1. English : 1 Set : 01 Hindi : 1 Set : 01
PART A — PHYSICS
1. An experiment is performed to obtain the
value of acceleration due to gravity g by
using a simple pendulum of length L. In
this experiment time for 100 oscillations is
measured by using a watch of 1 second
least count and the value is 90.0 seconds.
The length L is measured by using a meter
scale of least count 1 mm and the value is
20.0 cm. The error in the determination
of g would be :
(1) 1.7%
(2) 2.7%
(3) 4.4%
(4) 2.27%
2. The position of a projectile launched from
the origin at t50 is given by
r (40 50 ) mi j
→ ∧ ∧
5 1 at t52s. If the
projectile was launched at an angle u from
the horizontal, then u is (take g510 ms22).
(1) tan21 2
3
(2) tan21 3
2
(3) tan21 7
4
(4) tan21 4
5
Öæ» A — ÖæñçÌ·¤ çß™ææÙ
1. ÜÕæ§ü L ·ð¤ °·¤ âÚUÜ ÜæðÜ·¤ ·¤æ ÂýØæð» ·¤ÚU »éL¤ˆßèØ
ˆßÚU‡æ g ·¤æ ×æÙ çÙ·¤æÜÙð ·¤æ °·¤ ÂýØæð» ç·¤Øæ ÁæÌæ
ãñÐ §â ÂýØæð» ×ð´ 100 ÎæðÜÙæð´ ·¤æ â×Ø 1 âð·´¤ÇUU
¥ËÂÌ×æ¡·¤ ßæÜè ƒæǸUè âð ×æÂæ ÁæÌæ ãñ ¥æñÚ ×æÙ
90.0 âð·´¤ÇU ãñÐ ÜÕæ§ü L 1 mm ¥ËÂÌ×æ¡·¤ ßæÜð
×èÅUÚU Âñ×æÙð âð ×æÂè ÁæÌè ãñ ¥æñÚU §â·¤æ ×æÙ
20.0 cm ãñÐ g ·ð¤ ×æÙ ·ð¤ çÙÏüæÚU‡æ ×ð´ ˜æéçÅU ãæð»è Ñ
(1) 1.7%
(2) 2.7%
(3) 4.4%
(4) 2.27%
2. ×êÜ çÕ‹Îé âð t50 ÂÚU ÂýÿæðçÂÌ °·¤ Âýÿæð ·¤è çSÍçÌ
t52s ÂÚU r (40 50 ) mi j
→ ∧ ∧
5 1 âð Îè ÁæÌè ãñÐ
ØçÎ Âýÿæð ÿæñçÌÁ âð u ·¤æð‡æ ÂÚU ÂýÿæðçÂÌ ç·¤Øæ »Øæ
Íæ, ÌÕ u ãñ (g510 ms22 Üð´).
(1) tan21 2
3
(2) tan21 3
2
(3) tan21 7
4
(4) tan21 4
5
2. English : 2 Set : 01 Hindi : 2 Set : 01
3. Water is flowing at a speed of 1.5 ms21
through a horizontal tube of
cross-sectional area 1022 m2 and you are
trying to stop the flow by your palm.
Assuming that the water stops
immediately after hitting the palm, the
minimum force that you must exert should
be (density of water5103 kgm23).
(1) 15 N
(2) 22.5 N
(3) 33.7 N
(4) 45 N
4. A block A of mass 4 kg is placed on
another block B of mass 5 kg, and the block
B rests on a smooth horizontal table. If
the minimum force that can be applied on
A so that both the blocks move together is
12 N, the maximum force that can be
applied on B for the blocks to move
together will be :
(1) 30 N
(2) 25 N
(3) 27 N
(4) 48 N
3. 1022 m2 ·ð¤ ¥ÙéÂýSÍ ·¤æÅU ßæÜè ÿæñçÌÁ ÙÜè âð
1.5 ms21 ·¤è »çÌ âð ÂæÙè ÂýßæçãÌ ãæð ÚUãæ ãñ ¥æñÚU
¥æ ¥ÂÙè ãÍðÜè âð Õãæß ·¤æð ÚUæð·¤Ùð ·¤æ ÂýØæâ ·¤ÚU
ÚUãð ãñ´Ð Øã ×æÙÌð ãéØð ç·¤ ÂæÙè ãÍðÜè âð ÅU·¤ÚUæÌð ãè
L¤·¤ ÁæÌæ ãñ, ¥æ·¤æð ¥ÂÙè ãÍðÜè âð ·¤× âð ·¤×
§ÌÙæ ÕÜ Ü»æÙæ ÂǸð»æÐ (ÂæÙè ·¤æ
ƒæÙˆß5103 kgm23).
(1) 15 N
(2) 22.5 N
(3) 33.7 N
(4) 45 N
4. ÎýÃØ×æÙ 4 kg ·ð¤ °·¤ ŽÜæ·¤ A ·¤æð °·¤ ÎêâÚðU ÎýÃØ×æÙ
5 kg ·ð¤ °·¤ ŽÜæ·¤ B ·ð¤ ª¤ÂÚU ÚU¹æ ãñ ¥æñÚU ŽÜæ·¤ B
°·¤ ç¿·¤Ùè ÿæñçÌÁ ×ðÁ ÂÚU çߟææ× ¥ßSÍæ ×ð´ ÚU¹æ
ãñÐ ØçÎ ŽÜæ·¤ A ÂÚU ßã ‹ØêÙÌ× ÕÜ, çÁââð ç·¤
ÎæðÙæ´ð ŽÜæ·¤ °·¤ âæÍ »çÌàæèÜ ãæð´, 12 N ãñ ÌÕ
ŽÜæ·¤ B ÂÚU Ü»æØæ »Øæ ¥çÏ·¤Ì× ÕÜ, çÁââð ç·¤
ÎæðÙæ´ð ŽÜæ·¤ »çÌàæèÜ ãæð´, ãæð»æ Ñ
(1) 30 N
(2) 25 N
(3) 27 N
(4) 48 N
3. English : 3 Set : 01 Hindi : 3 Set : 01
5. Two bodies of masses 1 kg and 4 kg are
connected to a vertical spring, as shown
in the figure. The smaller mass executes
simple harmonic motion of angular
frequency 25 rad/s, and amplitude 1.6 cm
while the bigger mass remains stationary
on the ground. The maximum force
exerted by the system on the floor is
(take g510 ms22).
