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HONORS PHYSICS
Good morning! Please…
• Take out your homework, to be checked
• Answer the warm-up question:
   • A baseball is thrown straight down from a building that is 65 meters tall. Its
     initial velocity is 3.0 m/s. What will its velocity be right before it hits the
     ground?
AGENDA:
1. Physics in the News!
2. Finish projectile motion activity
3. Review
4. Review activities


NOTE: Midterm is Wednesday 9:45-11:45
- Bring a book or work to do if you finish the midterm early
• LAST DAY FOR HOT TASK/MIDTERM WILL BE WEDNESDAY.
• **Cheat sheet update***
MIDTERM TOPICS

Topics                                   Suggested Study Techniques
1. Conversion, measurement, precision,   •   Look over all old tests & know how to
   accuracy                                  do every problem
2. One-dimensional motion: constant      •   Go over your notes from each unit –
   speed                                     be familiar with concepts
3. One-dimensional motion: accelerated   •   Re-do problems from the homework &
   motion                                    problems from the review sheet
4. Free-fall motion                      Format:
5. Vectors                               •   30 multiple choice
6. Projectile motion                     •   14 problems with multiple parts
7. Forces & Newton’s laws
1. CONVERSION, MEASUREMENT, PRECISION,
ACCURACY
•   Using factor label method to convert numbers
•   What are some examples of SI units used in physics? English units?
•   What are the significant figures for the following two numbers:
     • 0.02003                   54300
•   What is precision? What is accuracy?
•   How to convert between metric units
     • Know kilo- to milli-
2 & 3. ONE-DIMENSIONAL MOTION: CONSTANT
SPEED & ACCELERATION
•   Graphing motion
     • Identifying the information given on an x vs. t, v vs. t, a vs. t graph
          • Slope of the lines on the graphs
          • Area under the curve
•   Solving problems using one-dimensional motion equations
2. ONE-DIMENSIONAL MOTION: CONSTANT
SPEED
•   Graphing motion
4. FREE-FALL MOTION
•   The acceleration of an object in free-fall
•   Using motion equations to solve free-fall problems:
     • An object dropped from rest
     • An object dropped with an initial velocity
     • An object thrown straight up in the air that comes back down.
4. FREE-FALL MOTION
•   Sample problem: a ball is thrown straight up into the air at 12.0 m/s.
     • What is the velocity of the ball at its maximum height? What is its acceleration at
       maximum height?
                                                                     7.4 m
     •   What is the maximum height that the ball will reach?
     • What will be the velocity of the ball after 2.0 seconds?      -7.6 m/s
5. VECTORS
•   Difference between scalar and vector quantities
     • What are some examples of each?
•   Breaking vector into its components
•   Solving for resultant vectors by adding or subtracting two vectors
6. PROJECTILE MOTION
•   Concepts behind projectile motion
     • Projectile motion is anything that has an initial horizontal velocity that is under the
       influence of free-fall
     • X & y dimensions of motion are completely independent of one another
           • What happens in the x-direction?
           • What happens in the y-direction?
•   What is range? At what angle does any object have maximum range?
•   Problems with initial horizontal velocity
•   Problems with projectiles launched at an angle.
7. FORCES
•   Newton’s laws and how they apply in various situations
     • What is Newton’s first law? Second law? Third?
•   Drawing free-body diagram
•   Problems with friction on an inclined plane
•   Problems with friction on a level surface
•   Problems with a force applied at an angle
•   Calculating coefficients of kinetic and static friction.
7. FORCES
•   A student moves a box of books down the hall by pulling on a rope attached to the box.
    The student pulls with a force of 185 N at an angle of 25.0 degrees above the horizontal.
    The box has a mass of 35.0 kg and the coefficient of friction between the box and floor is
    0.27. Find the acceleration of the box.
                                             -1.2 m/s2
7. FORCES
     •     What is the net force on each object?

                     FN = 10 N

Ff = 3 N                               Fa = 5 N

                 Mg = 10 N



                  FN = 10 N                                    FN = 10 N


 Ff = 3 N                             Fa = 1 N     Ff = 3 N                Fa = 3 N

                Mg = 10 N                                     Mg = 10 N
HOT TASK
•   What does the normal force do?
                                         4.0 kg
•   How can we find the normal in both
    situations shown?
                                                   15o




                                                  15o
NEWTON’S ACTIVITIES
•   When a constant force is applied to something, should the speed increase? Should it stay
    the same?
     • Use Newton’s Second law and think about the scooter activity – did speed change as
       force was constant? Did acceleration change?
•   Explain how Newton’s first law applies in a car when wearing a seatbelt vs. without a
    seatbelt.
Example: force applied at an angle
Suppose a 10.0 kg box is pulled at an angle of 30.0 degrees with a force
  of 50.0 Newtons.                     F ¹ mg!         N
a) Calculate the normal force of the box             å FY = 0 ® FN + Fay - Fg = 0
                                                     FN + Fay = mg
                                                     FN = mg - Fay ® (10)(9.8) - 50sin30
                                                     FN = 73N
a) If the block is accelerating at 1.5 m/s/s, calculate the coefficient of friction.

