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C02 atomic structure
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1-3b_Compounds Practice III. Answer the following questions about ions. 1. Write the reaction for the formation of a sulfide ion. 2. Why does the loss of electrons result in a positively charged ion? 3. What is the symbol for the ion with 44 protons and 41 electrons? 4. Determine the number of protons and electrons in Tl+3? 5. A chromium ion contains 20 electrons. What is the symbol? 6. Why will bismuth definitely form a cation?
Solution
I have solved the four question (2,3,4,5) as per Chegg guidelines. The question 1 is totally vague, since with what ions we need to form the sulfide ion, hence i have answered the four question, clear the ambiguity in Q1 and post it as another question with Q6
2) The loss of electron will lead to more number of protons than the number of electrons. Initially, the difference between number of electrons and number of protons is equal to zero
If there is a reduction in electron count, then the proton will dominate leading to the formation of positive charged ions
3) Ruthenium has the atomic number 44
Charge on Ruthenium = Number of protons - Number of electrons
=> 44 - 41
=> 3
Hence the symbol of the ion Ru(+3)
4)
Thallium has atomic number of 81
Number of protons = 81
Charge = Number of protons - Number of electrons
+3 = Number of protons - Number of electrons
Number of electrons = 78
Hence it contains 78 electrons and 81 protons
5)
Chromium has atomic number of 24
Charge = number of protons - number of electrons
=> 24 - 20
=> 4
Hence the charge on Chromium will be equal to +4
.

1-3b_Compounds Practice III. Answer the following questions about ions. 1. Write the reaction for the formation of a sulfide ion. 2. Why does the loss of electrons result in a positively charged ion? 3. What is the symbol for the ion with 44 protons and 41 electrons? 4. Determine the number of protons and electrons in Tl+3? 5. A chromium ion contains 20 electrons. What is the symbol? 6. Why will bismuth definitely form a cation?
Solution
I have solved the four question (2,3,4,5) as per Chegg guidelines. The question 1 is totally vague, since with what ions we need to form the sulfide ion, hence i have answered the four question, clear the ambiguity in Q1 and post it as another question with Q6
2) The loss of electron will lead to more number of protons than the number of electrons. Initially, the difference between number of electrons and number of protons is equal to zero
If there is a reduction in electron count, then the proton will dominate leading to the formation of positive charged ions
3) Ruthenium has the atomic number 44
Charge on Ruthenium = Number of protons - Number of electrons
=> 44 - 41
=> 3
Hence the symbol of the ion Ru(+3)
4)
Thallium has atomic number of 81
Number of protons = 81
Charge = Number of protons - Number of electrons
+3 = Number of protons - Number of electrons
Number of electrons = 78
Hence it contains 78 electrons and 81 protons
5)
Chromium has atomic number of 24
Charge = number of protons - number of electrons
=> 24 - 20
=> 4
Hence the charge on Chromium will be equal to +4
.

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