calendar View in Odoo 17
 
microwave assisted reaction. General introduction
microwave assisted reaction. General introductionmicrowave assisted reaction. General introduction
microwave assisted reaction. General introduction
 
Role Of Transgenic Animal In Target Validation-1.pptx
Role Of Transgenic Animal In Target Validation-1.pptxRole Of Transgenic Animal In Target Validation-1.pptx
Role Of Transgenic Animal In Target Validation-1.pptx
 
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
Ecological Succession. ( ECOSYSTEM, B. Pharmacy, 1st Year, Sem-II, Environmen...
 
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
 

Differentiation

  • 1. Differentiation (DIFFERENTIATION OF ALGEBRAIC EXPRESSION, THEOREMS OF DIFFERENTIATION, CHAIN RULE)
  • 2. REVIEW • Consider the graph below: A secant line is a straight line joining two points on a function. A tangent line is a straight line that touches a function at only one point. Secant Line. It is also equivalent to the average rate of change, or simply the slope between two points.
  • 3. REVIEW • . • The tangent line represents the instantaneous rate of change of the function at that one point. • The slope of the tangent line at a point on the function is equal to the derivative of the function at the same point.
  • 4. Ave speed= 100m/9.58s =10.43 m/s What is the speed of Bolt at 4 s? Derivative comes in!
  • 5.
  • 6.
  • 7. INTRODUCTION • Consider the graph of a function 𝑓 and a point 𝑃 = (𝑎, 𝑓 𝑎 ) on the graph. Tangent line
  • 8. INTRODUCTION • Let 𝑡 be an arbitrary nonzero real number, and consider the point 𝑄 𝑡 = 𝑎 + 𝑡, 𝑓 𝑎 + 𝑡 , which, together with 𝑃 = 𝑎, 𝑓 𝑎 , lies on the graph of 𝑓. The slope of the secant line 𝐿1 containing 𝑃 and 𝑄 𝑡 is equal to 𝑚 𝑃, 𝑄 𝑡 = 𝑓 𝑎 + 𝑡 − 𝑓(𝑎) 𝑎 + 𝑡 − 𝑎 , 𝑚 𝑃, 𝑄 𝑡 = 𝑓 𝑎 + 𝑡 − 𝑓(𝑎) 𝑡 . We would like to define the tangent line 𝐿 to be the limit, as 𝑡 approaches zero, of the line 𝐿𝑡. Hence we can express the limit of the slope of 𝐿𝑡 which is 𝑚 𝑃, 𝑄 𝑡 = lim 𝑡→𝑎 𝑓 𝑎+𝑡 −𝑓 𝑎 𝑡 .
  • 9. TANGENT LINE • An arbitrary real-valued function 𝑓 of a real variable is differentiable at a number 𝑎 in its domain if lim 𝑡→𝑎 𝑓 𝑎 + 𝑡 − 𝑓(𝑎) 𝑡 exist (i.e.., is finite). The derivative of 𝑓 at 𝑎, denoted 𝑓′ 𝑎 , is this limit. Thus 𝒇′ 𝒂 = 𝒍𝒊𝒎 𝒕→𝒂 𝒇 𝒂+𝒕 −𝒇(𝒂) 𝒕 .
  • 10. 𝑓′ 𝑥 = lim 𝑡→0 2𝑥𝑡 + 𝑡2 𝑡 𝑓′ 𝑥 = lim 𝑡→0 𝑡(2𝑥 + 𝑡 𝑡 𝑓′ 𝑥 = lim 𝑡→0 2𝑥 + 𝑡 𝑓′ 𝑥 = 2𝑥 ∎ The derivative of 𝑓 𝑥 = 𝑥2 is 𝑓′ 𝑥 = 2𝑥 . Example 1. Find the derivative of 𝑓 𝑥 = 𝑥2. Solution: Write the derivative formula 𝑓′ 𝑥 = lim 𝑡→0 𝑓(𝑥 + 𝑡)2 −𝑓(𝑥) 𝑡 Plug the function to the definition of derivative. and do some algebra operations 𝑓′ 𝑥 = lim 𝑡→0 (𝑥 + 𝑡)2−𝑥2 𝑡 𝑓′ 𝑥 = lim 𝑡→0 𝑥2 + 2𝑥𝑡 + 𝑡2 − 𝑥2 𝑡
  • 11. • Some other books are using Δ for the formula of slope ( 𝛥𝑦 𝛥𝑥 ). Here we will be using 𝑑 𝑑𝑥 , which reads as “ the derivative of” and 𝑓′(𝑥) which reads as “f prime of x”. Example, 𝑑 𝑑𝑥 𝑥2 = 2𝑥. "The derivative of x2 equals 2x" or simply "d dx of x2 equals 2x“.
  • 12.
  • 13. Solution: Let h be the arbitrary nonzero number 𝑓′ 𝑥 = lim ℎ→0 𝑓(𝑥 + ℎ)2 −𝑓(𝑥) ℎ 𝑓′ 𝑥 = lim ℎ→0 2(𝑥 + ℎ)2 −16 𝑥 + ℎ + 35 − (2𝑥2 − 16𝑥 + 35) ℎ 𝑓′ 𝑥 = lim ℎ→0 2(𝑥2 +2𝑥ℎ + ℎ2 ) − 16 𝑥 + ℎ + 35 − (2𝑥2 − 16𝑥 + 35) ℎ 𝑓′ 𝑥 = lim ℎ→0 2𝑥2 + 4𝑥ℎ + 2ℎ2 − 16𝑥 − 16ℎ + 35 − 2𝑥2 + 16𝑥 − 35) ℎ 𝑓′ 𝑥 = lim ℎ→0 2𝑥2 − 2𝑥2 + 4𝑥ℎ + 2ℎ2 − 16𝑥 + 16𝑥 − 16ℎ + 35 − 35) ℎ 𝑓′ 𝑥 = lim ℎ→0 4𝑥ℎ + 2ℎ2 − 16ℎ ℎ 𝑓′ 𝑥 = lim ℎ→0 ℎ(4𝑥 + 2ℎ − 16) ℎ 𝑓′ 𝑥 = lim ℎ→0 4𝑥 + 2ℎ − 16 𝑓′ 𝑥 = 4𝑥 − 16 ∎
  • 14.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 23.
  • 24.
  • 26.
  • 27.
  • 28. Calculate 𝑑𝑦 𝑑𝑥 2x3 − 4x2 3x5 + x2 . You can solve using power rule or using the product rule. Using Product Rule: = 𝑑 𝑑𝑥 2x3 − 4x2 3x5 + x2 + 2x3 − 4x2 [ 𝑑 𝑑𝑥 3x5 + x2 ] = (6𝑥2 − 8𝑥) 3x5 + x2 + 2x3 − 4x2 15x4 + 2x = 18𝑥7 + 6𝑥4 − 24𝑥6 − 8𝑥3 + 30𝑥7 + 4𝑥4 − 60𝑥6 − 8𝑥3 = 48𝑥7 − 84𝑥6 + 8𝑥4 − 16𝑥3 ∎ Using Power Rule: = 𝑑 𝑑𝑥 (6𝑥8 + 2𝑥5 − 12𝑥7 − 4𝑥4 = 𝑑 𝑑𝑥 6𝑥8 + 𝑑 𝑑𝑥 2𝑥5 − 𝑑 𝑑𝑥 12𝑥7 − 𝑑 𝑑𝑥 4𝑥4 = 48𝑥7 − 84𝑥6 + 8𝑥4 − 16𝑥3 ∎
  • 29.
  • 30.
  • 31.
  • 32.
  • 33.
  • 34.
  • 35.
  • 36.
  • 37. and