                FN     Fa = 50 N                           å Fx = Fnet = ma
                                  Fay = 50sin(30)          Fax - Ff = ma
 Ff                  30
                          Fax = 50cos(30)                  50 cos30 - m FN = (10)(1.5)
                mg
                                                           43.3- m (73) = 15
                                                           m = 0.39
EXAMPLE: FORCE APPLIED AT ANGLE
#5 from handout last week:
A 120.0 N force is applied at an angle of 45 degrees to a 40.0 kg box. The coefficient of
friction between the two surfaces is 0.15. Find
(b) The force due to gravity and normal force
(c) The force due to friction
(d) The acceleration
(e) How fast the object is moving in 10.0 sec
(f) How far it will move in 10.0 sec
NEWTON’S THIRD LAW
NEWTON’S THIRD LAW
“For every action there is an EQUAL and OPPOSITE reaction.
        • This law focuses on action/reaction pairs (forces)
        • They NEVER cancel out



                                   All you do is SWITCH the wording!
                                        •PERSON on WALL
                                        •WALL on PERSON
NEWTON’S THIRD LAW
• How does this law apply when there is a collision
  between two objects, like a train and a truck??
NEWTON’S THIRD LAW
                                This figure shows the force during a collision
                                between a truck and a train. You can clearly see
                                the forces are EQUAL and OPPOSITE. To help
                                you understand the law better, look at this
                                situation from the point of view of Newton’s
                                Second Law.

                                                  Ftruck = Ftrain
                               What about mass & acceleration just after collision?


                                         mtruck   Atruck = Mtraina   train


There is a balance between the mass and acceleration. One object usually
has a LARGE MASS and a SMALL ACCELERATION, while the other has a
SMALL MASS (comparatively) and a LARGE ACCELERATION.
N.T.L EXAMPLES
             Action:  HAMMER HITS NAIL
               Reaction: NAIL HITS HAMMER



                                Action: Earth pulls on YOU
                                Reaction: YOU pull on the earth
NEWTON’S FIRST LAW

Concepts                                    Problems
•   What is it?                             •   What type of problems apply?
     • An object in motion will remain in
       motion, or an object at rest will
       remain at rest unless acted upon                        4.0 kg
       by an unbalanced force.
•   Fnet = 0
     • What conditions can occur?
                                                               4.0 kg
     • Object can be at rest
     • Object can be in constant motion
       at a constant speed
NEWTON’S SECOND LAW

Concepts                                   Problems
•   What is it?                            •   What type of problems apply?
     • Fnet = ma or re-arranged as..
                   a = Fnet
                                                              4.0 kg
                        m
•   Fnet = ma
     • Describe the motion of the object
       when Newton’s 2 nd law applies                         4.0 kg
ATWOOD’S MACHINE
                   Draw the following FBDs if mass 1 = 1.0
                   kg, mass 2 = 2.0 kg:
                        • An FBD of the entire system
                        • An FBD of mass 1
                        • An FBD of mass 2
                   •   Which direction will the masses
                       move?
                   •   Use the FBDs to find the net force
                       equations for each FBD
                   •   Calculate the acceleration
FREE-BODY DIAGRAMS
•   Draw a Free-body diagram of an elevator accelerating up, and then one of an elevator
    accelerating down. Write the equation for the net force on the elevator for each.
FREE-BODY DIAGRAM
•   A block is pushed across a frictionless plane, and released when the block reaches a
    speed of 2.0 m/s. Draw the FBD of the block AFTER it is released.