(1) 20 N
(2) 10 N
(3) 60 N
(4) 40 N
5. ÎýÃØ×æÙ 1 kg °ß´ 4 kg ·¤è Îæð ßSÌé°ð´ °·¤ ª¤ŠßæüÏÚU
·¤×æÙè mæÚUæ ç¿˜æ ·ð¤ ¥ÙéâæÚU ÁæðǸUè »Øè ãñ´Ð ¥ËÂÌÚU
ÎýÃØ×æÙ ·¤æð‡æèØ ¥æßëçžæ 25 rad/s °ß´ ¥æØæ×
1.6 cm ·¤è âÚUÜ ¥æßÌü »çÌ ·¤ÚU ÚUãæ ãñ ÁÕç·¤
ÕëãžæÚU ÎýÃØ×æÙ çSÍÚU ÚUãÌæ ãñÐ çÙ·¤æØ mæÚUæ Ȥàæü ÂÚU
Ü»æØæ »Øæ ¥çÏ·¤Ì× ÕÜ ãñ
(g510 ms22 Üð´).
(1) 20 N
(2) 10 N
(3) 60 N
(4) 40 N
5. English : 5 Set : 01 Hindi : 5 Set : 01
7. India’s Mangalyan was sent to the Mars
by launching it into a transfer orbit EOM
around the sun. It leaves the earth at E
and meets Mars at M. If the semi-major
axis of Earth’s orbit is ae51.531011 m,
that of Mar’s orbit am52.2831011 m,
taken Kepler’s laws give the estimate of
time for Mangalyan to reach Mars from
Earth to be close to :
(1) 500 days
(2) 320 days
(3) 260 days
(4) 220 days
7. ÖæÚUÌ ·¤æ ×´»ÜØæÙ ×´»Ü »ýã ·ð¤ çÜØð âêØü ·ð¤ ¿æÚUæð´
¥æðÚU SÍæÙæ‹ÌÚU‡æ ·¤ÿæ EOM ×ð´ ÂýÿæðçÂÌ ç·¤Øæ »ØæÐ
§âÙð Âë‰ßè ·¤æð E ÂÚU ÀUæðÇ¸æ ¥æñÚU ×´»Ü »ýã âð Øã M
ÂÚU ç×ÜÌæ ãñÐ ØçÎ Âë‰ßè ·¤è ¥hü-Îèƒæü ¥ÿæ
ae51.531011 m ãñ ¥æñÚU ×´»Ü »ýã ·¤è ¥hü-Îèƒæü
¥ÿæ am52.2831011 m ãñ, ÌÕ ·ð¤ÂÜÚU ·ð¤ çÙØ×
·ð¤ ¥ÙéâæÚU Âë‰ßè âð ×´»Ü»ýã Ì·¤ ×´»ÜØæÙ ·ð¤ Âãé¡¿Ùð
·¤æ â×Ø Ü»Ö» ãæð»æ Ñ
(1) 500 çÎÙ
(2) 320 çÎÙ
(3) 260 çÎÙ
(4) 220 çÎÙ
6. English : 6 Set : 01 Hindi : 6 Set : 01
8. In materials like aluminium and copper,
the correct order of magnitude of various
elastic modulii is :
(1) Young’s modulii < shear modulii
< bulk modulii.
(2) Bulk modulii < shear modulii
< Young’s modulii.
(3) Shear modulii < Young’s modulii
< bulk modulii.
(4) Bulk modulii < Young’s modulii
< shear modulii.
9. The amplitude of a simple pendulum,
oscillating in air with a small spherical bob,
decreases from 10 cm to 8 cm in 40 seconds.
Assuming that Stokes law is valid, and
ratio of the coefficient of viscosity of air to
that of carbon dioxide is 1.3, the time in
which amplitude of this pendulum will
reduce from 10 cm to 5 cm in
carbondioxide will be close to (ln 551.601,
ln 250.693).
(1) 231 s
(2) 208 s
(3) 161 s
(4) 142 s
8. °ËØéç×çÙØ× °ß´ Ìæ¡Õð Áñâð ÂÎæÍæðü´ ·ð¤ çÜØð çßçÖ‹Ù
ÂýˆØæSÍÌæ »é‡ææ¡·¤æð´ ·ð¤ ÂçÚU×æ‡æ ·¤æ âãè ·ý¤× ãñ Ñ
(1) Ø´» ÂýˆØæSÍÌæ »é‡ææ¡·¤ < ¥ÂM¤Â‡æ ÂýˆØæSÍÌæ
»é‡ææ¡·¤ < ¥æØÌÙ ÂýˆØæSÍÌæ »é‡ææ¡·¤.
