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al loop is is attached to an axle with a handle as shown. The north pole of a magnet is placed I. A
metal below angular speed m a. On me ahe lop and the handle turned so that the loop rotates
counterclock wise at a constant two diagrams below, indicate the direction of the induced current
in the loop at each the instants shown. If the current is zero, state that explicitly. Explain how
yoru determined your answers Suppose the loop were replaced by a second loop that is identical
to the first except for a small cut in it (as shown). The loop is rotated as before i. How does the
maximum induced emf in the uncut b. Cut loop compare to the maximum induced emf in the cut
loop? Explain. How does the maximum induced current in the uncut loop compare to the
maximum induced current in the cut loop? Explain your reasoning. ii.
Solution
a) The EMF will be the same in both cases because they experience the same change in flux.
b) The maximum current in the cut loop will be much less than the maximum current in the
uncut loop because the gap acts as a resistor with very high resistance, causing a very low
induced current through the cut loop.

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  • 1. al loop is is attached to an axle with a handle as shown. The north pole of a magnet is placed I. A metal below angular speed m a. On me ahe lop and the handle turned so that the loop rotates counterclock wise at a constant two diagrams below, indicate the direction of the induced current in the loop at each the instants shown. If the current is zero, state that explicitly. Explain how yoru determined your answers Suppose the loop were replaced by a second loop that is identical to the first except for a small cut in it (as shown). The loop is rotated as before i. How does the maximum induced emf in the uncut b. Cut loop compare to the maximum induced emf in the cut loop? Explain. How does the maximum induced current in the uncut loop compare to the maximum induced current in the cut loop? Explain your reasoning. ii. Solution a) The EMF will be the same in both cases because they experience the same change in flux. b) The maximum current in the cut loop will be much less than the maximum current in the uncut loop because the gap acts as a resistor with very high resistance, causing a very low induced current through the cut loop.