                                                                       4.0 kg
HOMEWORK
24. A 650 N force acts in a northwesterly direction. A second 650-N force must be exerted in
what direction so that the resultant of the two forces points westward?
HOMEWORK
*26. Sketch the free-body diagram of a baseball (a) at the moment it is hit by the bat, (b) after
it has left the bat and is flying toward the outfield
HOMEWORK
27. USE figure from book: two forces F1 and F2 act on a 27.0 kg object on a frictionless
tabletop. If F1 = 10.2 N and F2 = 16.0N, what is the net force on the object and its
acceleration in both situation (a) and (b)




         F1


                 F2
HOMEWORK
32. A window washer pulls herself upward using the bucket-pulley apparatus shown. Mass =
65 kg.
          (a) how hard must she pull downward to raise herself slowly at constant speed?
          (b) If she increases this force by 10%, what will her acceleration be?
LAST NIGHT’S HOMEWORK
23. a) 40 N, b) 10 N, c) 0
38. 100 N, no force
*39. (a) μs=0.82 (b) μk=0.74
40. diagrams
41. μs=0.41
42. μs=2.3
HOMEWORK: FRICTION PROBLEMS
*23. A box weighing 10 N rests on a table. A rope tied to the box runs vertically upward over a
pulley and a weight is hung from the other end. Determine the force that the table exerts on
the box if the weight hanging on the other side of the pulley weighs (a) 30 N, (b) 60 N, and ©
90 N.
                    a) 40 N, b) 10 N, c) 0




   70N
HOMEWORK: FRICTION PROBLEMS
38. The coefficient of Friction between a 35 kg crate and the floor is 0.30, what horizontal
force is required to move the crate at a steady speed across the floor? What horizontal force
is required if μk is zero? (100 N, no force)
HOMEWORK: FRICTION
*39. A force of 40.0 N is required to start a 5.0 kg box moving across a horizontal concrete
floor. (a) what is the coefficient of static friction between the box and the floor? (b) if the 40.0
N force continues, the box accelerates at 0.70 m/s2. What is the coefficient of kinetic friction?
(a) μs=0.82 (b) μk=0.74




               FN

Ff                                Fa

                mg
HOMEWORK: FRICTION
*40. (a) a box sits at rest on a rough 30 degree inclined plane. Draw the free-body diagram,
showing all the forces cting on the box.
(b) How would the diagram change if the box were sliding down the plane?
(c) How would it change if the box were sliding up the plane after an initial shove?
HOMEWORK: FRICTION
41. A 2.0-kg silverware drawer does not slide readily. The owner gradually pulls with more and
more force. When the applied force reaches 8.0 N, the drawer suddenly opens, throwing all
the utensils to the floor. Find the coefficient of static friction between the drawer and the
cabinet. (μs=0.41)
HOMEWORK: FRICTION
42. Drag race tires in contact with an asphalt surface probably have one of the highest
coefficients of static friction in the everyday world. Assuming a constant acceleration and no
slipping of tires, estimate the coefficient of static friction for a drag racer that covers the
quarter mile in 6.0 s. (μs=2.3)
CALCULATING COEFFICIENTS OF STATIC &
     KINETIC FRICTION
You can calculate μs and μk between two surfaces       Materials needed:
by…
                                                       •   Brick of known mass with string
•   Finding out the MAXIMUM force required to              attached
    begin moving an object
                                                       •   Spring scale
                 Fmax = μsFN
•   Finding out the force required to move an object
    at a constant speed                                Directions:
                                                       •   Have TWO different people take readings
                  F f = μkFN                               from the force scales & take the average
                                                           of the two
     In both of these cases, the object is in
                  equilibrium, so                      •   Use equations to solve for coefficients
                                                       •   NOTE: Spring scale reads in Pounds –
           Fa = Ff & Fa = Fmax                             you will have to conver units to Newtons
                                                           (using 2.2 lbs = 1 kg, W = mg)
FORCES ON AN INCLINED PLANE
Ff = μFN
                                         FN

So to find Ff, we must find FN first!


Steps to solving these problems…
1.   FBD
2.   Sum forces in y-direction (to
     find Fn)
                                        FG
3.   Solve for Ff
4.   Find the net force in the x-             θ
     direction (direction of motion)
WORKSHEET PROBLEM #1                                 12 kg

1. A 12-kilogram block is place on a 25 o inclined plane.
                                                                    25o
 s=   0.15 and   k=   0.11
(a) Draw a Free Body Diagram showing mg, F , FN ,
    FII & Ff.
(b) Calculate for mg, FII , FN for the block.
(c) Calculate the forces of static & kinetic friction.
(d) Solve for the net force on the block.
(e) Solve for the acceleration of the block.
(f) How far will it slide in 1.0 seconds?
WORKSHEET PROBLEM #1                               12 kg