(2) ¥æØÌÙ ÂýˆØæSÍÌæ »é‡ææ¡·¤ < ¥ÂM¤Â‡æ
ÂýˆØæSÍÌæ »é‡ææ¡·¤ < Ø´» ÂýˆØæSÍÌæ »é‡ææ¡·¤.
(3) ¥ÂM¤Â‡æ ÂýˆØæSÍÌæ »é‡ææ¡·¤ < Ø´» ÂýˆØæSÍÌæ
»é‡ææ¡·¤ < ¥æØÌÙ ÂýˆØæSÍÌæ »é‡ææ¡·¤.
(4) ¥æØÌÙ ÂýˆØæSÍÌæ »é‡ææ¡·¤ < Ø´» ÂýˆØæSÍÌæ
»é‡ææ¡·¤ < ¥ÂM¤Â‡æ ÂýˆØæSÍÌæ »é‡ææ¡·¤.
9. ßæØé ×ð´ ÎæðÜÙ ·¤ÚU ÚUãð °·¤ ÌÙé »æðÜèØ ÕæÕ ßæÜð âÚUÜ
ÜæðÜ·¤ ·¤æ ¥æØæ× 40 âð·´¤ÇU ×ð´ 10 cm âð 8 cm
Ì·¤ ƒæÅU ÁæÌæ ãñ Ð Øã ×æÙ Üð´ ç·¤ SÅUæð·¤ ·¤æ çÙØ×
âãè ãñ ¥æñÚU ßæØé ·¤æ ·¤æÕüÙ ÇUæ§ü¥æò€âæ§Ç âð àØæÙÌæ
»é‡ææ´·¤ ·¤æ ¥ÙéÂæÌ 1.3 ãñ, ÌÕ ·¤æÕüÙ ÇUæ§ü ¥æò€âæ§ÇU
×ð´ §â ÜæðÜ·¤ ·ð¤ ¥æØæ× ·¤æð 10 cm âð 5 cm Ì·¤
ƒæÅUÙð ×ð´ Ü»æ â×Ø Ü»Ö» ãæð»æ
(ln 551.601, ln 250.693).
(1) 231 s
(2) 208 s
(3) 161 s
(4) 142 s
7. English : 7 Set : 01 Hindi : 7 Set : 01
10. A capillary tube is immersed vertically in
water and the height of the water column
is x. When this arrangement is taken into
a mine of depth d, the height of the water
column is y. If R is the radius of earth, the
ratio
x
y
is :
(1)
d
1
R
2
(2)
2d
1
R
2
(3)
R d
R d
2
1
(4)
R d
R d
1
2
11. Water of volume 2 L in a closed container
is heated with a coil of 1 kW. While water
is heated, the container loses energy at a
rate of 160 J/s. In how much time will the
temperature of water rise from 278C to
778C ? (Specific heat of water is
4.2 kJ/kg and that of the container is
negligible).
(1) 8 min 20 s
(2) 6 min 2 s
(3) 7 min
(4) 14 min
10. °·¤ ·ð¤àæÙçÜ·¤æ ·¤æ𠪤ŠßæüÏÚU ÂæÙè ×ð´ ÇéUÕæðØæ ÁæÌæ ãñ
¥æñÚU ÌÕ ÂæÙè ·ð¤ SÌÖ ·¤è ª¡¤¿æ§ü x ãæð ÁæÌè ãñÐ ÁÕ
§â çß‹Øæâ ·¤æð °·¤ »ãÚUæ§ü d ßæÜè °·¤ ¹æÙ ×ð´ Üð
ÁæØæ ÁæÌæ ãñ, ÌÕ ÂæÙè ·ð¤ SÌÖ ·¤è ª¡¤¿æ§ü y ãñÐ
ØçÎ Âë‰ßè ·¤è ç˜æ’Øæ R ãñ, ÌÕ ¥ÙéÂæÌ x
y
ãñ Ñ
(1)
d
1
R
2
(2)
2d
1
R
2
(3)
R d
R d
2
1
(4)
R d
R d
1
2
11. °·¤ Õ‹Î Âæ˜æ ×ð´ 2 L ¥æØÌÙ ÂæÙè ·¤æð 1 kW ·¤è
·é¤‡ÇUÜè âð »×ü ç·¤Øæ ÁæÌæ ãñÐ ÁÕ ÂæÙè »×ü ãæð ÚUãæ
ãñ, ÌÕ Âæ˜æ 160 J/s ·¤è ÎÚU â𠪤Áæü ·¤æ ÿæØ ·¤ÚU ÚUãæ
ãñÐ ç·¤ÌÙð â×Ø ×ð´ ÂæÙè ·¤æ ÌæÂ×æÙ 278C âð
778C Âãé¡¿ð»æ? (ÂæÙè ·¤è çßçàæcÅU ª¤c×æ
4.2 kJ/kg ãñ ¥æñÚU Âæ˜æ ·¤è çßçàæcÅU ª¤c×æ Ù»‡Ø ãñ)
(1) 8 ç×ÙÅU 20 âð·´¤ÇU
(2) 6 ç×ÙÅU 2 âð·´¤ÇUU
(3) 7 ç×ÙÅU
(4) 14 ç×ÙÅU
8. English : 8 Set : 01 Hindi : 8 Set : 01
12. The equation of state for a gas is given by
PV5nRT1aV, where n is the number of
moles and a is a positive constant. The
initial temperature and pressure of one
mole of the gas contained in a cylinder are
To and Po respectively. The work done by
the gas when its temperature doubles
isobarically will be :
(1)
o o
o
P T R
P 2a
(2) o o
o
P T R
P 1a
(3) Po To R ln 2
(4) Po To R
13. Modern vacuum pumps can evacuate a
vesseldowntoapressureof4.0310215 atm.
