2.60  kJ of heat is added to a slug of silver and a separate 2.60 kJ of heat is added to a slug of manganese. The heat capacity of the silver slug is 423J/°C while the heat capacity of the manganese slug is 925 J/°C. ???????If the slugs are each originally at 25.00°C, what is the final temperature of each slug? Solution Q = mc?T Q = heat energy (Joules, J), m = mass of a substance (kg) c = specific heat (units J/kg?K), ? is a symbol meaning \"the change in\" ?T = change in temperature (Kelvins, K) Let us take 100 gm of each silver and magnesise slug (because the weights are not given) For silver Q = 2.6 x10 3 Joules m = 100 gm Sp heat = 0.423J/°C 2.6 x10 3 = 100 x 0.423 x (Tf - 25) Final temperature = 86.46 Deg Cel For manganese Q = 2.6 x10 3 Joules m = 100 gm Sp heat = 0.925J/°C 2.6 x10 3 = 100 x 0.925 x (Tf - 25) Final temperature = 53.108 Deg Cel .

1. 2.60Â Â kJ of heat is added to a slug of silver and a separate 2.60 kJ of heat is added to a slug of
manganese. The heat capacity of the silver slug is 423J/°C while the heat capacity of the
manganese slug is 925 J/°C.
???????If the slugs are each originally at 25.00°C, what is the final temperature of each slug?
Solution
Q = mc?T
Q = heat energy (Joules, J), m = mass of a substance (kg)
c = specific heat (units J/kg?K), ? is a symbol meaning "the change in"
?T = change in temperature (Kelvins, K)
Let us take 100 gm of each silver and magnesise slug (because the weights are not given)
For silver
Q = 2.6 x10 3
Joules
m = 100 gm
Sp heat = 0.423J/°C
2.6 x10 3
= 100 x 0.423 x (Tf - 25)
Final temperature = 86.46 Deg Cel
For manganese
Q = 2.6 x10 3
Joules
m = 100 gm

2. Sp heat = 0.925J/°C
2.6 x10 3
= 100 x 0.925 x (Tf - 25)
Final temperature = 53.108 Deg Cel