1. A 12-kilogram block is pushed up a 25o inclined
plane, then the applied force is removed. Answer the              25o
following questions for the block AFTER it is released,
but while it is still traveling UP the incline.
 s=   0.15 and   k=   0.11
(a) Draw a Free Body Diagram showing mg, F , FN ,
    FII & Ff.
(b) Calculate for mg, FII , FN for the block.
(c) Calculate the forces of static & kinetic friction.
(d) Solve for the net force on the block.
(e) Solve for the acceleration of the block.
(f) How far will it slide up the incline if the initial
    velocity is 2.0 m/s2?
INTRO TO FRICTION!
What do you already know about friction?
When is friction useful?
When is it harmful?
Write a short paragraph about a friction-free world!
FRICTIONAL FORCES
  • There are two types of frictional forces:

    Type of friction                                  Definition                             Equation

Static Friction                 A force that acts parallel to the two surfaces &           Fmax = μsFN
(used for stationary objects)   keeps an object from moving.
Kinetic Friction                A force that acts opposite to the direction of an
(used for moving objects)                                                                    Ff = μkFN
                                object’s motion.

                                     Fmax is the maximum force that can
                                     be applied to an object before it              Ff is the frictional force
                                     begins to move




                      The greek symbol “μ” is pronounced “mu”
NEW FREE-BODY DIAGRAM
•   Now we include the force of friction!




                                            FN

                               Ff                Fa

                                            mg
HOW TO CALCULATE COEFFICIENTS OF
FRICTION (WHEN NET FORCE = 0)
             • When an object is moving at a CONSTANT SPEED,
               we can find the force of friction due to the coefficient
               of kinetic friction.
                           Constant speed means that acceleration = 0
     FN
                                          So Fnet = 0
                                        SO…. Fa – Ff = 0
Ff           Fa

                                            Ff = Fa
      mg
             • When a force is applied that causes an object to
               JUST BEGIN TO MOVE, we can find the force of
               friction due to the coefficient of static friction
                                    Once again…. Ff = Fa
Example: Net force = 0
A 10-kg box is being pulled across the table to the right at a constant speed with a force
   of 50N.
a) Calculate the Force of Friction     Fa = Ff = 50N

a) Calculate the Force Normal       mg Fn            (10)(9.8) 98N
a) Calculate the coefficient of kinetic friction
                                                   Ff = mk FN
                   FN

                                    Fa
                                                   50 = m k (98)
      Ff
                                                        50
                    mg                             m k = = 0.51
                                                        98
Example: Net force = 0
     Suppose the same box is now pulled at an angle of 30 degrees above the horizontal.
     a) Calculate the Force of Friction
                                          Fax    Fa cos     50cos30 43.3N
                                          Ff     Fax   43.3N
     a) Calculate the Force Normal
                                          FN    m g!
                                          FN    Fay    mg
               FN     Fa                  FN    m g Fay      (10)(9.8) 50 sin 30
                                 Fay      FN    73N
Ff                  30
                           Fax
               mg
EXAMPLE: NET FORCE = MA
A 50 N applied force drags an 8.16 kg log to the right across a horizontal
   surface. What is the acceleration of the log if the force of friction is 40.0 N?



             Fn                   a          FNET = ma
                         50 N
40 N                                         Fa - Ff = ma
              mg                             50 - 40 = 8.16a
                                             10 = 8.16a
                                             a=     1.23 m/s/s
EXAMPLE: NET FORCE = MA
A sled is being accelerated to the right at a rate of 1.5 m/s/s by a rope at a 33
   degree angle above the + x . Calculate the acceleration of the sled if the
   Frictional Force is 26.8 N, the mass of the sled is 66 kg and the tension in
   the rope is 150 N.
                         a
               FN
                                      Tsin

                               Tcos
                                             FNET = ma
 Ff                                          T cosq - Ff = ma
                    mg
                                             T cosq - ma = Ff
                                             150 cos33- (66)(1.5) = Ff
                                             Ff = 1.5 m/s/s
An Atwood's machine is a device where
                   two masses, m2 and m1, are connected by
ATWOOD’S MACHINE   a string passing over a pulley.
                   •   Assume the pulley is frictionless and
                       massless, which means the tension is
                       the same everywhere in the string.
                   •   To solve these problems:
                        • Make three FBDs: one for each
                          mass, and one for the overall
                          system.
                             • So you can make 3 Fnet=ma
                               equations.
                        • To find Tension: use the FBDs of
                          individual masses
                        • To find acceleration: use either
                          both FBDs of individual masses,
                          or one of the overall system
If mass 1 is 200 kg, and mass 2 is 30 kg,
                                          what is the acceleration of the system?
ATWOOD’S MACHINE
                                            a = 3.27 m/s2