at room temperature (300 K). Taking
R58.3 JK21 mole21, 1 atm5105 Pa and
NAvogadro5631023 mole21, the mean
distance between molecules of gas in an
evacuated vessel will be of the order of :
(1) 0.2 mm
(2) 0.2 mm
(3) 0.2 cm
(4) 0.2 nm
12. °·¤ »ñâ ·¤è ¥ßSÍæ ·¤æ â×è·¤ÚU‡æ PV5nRT1aV
âð çÎØæ ÁæÌæ ãñ, Áãæ¡ n ×æðÜ ·¤è â´Øæ ãñ ¥æñÚU a °·¤
ÏÙæˆ×·¤ çSÍÚUæ¡·¤ ãñÐ °·¤ ÕðÜÙ ×ð´ ÚU¹ð »ñ⠷𤠰·¤
×æðÜ ·¤æ ÂýæÚUçÖ·¤ ÌæÂ×æÙ °ß´ ÎæÕ ·ý¤×àæÑ To °ß´
Po ãñÐ ÁÕ §â·¤æ ÌæÂ×æÙ â×ÎæÕ ÂÚU Îæð»éÙæ ãæð
Áæ°ð»æ, ÌÕ »ñâ mæÚUæ ç·¤Øæ »Øæ ·¤æØü ãæð»æ Ñ
(1)
o o
o
P T R
P 2a
(2) o o
o
P T R
P 1a
(3) Po To R ln 2
(4) Po To R
13. ¥æÏéçÙ·¤ çÙßæüÌ Â ·¤×ÚðU ·ð¤ ÌæÂ×æÙ (300 K) ÂÚU
4.0310215 °ÅUU×æSȤèØÚU ÎæÕ Ì·¤ °·¤ ÕÌüÙ ·¤æð
çÙßæüçÌÌ ·¤ÚU â·¤Ìæ ãñÐ R58.3 JK21 ×æðÜ21,
1 °ÅU×æSȤèØÚU5105 ÂæS·¤Ü ¥æñÚU °ßæð»ðÇþUæð â´Øæ
5631023 ×æðÜ21 ÜðÌð ãéØð °·¤ çÙßæüçÌÌ ÕÌüÙ ×ð´
»ñ⠷𤠥‡æé¥æ´ð ·ð¤ Õè¿ ×æŠØ ÎêÚUè ·¤æ ×æ٠ֻܻ
§ÌÙæ ãæð»æ Ñ
(1) 0.2 mm
(2) 0.2 mm
(3) 0.2 cm
(4) 0.2 nm
9. English : 9 Set : 01 Hindi : 9 Set : 01
14. A particle which is simultaneously
subjected to two perpendicular simple
harmonic motions represented by ;
x5a1 cos vt and y5a2 cos 2vt traces a
curve given by :
(1)
(2)
(3)
(4)
14. °·¤ ·¤‡æ, çÁâ ÂÚU °·¤ âæÍ Îæð ÜÕßÌ÷ âÚUÜ ¥æßÌü
»çÌØæ¡ x5a1 cos vt ¥æñÚU y5a2 cos 2vt Ü» ÚUãè
ãñ´, §â ß·ý¤ ·¤æð ÎàææüØð»æ Ñ
(1)
(2)
(3)
(4)
12. English : 12 Set : 01 Hindi : 12 Set : 01
19. The mid points of two small magnetic
dipoles of length d in end-on positions, are
separated by a distance x, (x >> d). The
force between them is proportional to
x2n where n is :
(1) 1
(2) 2
(3) 3
(4) 4
20. The magnetic field of earth at the equator
is approximately 431025 T. The radius
of earth is 6.43106 m. Then the dipole
moment of the earth will be nearly of the
order of :
(1) 1023 A m2
(2) 1020 A m2
(3) 1016 A m2
(4) 1010 A m2
19. ¥ÿæèØ çSÍçÌ ×ð´ ÜÕæ§ü d ·ð¤ Îæð ÌÙé ¿éÕ·¤èØ çmÏéýßæ´ð
·ð¤ ×ŠØ çÕ‹Îé¥æð´ ·¤æð x ÎêÚUè ÂÚU ÚU¹æ »Øæ ãñ (x >>d)Ð
ÎæðÙæð´ ·ð¤ Õè¿ ÕÜ x2n ·¤ð¤ â×æÙéÂæÌè ãñ, Áãæ¡ n ãñ :
(1) 1
(2) 2
(3) 3
(4) 4
20. Öê×ŠØ ÚðU¹æ ÂÚU Âë‰ßè ·ð¤ ¿éÕ·¤èØ ÿæð˜æ ·¤æ
×æ٠ֻܻ 431025 T ãñÐ Âë‰ßè ·¤è ç˜æ’Øæ
6.43106 m ãñÐ ÌÕ Âë‰ßè ·¤æ çmÏýéß ¥æƒæê‡æü ֻܻ
§â ·¤æðçÅU ·¤æ ãæð»æ Ñ
(1) 1023 A m2
(2) 1020 A m2
(3) 1016 A m2
(4) 1010 A m2
13. English : 13 Set : 01 Hindi : 13 Set : 01
21. When the rms voltages VL, VC and VR are
measured respectively across the inductor
L, the capacitor C and the resistor R in a
series LCR circuit connected to an
AC source, it is found that the ratio
VL : VC : VR51 : 2 : 3. If the rms voltage
of the AC source is 100 V, then VR is close
to :
(1) 50 V
(2) 70 V
(3) 90 V
(4) 100 V
21. °·¤ ÂýˆØæßÌèü ÏæÚUæ ŸææðÌ âð ÁéǸð Ÿæð‡æè LCR
ÂçÚUÂÍ ×ð´ ÂýðÚU·¤ˆß L â´ÏæçÚUÌ C ¥æñÚU ÂýçÌÚUæðÏ·¤ R ÂÚU
×æÂð »Øð ß»ü-×æŠØ-×êÜ ßæðËÅUÌæ°ð´ ·ý¤×àæÑ
VL, VC °ß´ VR ãñ´, ÌÕ Øã ÂæØæ ÁæÌæ ãñ ç·¤
VL : VC : VR51 : 2 : 3 Ð ØçÎ ÂýˆØæßÌèü ÏæÚUæ oýæðÌ
·¤è ß»ü-×æŠØ-×êÜ ßæðËÅUÌæ 100 V ãñ´, ÌÕ VR ·¤æ
×æ٠ֻܻ ãñ Ñ
(1) 50 V
(2) 70 V
(3) 90 V
(4) 100 V
14. English : 14 Set : 01 Hindi : 14 Set : 01
22. Match List I (Wavelength range of
electromagnetic spectrum) with List II.
