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Array Presentation (EngineerBaBu.com)
- 1. SEMINAR ON ARRAYS UNDER THE GUIDENCE OF- Ms. PINKI MA’M PREPARED BY- SAURABH SHUKLA & SAURABH VYAS B.E. 2 nd Yr. 1Vth Sem
- 3. 11/01/11 DECLARATION OF ONE DIMENSIONAL ARRAY Data_type var_name[Expression] Data Type is the type of elements to be stored in the array Var_name is the name of the array like any Other variables Expression specifies the number of elements to be stored In array Example int num[10]; Num[0] =data1 Num[1] =data2 Num[2] =data3 Num[3] =data4 Num[4] =data5 Num[5] =data6 Num[6] =data7 Num[7] =data8 Num[8] =data9 Num[9] =data10
- 4. 11/01/11 ACCESSING ONE DIMENSIONAL ARRAY ELEMENTS #<Include<stdio.h> #include<conio.h> Void main() { Int a[10]; Clrscr(); Printf (“enter the array”); For (i=0;i<10;i++) { Scanf(“%d”,&a[i]); } Printf(“the entered array is”); For(i=0;i<10;i++) { printf(“%d”,a[i]);} } getch(); } Arrray declaration Taking values from user Printing the values OUTPUT Enter the array 1 2 3 4 5 6 7 8 9 10 Entered array is 1 2 3 4 5 6 7 8 9 10
- 7. 11/01/11 INSERTION Int i,len,pos,num; Void main() { int a[10]; Void insert (int a[ ],int,int,int); Printf(“enter integers to be read”); Scanf(“%d”,&len); Printf(:enter ur array”); For(i=0;1<len;i++) { scanf(“%d”,&a[i]); } Printf(:enter position”); Scanf(“%d”,&pos); --pos; Printf(:enter integer to be inserted”); Scanf(“%d”,&num); Insert(a,len,pos,num);} For(i=len;1pos;i--) {a[i+1])=a[i]; } A{pos]=num; Len ++; Printf(“new array is ”); For(i=0;i<len;i++) { printf(“%d”,&a[i]); } } ORIGINAL ARRAY 1 2 3 4 5 6 7 8 HOW IT WORKS ENTER POSITION 4 ENTER NUM 9 DURING PROCESSING 1 2 3 …….. 4 5 6 7 8 NEW ARRAY 1 2 3 …9…. 4 5 6 7 8 THE ACTUAL 4 th POSITION
- 9. 11/01/11 DELETION Int i,n; Void main() { Int a[10],pos; Void delete(int a[ ],int,int); Printf(“enter no of elements in array”); Scanf(“%d”,&n); Printf(“enter ur array”); For(i=0;i<n;i++) Scanf(“%d”,&a[i]); Printf(:enter position”); Scanf(“%d”,&pos); --pos; delete(a[ ],pos,n); Void delete(int a [ ],int pos,int n) { int j item; Item =a[pos]; For(j=pos;j<n;j++) a[j]=a[j+1]; n=n-1; } For(i=0;i<n;i++) printf(“%d”,&a[i]); } HOW IT WORKS ORIGINAL ARRAY 1 2 3 4 5 6 7 8 ENTER POSITION 4 DURING PROCESSING 1 2 3 4 5 6 7 8 NEW ARRAY 1 2 3 5 6 7 8 THE ACTUAL 4 th POSITION
- 10. 11/01/11 ALGORITHM Letr LB be the lower bound andUB be the upper bound of linear array a 1. [initialize the counter] Set I at lower bound LB 2. Repeat for i=LB to UB [visit element]Display element a[i] [end of the loop] 3. EXIT TRAVERSING
- 11. 11/01/11 TRAVERSING AN ARRAY #include<stdio.h> Void main ( ) { Int i,n,a[10]; printf)(“enter length of the array”); Scanf(“%d”,&n); Printf(“enter ur array”); For(i=0;i<n;i++) Scanf(“%d”,&a [ i ]); Printf(“traversing the array”); For(i=0;i<n;i++) printf(“%d”,&a [ i ]); } OUTPUT 1 2 3 4 5 TRAVERSING THE ARRAY ENTER UR ARRAY 1 2 3 4 5 ENTER LENGTH OF ARRAY 5
- 13. 11/01/11 void main() { int a[10],b[10],c[10],i,j,k=0,l,m,n; cout<<"Enter sizeof array1 and array2” ; cin>>m>>n; cout<<"Enter elements of 1st:"; for(i=0;i<m;i++) {cin>>a[i];} cout<<"Elements of 2nd list:"; for(i=0;i<n;i++) {cin>>b[i];} for(i=0;i<m;i++) {c[i]=a[i];} for(j=0;j<n;j++) {c[j+m]=b[j];} for(i=0;i<(m+n);i++) {for(j=0;j<(m+n);j++) {if(c[i]<c[j]) {k=c[j]; c[j]=c[i]; c[i]=k; }}} cout<<"New merged array :"; for(i=0;i<(m+n);i++) {cout<<c[i]<<"";} } PROGRAM OUTPUT Enter size of array1 and array2 5 6 Enter elements of 1 st: 5 9 16 50 80 Elements of 2 nd list: 11 32 49 58 75 98 New merged array : 5 9 11 16 32 49 50 58 75 80 98
- 15. 11/01/11 SEARCHING Int i,n; Void main() { Int a[10],pos=-1,k; Printf(“enter no of elements in array”); Scanf(“%d”,&n); Printf(“enter ur array”); For(i=0;i<n;i++) Scanf(“%d”,&a[i]); Printf(:enter no. to be searched :”); Scanf(“%d”,&k); For(j=0;j<n;j++) {if (k==a[j]) {pos=i; break;} } If (pos>=0) printf(“%d is found in position %d”,k,pos+1); Else printf(“element does not exist”); getch(); } OUTPUT Enter no of elements in array: 6 Enter ur array: 10 20 30 40 50 60 Enter no to be searched : 50 50 is found in position 5 OUTPUT Enter no of elements in array: 6 Enter ur array: 10 20 30 40 50 60 Enter no to be searched : 45 Element does not exist
- 18. 11/01/11 PROGRAM #include<stdio.h> void main() { int a[10],i,n,j,x; printf("enter the value of n "); scanf("%d",&n); printf("enter array "); for(i=0;i<n;i++) { scanf("%d",&a[i]);} printf(" ur unsorted array is "); for(i=0;i<n;i++) { printf("%d ",a[i]);} for(i=0;i<n;i++) { for(j=0;j<n;j++) { if(a[j]>a[i]) { x=a[i]; a[i]=a[j]; a[j]=x; } } } printf(" ur sorted array is "); for(j=0;j<n;j++) {printf("%d ",a[j]);} } SELECTION SORTING
- 19. 11/01/11 interchange 16 13 15 EXAMPLE ENTERED ARRAY a[0] a[1] a[2] a[3] a[4] 6 PASS 1 13 16 6 2 15 PASS 2 13 16 15 2 6 PASS 3 16 13 15 2 6 PASS 4 15 13 16 2 6 PASS 5 13 2 6 16 15 2
- 21. 11/01/11 EXAMPLE > 11 13 ENTERED ARRAY a[0] a[1] a[2] a[3] a[4] 6 PASS 1 6 13 15 11 2 PASS 2 13 6 15 2 11 PASS 3 11 13 15 2 6 PASS 4 13 11 15 2 6 RESULT 13 2 6 11 15 2 < > > > < > < < > < < < < < < 15
- 23. 11/01/11 FROM SAURABH SHUKLA & SAURABH VYAS