• Make FBDs
• Have the direction of acceleration be
  positive
• Use Newton’s 2 nd law to find
  acceleration
HOMEWORK SOLUTIONS
    Pg. 104 # 1-8
1. 69 N
                                                   Free Body Diagrams
2. 116 kg
3. 883 N                                           a. A projectile in motion in the presence
                                                      of air resistance.
4. 1260 N
5. (a) 648 N                                       b. A car at the instant it hits a brick wall.
   (b) 112 N                                       c. A heavy crate being pushed across a
    (c) 244 N                                         surface (neglect surface friction).
   (d) 0 N                                         d. A shopping cart being pushed at a 30°
6. (a) W = 196 N, Fn = 196 N                          angle with horizontal (neglect surface
                                                      friction).
    (b) Fn on 20 kg box: 294 N, Fn on 10 kg from
20 kg = 98 kg
7. 3443 N
8. F = 153 N

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Day 23 a-h-midterm review

  • 1. HONORS PHYSICS Good morning! Please… • Take out your homework, to be checked • Answer the warm-up question: • A baseball is thrown straight down from a building that is 65 meters tall. Its initial velocity is 3.0 m/s. What will its velocity be right before it hits the ground?
  • 2. AGENDA: 1. Physics in the News! 2. Finish projectile motion activity 3. Review 4. Review activities NOTE: Midterm is Wednesday 9:45-11:45 - Bring a book or work to do if you finish the midterm early • LAST DAY FOR HOT TASK/MIDTERM WILL BE WEDNESDAY. • **Cheat sheet update***
  • 3. MIDTERM TOPICS Topics Suggested Study Techniques 1. Conversion, measurement, precision, • Look over all old tests & know how to accuracy do every problem 2. One-dimensional motion: constant • Go over your notes from each unit – speed be familiar with concepts 3. One-dimensional motion: accelerated • Re-do problems from the homework & motion problems from the review sheet 4. Free-fall motion Format: 5. Vectors • 30 multiple choice 6. Projectile motion • 14 problems with multiple parts 7. Forces & Newton’s laws
  • 4. 1. CONVERSION, MEASUREMENT, PRECISION, ACCURACY • Using factor label method to convert numbers • What are some examples of SI units used in physics? English units? • What are the significant figures for the following two numbers: • 0.02003 54300 • What is precision? What is accuracy? • How to convert between metric units • Know kilo- to milli-
  • 5. 2 & 3. ONE-DIMENSIONAL MOTION: CONSTANT SPEED & ACCELERATION • Graphing motion • Identifying the information given on an x vs. t, v vs. t, a vs. t graph • Slope of the lines on the graphs • Area under the curve • Solving problems using one-dimensional motion equations
  • 6. 2. ONE-DIMENSIONAL MOTION: CONSTANT SPEED • Graphing motion
  • 7. 4. FREE-FALL MOTION • The acceleration of an object in free-fall • Using motion equations to solve free-fall problems: • An object dropped from rest • An object dropped with an initial velocity • An object thrown straight up in the air that comes back down.
  • 8. 4. FREE-FALL MOTION • Sample problem: a ball is thrown straight up into the air at 12.0 m/s. • What is the velocity of the ball at its maximum height? What is its acceleration at maximum height? 7.4 m • What is the maximum height that the ball will reach? • What will be the velocity of the ball after 2.0 seconds? -7.6 m/s
  • 9. 5. VECTORS • Difference between scalar and vector quantities • What are some examples of each? • Breaking vector into its components • Solving for resultant vectors by adding or subtracting two vectors
  • 10. 6. PROJECTILE MOTION • Concepts behind projectile motion • Projectile motion is anything that has an initial horizontal velocity that is under the influence of free-fall • X & y dimensions of motion are completely independent of one another • What happens in the x-direction? • What happens in the y-direction? • What is range? At what angle does any object have maximum range? • Problems with initial horizontal velocity • Problems with projectiles launched at an angle.