(Method of production of these waves)
and select the correct option from the
options given below the lists.
(a)
700 nm to
1 mm
(i)
Vibration of atoms
and molecules.
(b)
1 nm to
400 nm
(ii)
Inner shell electrons
in atoms moving from
one energy level to a
lower level.
(c) < 1023
nm (iii)
Radioactive decay of
the nucleus.
(d)
1 mm to
0.1 m
(iv) Magnetron valve.
List I List II
(1) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
(2) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
(3) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
(4) (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
22. âê¿è I (çßléÌ ¿éÕ·¤èØ SÂð€ÅþU× ·¤è ÌÚ´U»ÎñŠØü ÚðU‹Á)
·¤æð âê¿è II (§Ù ÌÚ´U»æð´ ·ð¤ çÙ×æü‡æ ·¤è çßçÏ) âð âé×ðçÜÌ
·¤èçÁ°ð ¥æñÚU âê¿è ·ð¤ Ùè¿ð çÎØð »Øð çß·¤ËÂæ´ð ×ð´ âð
âãè çß·¤Ë ¿éçÙ°Ð
(a)
700 nm ÇÕ
1 mm
(i)
ŠøËΊËÕ™ •Ä™ §¿U¼ËøËΊËÕ™ œÕ‰
œ‰ƒ§¾ ÇÕ
(b)
1 nm ÇÕ
400 nm
(ii)
§¿U¼ËøËΊËÕ™ œÕ‰ ŠËü±Ì¿Uœ‰ ÅËÖÁ
ŒÁÕþªãU˾ËÕ™ œ‰Í •œ‰ ‰¦Ëá S±¿U
ÇÕ Ì¾¤ÁÕ S±¿U œ‰Í ̱ ÇÕ
(c) < 1023
nm (iii)
¾ËÌ»œ‰ œÕ‰ ¿ÕU̬U½ËÕ Ç̜≽
ä˽ ÇÕ
(d)
1 mm ÇÕ
0.1 m
(iv) ¼Öó¾ÕªãUˆ¾ ÄË°Ä ÇÕ
ÇÏ¤Í I ÇÏ¤Í II
(1) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
(2) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
(3) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
(4) (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
15. English : 15 Set : 01 Hindi : 15 Set : 01
23. A diver looking up through the water sees
the outside world contained in a circular
horizon. The refractive index of water is
4
3
, and the diver’s eyes are 15 cm below
the surface of water. Then the radius of
the circle is :
(1) 15333 5 cm
(2) 1533 7 cm
(3)
15 7
cm
3
3
(4)
15 3
cm
7
3
23. °·¤ »æðÌæ¹æðÚU ÂæÙè ·ð¤ ¥‹ÎÚU âð ÕæãÚU ·¤è ÎéçÙØæ ·¤æð
°·¤ ßëžæèØ ÿæñçÌÁ ×ð´ çÙçãÌ Îð¹Ìæ ãñÐ ÂæÙè ·¤æ
¥ÂßÌüÙæ¡·¤ 4
3
ãñ ¥æñÚU »æðÌæ¹æðÚU ·¤è ¥æ¡¹ ÂæÙè ·ð¤
ÂëcÆU âð 15 cm Ùè¿ð ãñ´Ð ÌÕ ßëžæ ·¤è ç˜æ’Øæ ãñ Ñ
(1) 15333 5 cm
(2) 1533 7 cm
(3)
15 7
cm
3
3
(4)
15 3
cm
7
3
16. English : 16 Set : 01 Hindi : 16 Set : 01
24. Using monochromatic light of wavelength
l, an experimentalist sets up the Young’s
double slit experiment in three ways as
shown.
If she observes that y5b9, the wavelength
of light used is :
24. ÌÚ´U»ÎñƒØü l ·ð¤ °·¤ß‡æèü Âý·¤æàæ ·ð¤ ÂýØæð» âð °·¤ ßñ™ææçÙ·¤
Ø´» ·ð¤ çmçÀUÎý ÂýØæð» ·¤æð ÎàææüØð »Øð ÌèÙ Âý·¤æÚU âð
ÃØßçSÍÌ ·¤ÚUÌè ãñÐ
ØçÎ ßã ÂæÌè ãñ ç·¤ y5b9, ÌÕ ÂýØæð» ç·¤Øð »Øð
Âý·¤æàæ ·¤è ÌÚ´U»ÎñƒØü ãñ Ñ
17. English : 17 Set : 01 Hindi : 17 Set : 01
(1) 520 nm
(2) 540 nm
(3) 560 nm
(4) 580 nm
25. The focal lengths of objective lens and eye
lens of a Gallelian Telescope are
respectively 30 cm and 3.0 cm. Telescope
produces virtual, erect image of an object
situated far away from it at least distance
of distinct vision from the eye lens. In this
condition, the Magnifying Power of the
Gallelian Telescope should be :
(1) 111.2
(2) 211.2
(3) 28.8
(4) 18.8
26. For which of the following particles will it
be most difficult to experimentally verify
the de-Broglie relationship ?
