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González Collazo
                                                        Karla Cristina

Problema 1: Ejercicio 7.25

1.> t.test(dato1)
        One Sample t-test
data: dato1
t = 62.3859, df = 23, p-value < 2.2e-16
alternative hypothesis: true mean is not equal to 0
95 percent confidence interval:
 59.8112 63.9138
sample estimates:
mean of x
  61.8625

2. > n=24
> mx=mean(dato1)= 61.8625

> s=sd(dato1)= 4.857877

> conf=.95

> gl=n-1= 23

> area=(1+conf)/2= 0.975

> t0=qt(area,gl)= 2.068658

> a=mx-t0*s/sqrt(n)= 59.8112

> b=mx+t0*s/sqrt(n)= 63.9138




Interpretación:
Problema 2: Ejercicio 7.31

1. > t.test(dato2)

        One Sample t-test

data: dato2
t = 10.109, df = 39, p-value = 1.881e-12
alternative hypothesis: true mean is not equal to 0
95 percent confidence interval:
 27.32181 40.99019

sample estimates:
mean of x
   34.156



2. > n=40

> mx=mean(dato2)= 34.156

> s=sd(dato2)= 21.36917

> conf=.95

> gl=n-1= 39

> area=(1+conf)/2= 0.975

> t0=qt(area,gl)= 2.022691

> a=mx-t0*s/sqrt(n)= 27.32181

> b=mx+t0*s/sqrt(n)= 40.99019




Interpretación:

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Esta 3042 primer trabajo entregar

  • 1. González Collazo Karla Cristina Problema 1: Ejercicio 7.25 1.> t.test(dato1) One Sample t-test data: dato1 t = 62.3859, df = 23, p-value < 2.2e-16 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: 59.8112 63.9138 sample estimates: mean of x 61.8625 2. > n=24 > mx=mean(dato1)= 61.8625 > s=sd(dato1)= 4.857877 > conf=.95 > gl=n-1= 23 > area=(1+conf)/2= 0.975 > t0=qt(area,gl)= 2.068658 > a=mx-t0*s/sqrt(n)= 59.8112 > b=mx+t0*s/sqrt(n)= 63.9138 Interpretación:
  • 2. Problema 2: Ejercicio 7.31 1. > t.test(dato2) One Sample t-test data: dato2 t = 10.109, df = 39, p-value = 1.881e-12 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: 27.32181 40.99019 sample estimates: mean of x 34.156 2. > n=40 > mx=mean(dato2)= 34.156 > s=sd(dato2)= 21.36917 > conf=.95 > gl=n-1= 39 > area=(1+conf)/2= 0.975 > t0=qt(area,gl)= 2.022691 > a=mx-t0*s/sqrt(n)= 27.32181 > b=mx+t0*s/sqrt(n)= 40.99019 Interpretación: