Math question Let A be a matrix such that A^2 = I where I is the identity matrix, Show that e^At = cosh(t)I + sinh(t) A. (Hint: use identities cos h(t) = cos(it) and sinh(t) = -isin(it) and the power series expansion of cosh(t) and sinh(t)). Solution cosht = cos (it) sinht = -isinit Hence coshtI + sinhtA = cos(it)I -isin(it) A = cos it (A2) - i sin (it) A = A(cosit-sin itA) = eAt.