(1) an electron
(2) a proton
(3) an a-particle
(4) a dust particle
(1) 520 nm
(2) 540 nm
(3) 560 nm
(4) 580 nm
25. °·¤ »ñçÜçÜØÙ ÎêÚUÎàæèü ·ð¤ ¥çÖÎëàØ·¤ °ß´ Ùðç˜æ·¤æ
Üð‹â ·¤è $Ȥæð·¤â ÜÕæ§Øæ¡ ·ý¤×àæÑ 30 cm °ß´
3.0 cm ãñÐ ÎêÚUÎàæèü Ùðç˜æ·¤æ Üð‹â âð âéSÂcÅU ÎàæüÙ
·¤è ‹ØêÙÌ× ÎêÚUè ÂÚU °·¤ ¥ˆØ‹Ì ÎêÚU ·¤è ßSÌé ·¤æ
¥æÖæâè, âèÏæ ÂýçÌçÕÕ ÕÙæÌæ ãñÐ §â çSÍçÌ ×ð´,
»ñçÜçÜØÙ ÎêÚUÎàæèü ·¤è ¥æßÏüÙ ÿæ×Ìæ ãæð»è Ñ
(1) 111.2
(2) 211.2
(3) 28.8
(4) 18.8
26. çÙÙçÜç¹Ì ·¤‡ææð´ ×ð´ âð 緤⠷¤‡æ ·ð¤ çÜØð
ÇUè-Õýæ‚Üè âÕ‹Ï ·¤æ ÂýæØæðç»·¤ âˆØæÂÙ ¥ˆØçÏ·¤
×éçà·¤Ü ãæð»æ?
(1) °·¤ §Üð€ÅþUæÙ$
(2) °·¤ ÂýæðÅUæòÙ
(3) °·¤ a-·¤‡æ
(4) °·¤ ÏêÜ ·¤æ ·¤‡æ
21. English : 21 Set : 01 Hindi : 21 Set : 01
33. The standard electrode potentials
( )M /M
o
E 1 of four metals A, B, C and D are
21.2 V , 0.6 V, 0.85 V and 20.76 V,
respectively. The sequence of deposition
of metals on applying potential is :
(1) A, C, B, D
(2) B, D, C, A
(3) C, B, D, A
(4) D, A, B, C
34. At a certain temperature, only 50% HI is
dissociated into H2 and I2 at equilibrium.
The equilibrium constant is :
(1) 1.0
(2) 3.0
(3) 0.5
(4) 0.25
35. Dissolving 120 g of a compound of
(mol. wt. 60) in 1000 g of water gave a
solution of density 1.12 g/mL. The
molarity of the solution is :
(1) 1.00 M
(2) 2.00 M
(3) 2.50 M
(4) 4.00 M
33. ¿æÚU ÏæÌé¥æð´ A, B, C ¥æñÚU D ·ð¤ SÅñU‹ÇUÇüU (×æÙ·¤)
§Üñ€ÅþUæðÇU çßÖß ( )M /M
o
E 1 ·ý×æÙéâæÚU
21.2 V, 0.6 V, 0.85 V ¥æñÚU 20.76 V ãñ´Ð çßÖß
Üæ»ê ·¤ÚUÙð ÂÚU ÏæÌé Á×Ùð ·¤æ ·ý¤× ãæð»æ Ñ
(1) A, C, B, D
(2) B, D, C, A
(3) C, B, D, A
(4) D, A, B, C
34. °·¤ Ìæ çßàæðá âæØÂÚU ·ð¤ßÜ 50% HI, H2 ¥æñÚU
I2 ×ð´ çßÖæçÁÌ ãæðÌæ ãñÐ âæØ çSÍÚUæ´·¤ ·¤æ ×æÙ ãæð»æ Ñ
(1) 1.0
(2) 3.0
(3) 0.5
(4) 0.25
35. °·¤ Øæñç»·¤ (¥‡æéÖæÚU 60) ·¤è 120 »ýæ× ×æ˜ææ ·¤æð
1000 »ýæ× ÁÜ ×ð´ ƒææðÜÙð ÂÚU ÂýæŒÌ ãé° çßÜØÙ ·¤æ
ƒæÙˆß 1.12 »ýæ× ÂýçÌ ç×çÜ çÜÅUÚU ãñÐ çßÜØÙ ·¤è
×æðÜñçÚUÅUè ãæð»è Ñ
(1) 1.00 M
(2) 2.00 M
(3) 2.50 M
(4) 4.00 M
22. English : 22 Set : 01 Hindi : 22 Set : 01
36. The half-life period of a first order reaction
is 15 minutes. The amount of substance
left after one hour will be :
(1) 1
4 of the original amount
(2) 1
8 of the original amount
(3) 1
16 of the original amount
(4) 1
32 of the original amount
37. A current of 10.0 A flows for 2.00 h
through an electrolytic cell containing a
molten salt of metal X. This results in the
decomposition of 0.250 mol of metal X at
the cathode. The oxidation state of X in
the molten salt is : (F596,500 C)
(1) 11
(2) 21
(3) 31
