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Heat Capacity
Work In
         Work done                        The work - energy principle
         on a system                       applies to all objects.

       v1                v2                 • If an object speeds up it
                                              gains kinetic energy.
 K1 = (1 / 2)mv12   K 2 = (1 / 2)mv2
                                   2

                                            • If an object slows down it
                                              loses kinetic energy.


                                                 ∆W = ∆K
Heat In
          Heat into a            Temperature change is due
          system                  to heat (Q).

                                  • If an object’s temperature
                                    increases it gains heat.
 T1 ,U1             T2 ,U 2
                                  • If an object’s temperature
                                    decreases it loses heat.


                                       ∆Q ∝ ∆T
Heat Capacity
   The ratio of the change in heat to the change in
    temperature is the heat capacity (C).
    •   Depends on material
    •   Depends on the mass
    •   Measured in J/K




        ∆Q = C∆ T
Specific Heat
   The ratio of the change in     Material   Specific heat
    heat to the change in          Mercury    140 J/kg-K
    temperature is the heat        Copper     390 J/kg-K
    capacity (C).
                                   Steel      500 J/kg-K
     •   Depends on material
     •   independent of the mass   Granite    840 J/kg-K
     •   Measured in J/kg-K        Aluminum   900 J/kg-K
                                   Wood       1400 J/kg-K
                                   Ice        2100 J/kg-K
         ∆Q = mc∆T                 Water      4200 J/kg-K
Take a Shower
   You are last to use the           Find the heat required.
    shower today and the                 ∆Q = mc∆T = (150 kg)
    temperature in the water              (4200 J/kg-K) ( 32 C)
    heater has dropped to 18 °C          ∆Q = 2.1 x 107 J
    from the normal temperature
    of 50 °C. The heater holds        Find the time from the
    150 kg and has a 50 kW
                                       power, and set the heat to
    heating coil.
                                       the work.
                                           P = ∆W/∆t
   How long should you wait               t = ∆Q / P
    before starting your shower?           (2.1 x 107 J) / (5 x 104 W)
                                           t = 4000 s = 1.1 hr
Equilibrium Temperature
   Two systems in thermal contact will adjust to reach
    the same temperature - thermal equilibrium

   If they are thermally insulated, all the heat goes from
    the hot system to the cold system.




         1      2           m1c1∆T1 + m2 c2 ∆T2 = 0
Doing Dishes
   A 1.5 kg aluminum pan is            Setup the equation for an
    heated to 180 °C then                unknown equilibrium
    placed into a sink with 8 kg         temperature T.
    water at 20 °C.                      m p c p (T − Tp ) + mwcw (Tw − T ) = 0

   If no water boils, what is the      Solve for T.
    equilibrium temperature?                  m p c pTp + mwcwTw
                                         T=
                                                m p c p + mwcw

                                        T = 26 °C


                                                                 next

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P210 13b

  • 2. Work In Work done  The work - energy principle on a system applies to all objects. v1 v2 • If an object speeds up it gains kinetic energy. K1 = (1 / 2)mv12 K 2 = (1 / 2)mv2 2 • If an object slows down it loses kinetic energy. ∆W = ∆K
  • 3. Heat In Heat into a  Temperature change is due system to heat (Q). • If an object’s temperature increases it gains heat. T1 ,U1 T2 ,U 2 • If an object’s temperature decreases it loses heat. ∆Q ∝ ∆T
  • 4. Heat Capacity  The ratio of the change in heat to the change in temperature is the heat capacity (C). • Depends on material • Depends on the mass • Measured in J/K ∆Q = C∆ T
  • 5. Specific Heat  The ratio of the change in Material Specific heat heat to the change in Mercury 140 J/kg-K temperature is the heat Copper 390 J/kg-K capacity (C). Steel 500 J/kg-K • Depends on material • independent of the mass Granite 840 J/kg-K • Measured in J/kg-K Aluminum 900 J/kg-K Wood 1400 J/kg-K Ice 2100 J/kg-K ∆Q = mc∆T Water 4200 J/kg-K
  • 6. Take a Shower  You are last to use the  Find the heat required. shower today and the  ∆Q = mc∆T = (150 kg) temperature in the water (4200 J/kg-K) ( 32 C) heater has dropped to 18 °C  ∆Q = 2.1 x 107 J from the normal temperature of 50 °C. The heater holds  Find the time from the 150 kg and has a 50 kW power, and set the heat to heating coil. the work.  P = ∆W/∆t  How long should you wait  t = ∆Q / P before starting your shower?  (2.1 x 107 J) / (5 x 104 W)  t = 4000 s = 1.1 hr
  • 7. Equilibrium Temperature  Two systems in thermal contact will adjust to reach the same temperature - thermal equilibrium  If they are thermally insulated, all the heat goes from the hot system to the cold system. 1 2 m1c1∆T1 + m2 c2 ∆T2 = 0
  • 8. Doing Dishes  A 1.5 kg aluminum pan is  Setup the equation for an heated to 180 °C then unknown equilibrium placed into a sink with 8 kg temperature T. water at 20 °C. m p c p (T − Tp ) + mwcw (Tw − T ) = 0  If no water boils, what is the  Solve for T. equilibrium temperature? m p c pTp + mwcwTw T= m p c p + mwcw  T = 26 °C next