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Warm-Up  ,[object Object],1. 2. 3.  f(x) = x 2  + 4x - 7,  find f(-5).
Piecewise Functions Objectives:  Become familiar with piecewise functions Evaluate  piecewise functions
What Does Research Say? ,[object Object],[object Object]
Piecewise Functions A  piecewise function  is a function that is a combination of one or more functions.
Read this as “ f of x is 5 if x is greater than 0 and less than 13 ,  9 if x is greater than or equal to 13 and less than 55 , and  6.5 if x is greater than or equal to 55 . ” The rule for a  piecewise function  is different for different parts, (or pieces), of the domain (x-values)  For instance, movie ticket prices are often different for different age groups. So the function for movie ticket prices would assign a different value (ticket price) for each domain interval (age group).
Restricting the domain  of a function ,[object Object],[object Object],all real numbers  f(x) = x 2  - 3
[object Object],Looking at only “part” or a “piece”  of the function  What rule would you write for this function? (How could we restrict the original function?) f(x) = x 2  - 3  if   x   ≥ -2 x   ≥ -2 f(x) = x 2  - 3
Restricting the domain  of a function What is the domain?  All real numbers What is the equation for this graph?  f(x) = –2x – 5
[object Object],Looking at only “part” or a “piece” of the function  What rule would you write for this function? f(x) = –2x – 5 f(x) = –2x – 5  if   x < –2
What rule would you write for this piecewise function? Piecewise Functions   x 2  – 3  if  x ≥ –2
a)  What is the value of y when  x = –4?  Give two ways to find it. Piecewise Functions   b) Which equation would you use to find the value of y when x = 2? c) Which equation would you use to find the value of y when x = –2? x 2  – 3  if  x ≥ –2
Piecing it all together:   Evaluating  Piecewise Functions ,[object Object],[object Object],9 3 -1 25
2x + 1  if x ≤ 2  x 2  – 4  if x > 2  h(x) = Because  –1 ≤ 2, use the rule for x ≤ 2 . Because  4 > 2, use the rule for x > 2. h(–1) = 2(–1) + 1 = –1 h(4) = 4 2  – 4 = 12 Evaluate the piecewise function for:  x = –1 and x = 4.
3x 2  + 1  if x < 0  5x – 2  if x ≥ 0  g(x) = Because  –1 < 0, use the rule for x < 0. Because  3 ≥ 0, use the rule for x ≥ 0. g(3) = 5(3) – 2 = 13 g(–1) = 3(–1) 2  + 1 = 4 Evaluate each piecewise function for:  x = –1 and x = 3
12  if x < –3  20  if x ≥ 6 f(x) = Because  –3 ≤  –1  < 6 , use the rule for – 3 ≤ x < 6   f(–1) = 15 Evaluate each piecewise function for:  x = –1 and x = 3 15  if –3 ≤ x < 6  f(3) = 15 Because  –3 ≤  3  < 6 , use the rule for – 3 ≤ x < 6

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Piecewise function lesson 3

  • 1.
  • 2. Piecewise Functions Objectives: Become familiar with piecewise functions Evaluate piecewise functions
  • 3.
  • 4. Piecewise Functions A piecewise function is a function that is a combination of one or more functions.
  • 5. Read this as “ f of x is 5 if x is greater than 0 and less than 13 , 9 if x is greater than or equal to 13 and less than 55 , and 6.5 if x is greater than or equal to 55 . ” The rule for a piecewise function is different for different parts, (or pieces), of the domain (x-values) For instance, movie ticket prices are often different for different age groups. So the function for movie ticket prices would assign a different value (ticket price) for each domain interval (age group).
  • 6.
  • 7.
  • 8. Restricting the domain of a function What is the domain? All real numbers What is the equation for this graph? f(x) = –2x – 5
  • 9.
  • 10. What rule would you write for this piecewise function? Piecewise Functions x 2 – 3 if x ≥ –2
  • 11. a) What is the value of y when x = –4? Give two ways to find it. Piecewise Functions b) Which equation would you use to find the value of y when x = 2? c) Which equation would you use to find the value of y when x = –2? x 2 – 3 if x ≥ –2
  • 12.
  • 13. 2x + 1 if x ≤ 2 x 2 – 4 if x > 2 h(x) = Because –1 ≤ 2, use the rule for x ≤ 2 . Because 4 > 2, use the rule for x > 2. h(–1) = 2(–1) + 1 = –1 h(4) = 4 2 – 4 = 12 Evaluate the piecewise function for: x = –1 and x = 4.
  • 14. 3x 2 + 1 if x < 0 5x – 2 if x ≥ 0 g(x) = Because –1 < 0, use the rule for x < 0. Because 3 ≥ 0, use the rule for x ≥ 0. g(3) = 5(3) – 2 = 13 g(–1) = 3(–1) 2 + 1 = 4 Evaluate each piecewise function for: x = –1 and x = 3
  • 15. 12 if x < –3 20 if x ≥ 6 f(x) = Because –3 ≤ –1 < 6 , use the rule for – 3 ≤ x < 6 f(–1) = 15 Evaluate each piecewise function for: x = –1 and x = 3 15 if –3 ≤ x < 6 f(3) = 15 Because –3 ≤ 3 < 6 , use the rule for – 3 ≤ x < 6