(4) 41
36. °·¤ ÂýÍ× ·¤æðçÅU ·¤è ¥çÖç·ý¤Øæ ·¤æ ¥Ïü-¥æØé ·¤æÜ
15 ç×ÙÅU ãñÐ °·¤ ƒæ‡ÅUæ Âà¿æÌ÷ ÂÎæÍü ·¤è àæðá ÚUãè
×æ˜ææ ãæð»è Ñ
(1) ÂýæÚUçÖ·¤ ×æ˜ææ ·¤æ 1
4 Öæ»
(2) ÂýæÚUçÖ·¤ ×æ˜ææ ·¤æ 1
8 Öæ»
(3) ÂýæÚUçÖ·¤ ×æ˜ææ ·¤æ 1
16 Öæ»
(4) ÂýæÚUçÖ·¤ ×æ˜ææ ·¤æ 1
32 Öæ»
37. ÏæÌé X ·ð¤ çƒæÜð ãé° Ü߇æ ÏæÚU·¤ §Üñ€ÅþUæðçÜçÅU·¤
âñÜ ×ð´ âð 2.00 ƒæ‡ÅðU ·ð¤ çÜØð 10.0 A ·¤è çßléÌ
ÏæÚUæ ¿ÜæÙð ÂÚU 0.250 ×æðÜ X ÏæÌé ·¤æ Á×æß ãé¥æÐ
çƒæÜð ãé° Ü߇æ ×ð´ ÏæÌé X ·¤è ¥æ€âè·ë¤Ì ¥ßSÍæ
ãæð»è Ñ (ÁÕç·¤ F596,500 C)
(1) 11
(2) 21
(3) 31
(4) 41
32. English : 32 Set : 01 Hindi : 32 Set : 01
64. If
1
a
and
1
b
are the roots of the
equation, ax21bx1150 (a ¹ 0, a, b Î R),
then the equation,
x(x1b3)1(a323abx)50 has roots :
(1)
3
2a and
3
2b
(2) a
1
2b and
1
2a b
(3) a b and a b
(4)
3
2
2
a and
3
2
2
b
65. If a, b, c are non - zero real numbers and if
the system of equations
(a21)x5y1z,
(b21)y5z1x,
(c21)z5x1y,
has a non-trivial solution, then
ab1bc1ca equals :
(1) a1b1c
(2) abc
(3) 1
(4) 21
64. ØçÎ
1
a
ÌÍæ
1
b
â×è·¤ÚU‡æ ax21bx1150
(a ¹ 0, a, b Î R) ·ð¤ ×êÜ ãñ, Ìæð â×è·¤ÚU‡æ
x(x1b3)1(a323abx)50 ·ð¤ ×êÜ ã´ñ Ñ
(1)
3
2a ÌÍæ
3
2b
(2) a
1
2b ÌÍæ
1
2a b
(3) a b ÌÍæ a b
(4)
3
2
2
a ÌÍæ
3
2
2
b
65. ØçÎ a, b, c àæê‹ØðÌÚU ßæSÌçß·¤ â´Øæ°¡ ãñ´ ÌÍæ ØçÎ
â×è·¤ÚU‡æ çÙ·¤æØ
(a21)x5y1z,
(b21)y5z1x,
(c21)z5x1y,
·¤æ °·¤ ¥Ìé‘ÀU ãÜ ãñ, Ìæð ab1bc1ca ÕÚUæÕÚU ãñ Ñ
(1) a1b1c
(2) abc
(3) 1
(4) 21
33. English : 33 Set : 01 Hindi : 33 Set : 01
66. If B is a 333 matrix such that B250, then
det. [(I1B)50250B] is equal to :
(1) 1
(2) 2
(3) 3
(4) 50
67. The number of terms in the expansion of
(11x)101 (11x22x)100 in powers of x is :
(1) 302
(2) 301
(3) 202
(4) 101
68. The sum of the digits in the unit’s place of
all the 4-digit numbers formed by using the
numbers 3, 4, 5 and 6, without repetition,
is :
(1) 432
(2) 108
(3) 36
(4) 18
66. ØçÎ B °·¤ °ðâæ 333 ¥æÃØêã ãñ ç·¤ B250 ãñ, Ìæð
det. [(I1B)50250B] ÕÚUæÕÚU ãñ Ñ
(1) 1
(2) 2
(3) 3
(4) 50
67. (11x)101 (11x22x)100 ·ð¤ x ·¤è ƒææÌæð´ ×ð´ ÂýâæÚU
×ð´ ÂÎæð´ ·¤è â´Øæ ãñ Ñ
(1) 302
(2) 301
(3) 202
(4) 101
68. â´Øæ¥æð´ 3, 4, 5 ÌÍæ 6 ·ð¤ ÂýØæð» âð, çÕÙæ ·¤æð§ü â´Øæ
ÎæðãÚUæ°, ÕÙÙð ßæÜè âÖè ¿æÚU ¥´·¤æð´ ·¤è â´Øæ¥æð´ ·ð¤
§·¤æ§ü ·ð¤ SÍæÙ ÂÚU ¥æÙð ßæÜð ¥´·¤æð´ ·¤æ Øæð» ãñ Ñ
(1) 432
(2) 108
(3) 36
(4) 18
34. English : 34 Set : 01 Hindi : 34 Set : 01
69. Given an A.P. whose terms are all positive
integers. The sum of its first nine terms is
greater than 200 and less than 220. If the
second term in it is 12, then its 4th term