  • 11. 7. FORCES • Newton’s laws and how they apply in various situations • What is Newton’s first law? Second law? Third? • Drawing free-body diagram • Problems with friction on an inclined plane • Problems with friction on a level surface • Problems with a force applied at an angle • Calculating coefficients of kinetic and static friction.
  • 12. 7. FORCES • A student moves a box of books down the hall by pulling on a rope attached to the box. The student pulls with a force of 185 N at an angle of 25.0 degrees above the horizontal. The box has a mass of 35.0 kg and the coefficient of friction between the box and floor is 0.27. Find the acceleration of the box. -1.2 m/s2
  • 13. 7. FORCES • What is the net force on each object? FN = 10 N Ff = 3 N Fa = 5 N Mg = 10 N FN = 10 N FN = 10 N Ff = 3 N Fa = 1 N Ff = 3 N Fa = 3 N Mg = 10 N Mg = 10 N
  • 14. HOT TASK • What does the normal force do? 4.0 kg • How can we find the normal in both situations shown? 15o 15o
  • 15. NEWTON’S ACTIVITIES • When a constant force is applied to something, should the speed increase? Should it stay the same? • Use Newton’s Second law and think about the scooter activity – did speed change as force was constant? Did acceleration change? • Explain how Newton’s first law applies in a car when wearing a seatbelt vs. without a seatbelt.
  • 16. Example: force applied at an angle Suppose a 10.0 kg box is pulled at an angle of 30.0 degrees with a force of 50.0 Newtons. F ¹ mg! N a) Calculate the normal force of the box å FY = 0 ® FN + Fay - Fg = 0 FN + Fay = mg FN = mg - Fay ® (10)(9.8) - 50sin30 FN = 73N a) If the block is accelerating at 1.5 m/s/s, calculate the coefficient of friction. FN Fa = 50 N å Fx = Fnet = ma Fay = 50sin(30) Fax - Ff = ma Ff 30 Fax = 50cos(30) 50 cos30 - m FN = (10)(1.5) mg 43.3- m (73) = 15 m = 0.39
  • 17. EXAMPLE: FORCE APPLIED AT ANGLE #5 from handout last week: A 120.0 N force is applied at an angle of 45 degrees to a 40.0 kg box. The coefficient of friction between the two surfaces is 0.15. Find (b) The force due to gravity and normal force (c) The force due to friction (d) The acceleration (e) How fast the object is moving in 10.0 sec (f) How far it will move in 10.0 sec
  • 19. NEWTON’S THIRD LAW “For every action there is an EQUAL and OPPOSITE reaction. • This law focuses on action/reaction pairs (forces) • They NEVER cancel out All you do is SWITCH the wording! •PERSON on WALL •WALL on PERSON
  • 20. NEWTON’S THIRD LAW • How does this law apply when there is a collision between two objects, like a train and a truck??
  • 21. NEWTON’S THIRD LAW This figure shows the force during a collision between a truck and a train. You can clearly see the forces are EQUAL and OPPOSITE. To help you understand the law better, look at this situation from the point of view of Newton’s Second Law. Ftruck = Ftrain What about mass & acceleration just after collision? mtruck Atruck = Mtraina train There is a balance between the mass and acceleration. One object usually has a LARGE MASS and a SMALL ACCELERATION, while the other has a SMALL MASS (comparatively) and a LARGE ACCELERATION.
  • 22. N.T.L EXAMPLES Action: HAMMER HITS NAIL Reaction: NAIL HITS HAMMER Action: Earth pulls on YOU Reaction: YOU pull on the earth
  • 23. NEWTON’S FIRST LAW Concepts Problems • What is it? • What type of problems apply? • An object in motion will remain in motion, or an object at rest will remain at rest unless acted upon 4.0 kg by an unbalanced force. • Fnet = 0 • What conditions can occur? 4.0 kg • Object can be at rest • Object can be in constant motion at a constant speed
  • 24. NEWTON’S SECOND LAW Concepts Problems • What is it? • What type of problems apply? • Fnet = ma or re-arranged as.. a = Fnet 4.0 kg m • Fnet = ma • Describe the motion of the object when Newton’s 2 nd law applies 4.0 kg
  • 25. ATWOOD’S MACHINE Draw the following FBDs if mass 1 = 1.0 kg, mass 2 = 2.0 kg: • An FBD of the entire system • An FBD of mass 1 • An FBD of mass 2 • Which direction will the masses move? • Use the FBDs to find the net force equations for each FBD • Calculate the acceleration
  • 26. FREE-BODY DIAGRAMS • Draw a Free-body diagram of an elevator accelerating up, and then one of an elevator accelerating down. Write the equation for the net force on the elevator for each.
  • 27. FREE-BODY DIAGRAM • A block is pushed across a frictionless plane, and released when the block reaches a speed of 2.0 m/s. Draw the FBD of the block AFTER it is released. 4.0 kg
