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Quadratic Equations (Quadratic Formula) Using PowerPoint
1.
Quadratic Equations (Quadratic
Formula) by Rich Rollo
2.
The Equation 5y
2 –8y + 3 = 0
3.
The Quadratic Formula
x = -b + b 2 –4ac 2a
4.
Identify the Parts
ay 2 + by + c = 0 5y 2 –8y + 3 = 0 Therefore in this case, a = 5, b = -8, and c = 3.
5.
Step One Plug
in the values of a, b, and c into the quadratic formula. x = -(-8) + (-8) 2 –4(5)(3) 2(5)
6.
Step Two Simplify
all terms found within the radicand. x = -(-8) + 64 –60 2(5) x = -(-8) + 4 2(5)
7.
Step 3 Simplify
the remaining terms in the formula. x = -(-8) + 4 2(5) x = 8 + 2 10
8.
Step 4 Isolate
the variable to find the solution set. x = 8 + 2 10 X = 8 + 2 X = 8 –2 10 10 = = 1 .6 &
9.
Solution Set 1
and .6
10.
Check the 1
st Solution Check ………………………………………… 1 5y 2 –8y + 3 = 0 5(1) 2 –8(1) + 3 = 0 5 –8 + 3 = 0 True
11.
Check the 2
nd Solution Check ………………………………six-tenths. (.6) 5y 2 –8y + 3 = 0 5(.6) 2 –8(.6) + 3 = 0 1.8 –4.8 + 3 = 0 True
12.
Therefore 1 and
.6 is the solution set for 5y 2 –8y + 3 = 0