is :
(1) 8
(2) 16
(3) 20
(4) 24
70. If the sum
2 2 2 2 2 2
3 5 7
1 1 2 1 2 3
.......1 1 1 1
1 1 1
upto
20 terms is equal to
k
21
, then k is equal to :
(1) 120
(2) 180
(3) 240
(4) 60
71. If f(x) is continuous and ( )9 2
2 9f ,5 then
20
1 cos 3
lim
x
x
f
x→
2
is equal to :
(1) 9/2
(2) 2/9
(3) 0
(4) 8/9
69. Îè »§ü °·¤ â×æ´ÌÚU ŸæðÉ¸è ·ð¤ âÖè ÂÎ ÏÙÂê‡ææZ·¤ ãñ´Ð
§â·ð¤ ÂýÍ× Ùæñ ÂÎæð´ ·¤æ Øæð» 200 âð ¥çÏ·¤ ÌÍæ
220 âð ·¤× ãñÐ ØçÎ §â·¤æ ÎêâÚUæ ÂÎ 12 ãñ, Ìæð
§â·¤æ ¿æñÍæ ÂÎ ãñ Ñ
(1) 8
(2) 16
(3) 20
(4) 24
70. ØçÎ
2 2 2 2 2 2
3 5 7
1 1 2 1 2 3
.......1 1 1 1
1 1 1
·ð¤20
ÂÎæð´ Ì·¤ ·¤æ Øæð» k
21
·ð¤ ÕÚUæÕÚU ãñ, Ìæð k ÕÚUæÕÚU ãñ Ñ
(1) 120
(2) 180
(3) 240
(4) 60
71. ØçÎ f(x) âÌÌ ãñ ÌÍæ ( )9 2
2 9f 5 ãñ, Ìæð
20
1 cos 3
lim
x
x
f
x→
2
ÕÚUæÕÚU ãñ Ñ
(1) 9/2
(2) 2/9
(3) 0
(4) 8/9
35. English : 35 Set : 01 Hindi : 35 Set : 01
72. If y5enx, then
2 2
2 2
d d
d d
y x
x y
is equal to :
(1) n enx
(2) n e2nx
(3) 1
(4) 2n e2nx
73. If the Rolle’s theorem holds for the
function f(x)52x31ax21bx in the interval
[21, 1] for the point c5
1
2
, then the value
of 2a1b is :
(1) 1
(2) 21
(3) 2
(4) 22
74. If
3 4
( ) 1
5 5
x x
f x
5 1 2 , x Î R, then the
equation f(x)50 has :
(1) no solution
(2) one solution
(3) two solutions
(4) more than two solutions
72. ØçÎ y5enx ãñ, Ìæð
2 2
2 2
d d
d d
y x
x y
ÕÚUæÕÚU ãñ Ñ
(1) n enx
(2) n e2nx
(3) 1
(4) 2n e2nx
73. ØçΠȤÜÙ f(x)52x31ax21bx ·ð¤¤ çÜ° ¥´ÌÚUæÜ
[21, 1] ×ð´ çÕ´Îé c5
1
2
ÂÚU ÚUæðÜð ·¤æ Âý×ðØ Üæ»ê ãñ,
Ìæð 2a1b ·¤æ ×æÙ ãñ Ñ
(1) 1
(2) 21
(3) 2
(4) 22
74. ØçÎ 3 4
( ) 1
5 5
x x
f x
5 1 2 , x Î R ãñ, Ìæð
â×è·¤ÚU‡æ f(x)50 ·¤æ/·ð¤ Ñ
(1) ·¤æð§ü ãÜ Ùãè´ ãñÐ
(2) °·¤ ãÜ ãñÐ
(3) Îæð ãÜ ãñ´Ð
(4) Îæð âð ¥çÏ·¤ ãÜ ãñ´Ð
36. English : 36 Set : 01 Hindi : 36 Set : 01
75.
8 8
2 2
sin cos
d
(1 2 sin cos )
x x
x
x x
∫
2
2
is equal to :
(1)
1
2
sin 2x1c
(2)
1
2
2 sin 2x1c
(3)
1
2
2 sin x1c
(4) 2sin2 x1c
76. The integral
1
2
0
2
(1 2 )
d
1 4
ln x
x
x
∫
1
1
, equals :
(1)
4
p
ln 2
(2)
8
p
ln 2
(3)
16
p
ln 2
(4)
32
p
ln 2
77. Let A5{(x, y) : y2 [ 4x, y22x/24}. The
area (in square units) of the region A is :
(1) 8
(2) 9
(3) 10
(4) 11
75.
8 8
2 2
sin cos
d
(1 2 sin cos )
x x
x
x x
∫
2
2
ÕÚUæÕÚU ãñ Ñ
(1)
1
2
sin 2x1c
(2)
1
2
2 sin 2x1c
(3)
1
2
2 sin x1c
(4) 2sin2 x1c
76. â×æ·¤Ü
1
2
0
2
(1 2 )
d
1 4
ln x
x
x
∫
1
1
, ÕÚUæÕÚU ãñ Ñ
(1)
4
p
ln 2
(2)
8
p
ln 2
(3)
16
p
ln 2
(4)
32
p
ln 2
77. ×æÙæ A5{(x, y) : y2 [ 4x, y22x/24} ãñÐ
ÿæð˜æ A ·¤æ ÿæð˜æÈ¤Ü (ß»ü §·¤æ§üØæð´ ×ð´) ãñ Ñ
(1) 8
(2) 9
(3) 10
(4) 11