  • 28.
  • 29. HOMEWORK 24. A 650 N force acts in a northwesterly direction. A second 650-N force must be exerted in what direction so that the resultant of the two forces points westward?
  • 30. HOMEWORK *26. Sketch the free-body diagram of a baseball (a) at the moment it is hit by the bat, (b) after it has left the bat and is flying toward the outfield
  • 31. HOMEWORK 27. USE figure from book: two forces F1 and F2 act on a 27.0 kg object on a frictionless tabletop. If F1 = 10.2 N and F2 = 16.0N, what is the net force on the object and its acceleration in both situation (a) and (b) F1 F2
  • 32. HOMEWORK 32. A window washer pulls herself upward using the bucket-pulley apparatus shown. Mass = 65 kg. (a) how hard must she pull downward to raise herself slowly at constant speed? (b) If she increases this force by 10%, what will her acceleration be?
  • 33. LAST NIGHT’S HOMEWORK 23. a) 40 N, b) 10 N, c) 0 38. 100 N, no force *39. (a) μs=0.82 (b) μk=0.74 40. diagrams 41. μs=0.41 42. μs=2.3
  • 34. HOMEWORK: FRICTION PROBLEMS *23. A box weighing 10 N rests on a table. A rope tied to the box runs vertically upward over a pulley and a weight is hung from the other end. Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs (a) 30 N, (b) 60 N, and © 90 N. a) 40 N, b) 10 N, c) 0 70N
  • 35. HOMEWORK: FRICTION PROBLEMS 38. The coefficient of Friction between a 35 kg crate and the floor is 0.30, what horizontal force is required to move the crate at a steady speed across the floor? What horizontal force is required if μk is zero? (100 N, no force)
  • 36. HOMEWORK: FRICTION *39. A force of 40.0 N is required to start a 5.0 kg box moving across a horizontal concrete floor. (a) what is the coefficient of static friction between the box and the floor? (b) if the 40.0 N force continues, the box accelerates at 0.70 m/s2. What is the coefficient of kinetic friction? (a) μs=0.82 (b) μk=0.74 FN Ff Fa mg
  • 37. HOMEWORK: FRICTION *40. (a) a box sits at rest on a rough 30 degree inclined plane. Draw the free-body diagram, showing all the forces cting on the box. (b) How would the diagram change if the box were sliding down the plane? (c) How would it change if the box were sliding up the plane after an initial shove?
  • 38. HOMEWORK: FRICTION 41. A 2.0-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force. When the applied force reaches 8.0 N, the drawer suddenly opens, throwing all the utensils to the floor. Find the coefficient of static friction between the drawer and the cabinet. (μs=0.41)
  • 39. HOMEWORK: FRICTION 42. Drag race tires in contact with an asphalt surface probably have one of the highest coefficients of static friction in the everyday world. Assuming a constant acceleration and no slipping of tires, estimate the coefficient of static friction for a drag racer that covers the quarter mile in 6.0 s. (μs=2.3)
  • 40. CALCULATING COEFFICIENTS OF STATIC & KINETIC FRICTION You can calculate μs and μk between two surfaces Materials needed: by… • Brick of known mass with string • Finding out the MAXIMUM force required to attached begin moving an object • Spring scale Fmax = μsFN • Finding out the force required to move an object at a constant speed Directions: • Have TWO different people take readings F f = μkFN from the force scales & take the average of the two In both of these cases, the object is in equilibrium, so • Use equations to solve for coefficients • NOTE: Spring scale reads in Pounds – Fa = Ff & Fa = Fmax you will have to conver units to Newtons (using 2.2 lbs = 1 kg, W = mg)
  • 41. FORCES ON AN INCLINED PLANE Ff = μFN FN So to find Ff, we must find FN first! Steps to solving these problems… 1. FBD 2. Sum forces in y-direction (to find Fn) FG 3. Solve for Ff 4. Find the net force in the x- θ direction (direction of motion)
  • 42. WORKSHEET PROBLEM #1 12 kg 1. A 12-kilogram block is place on a 25 o inclined plane. 25o s= 0.15 and k= 0.11 (a) Draw a Free Body Diagram showing mg, F , FN , FII & Ff. (b) Calculate for mg, FII , FN for the block. (c) Calculate the forces of static & kinetic friction. (d) Solve for the net force on the block. (e) Solve for the acceleration of the block. (f) How far will it slide in 1.0 seconds?
