What are the respective central-metal oxidation state, coordination number, and overall charge on the complex ion in Na2[Cr(NH3)2 (NCS)4]? O +3, 6;+1 O +2, 4;-1 Submit Request Answer Solution Answer - We have the formula of the compound as Na 2 [Cr(NH 3 ) 2 (NCS) 4 ]. To find oxidation number we have to knnow that Na forms Na + in ionic state and NCS forms NCS - .NH 3 have no charge and neutral in the solution. Now, 0=2*1+x+3*0+4*(-1) x=2 ,Hence the oxidation state is +2. Coordination number - The number of compound in attach to the centra atom. Two NH3 and 4 NCS . Hence coordination number is 6. Overall charge =2+ of Na and (-4) of NCS molecules =-2 .