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Pythagorean theorem and distance formula

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Pythagorean Theorem and Distance Formula By: Tristin Patton
Pythagorean Theorem ,[object Object]
4 3 ?? 3 2 +4 2= ??? 9+16=25 The square root of 25 is 5. =5
The Distance Formula ,[object Object],(X2-X1) 2 + (Y2-Y1) 2
(2,4) (7,13) (7-2) 2 +(13-4) 2 5 2 +9 2 25+81=106 The square root of 106 is 10.3. The distance between (2,4) and (7,13) is 10.3 2 .

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Pythagorean theorem and distance formula

  • 1. Pythagorean Theorem and Distance Formula By: Tristin Patton
  • 2.
  • 3. 4 3 ?? 3 2 +4 2= ??? 9+16=25 The square root of 25 is 5. =5
  • 4.
  • 5. (2,4) (7,13) (7-2) 2 +(13-4) 2 5 2 +9 2 25+81=106 The square root of 106 is 10.3. The distance between (2,4) and (7,13) is 10.3 2 .