  • 43. WORKSHEET PROBLEM #1 12 kg 1. A 12-kilogram block is pushed up a 25o inclined plane, then the applied force is removed. Answer the 25o following questions for the block AFTER it is released, but while it is still traveling UP the incline. s= 0.15 and k= 0.11 (a) Draw a Free Body Diagram showing mg, F , FN , FII & Ff. (b) Calculate for mg, FII , FN for the block. (c) Calculate the forces of static & kinetic friction. (d) Solve for the net force on the block. (e) Solve for the acceleration of the block. (f) How far will it slide up the incline if the initial velocity is 2.0 m/s2?
  • 44. INTRO TO FRICTION! What do you already know about friction? When is friction useful? When is it harmful? Write a short paragraph about a friction-free world!
  • 45. FRICTIONAL FORCES • There are two types of frictional forces: Type of friction Definition Equation Static Friction A force that acts parallel to the two surfaces & Fmax = μsFN (used for stationary objects) keeps an object from moving. Kinetic Friction A force that acts opposite to the direction of an (used for moving objects) Ff = μkFN object’s motion. Fmax is the maximum force that can be applied to an object before it Ff is the frictional force begins to move The greek symbol “μ” is pronounced “mu”
  • 46. NEW FREE-BODY DIAGRAM • Now we include the force of friction! FN Ff Fa mg
  • 47. HOW TO CALCULATE COEFFICIENTS OF FRICTION (WHEN NET FORCE = 0) • When an object is moving at a CONSTANT SPEED, we can find the force of friction due to the coefficient of kinetic friction. Constant speed means that acceleration = 0 FN So Fnet = 0 SO…. Fa – Ff = 0 Ff Fa Ff = Fa mg • When a force is applied that causes an object to JUST BEGIN TO MOVE, we can find the force of friction due to the coefficient of static friction Once again…. Ff = Fa
  • 48. Example: Net force = 0 A 10-kg box is being pulled across the table to the right at a constant speed with a force of 50N. a) Calculate the Force of Friction Fa = Ff = 50N a) Calculate the Force Normal mg Fn (10)(9.8) 98N a) Calculate the coefficient of kinetic friction Ff = mk FN FN Fa 50 = m k (98) Ff 50 mg m k = = 0.51 98
  • 49. Example: Net force = 0 Suppose the same box is now pulled at an angle of 30 degrees above the horizontal. a) Calculate the Force of Friction Fax Fa cos 50cos30 43.3N Ff Fax 43.3N a) Calculate the Force Normal FN m g! FN Fay mg FN Fa FN m g Fay (10)(9.8) 50 sin 30 Fay FN 73N Ff 30 Fax mg
  • 50. EXAMPLE: NET FORCE = MA A 50 N applied force drags an 8.16 kg log to the right across a horizontal surface. What is the acceleration of the log if the force of friction is 40.0 N? Fn a FNET = ma 50 N 40 N Fa - Ff = ma mg 50 - 40 = 8.16a 10 = 8.16a a= 1.23 m/s/s
  • 51. EXAMPLE: NET FORCE = MA A sled is being accelerated to the right at a rate of 1.5 m/s/s by a rope at a 33 degree angle above the + x . Calculate the acceleration of the sled if the Frictional Force is 26.8 N, the mass of the sled is 66 kg and the tension in the rope is 150 N. a FN Tsin Tcos FNET = ma Ff T cosq - Ff = ma mg T cosq - ma = Ff 150 cos33- (66)(1.5) = Ff Ff = 1.5 m/s/s
  • 52. An Atwood's machine is a device where two masses, m2 and m1, are connected by ATWOOD’S MACHINE a string passing over a pulley. • Assume the pulley is frictionless and massless, which means the tension is the same everywhere in the string. • To solve these problems: • Make three FBDs: one for each mass, and one for the overall system. • So you can make 3 Fnet=ma equations. • To find Tension: use the FBDs of individual masses • To find acceleration: use either both FBDs of individual masses, or one of the overall system
  • 53. If mass 1 is 200 kg, and mass 2 is 30 kg, what is the acceleration of the system? ATWOOD’S MACHINE a = 3.27 m/s2 • Make FBDs • Have the direction of acceleration be positive • Use Newton’s 2 nd law to find acceleration
  • 54. HOMEWORK SOLUTIONS Pg. 104 # 1-8 1. 69 N Free Body Diagrams 2. 116 kg 3. 883 N a. A projectile in motion in the presence of air resistance. 4. 1260 N 5. (a) 648 N b. A car at the instant it hits a brick wall. (b) 112 N c. A heavy crate being pushed across a (c) 244 N surface (neglect surface friction). (d) 0 N d. A shopping cart being pushed at a 30° 6. (a) W = 196 N, Fn = 196 N angle with horizontal (neglect surface friction). (b) Fn on 20 kg box: 294 N, Fn on 10 kg from 20 kg = 98 kg 7. 3443 N 8. F = 153 N