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Physics Helpline
L K Satapathy
Binomial Theorem 1
Binomial Theorem 1
Physics Helpline
L K Satapathy
1 2 2
0 1 2( ) ...n n n n n n n
a b C a C a b C a b 
    
1 2 2
0 1 2( ) ...n n n n n n n
a b C a C a b C a b 
    
 Subscript of C increases from 0 to n
 Power of a decreases from n to 0
 Power of b increases from 0 to n
 Sum of the powers of a and b = n
...n n r r n n
r nC a b C b
  
( 1) .. ( 1)r n n r r n n n
r nC a b C b
    
Binomial Theorem 1
Physics Helpline
L K Satapathy
2
0 1 2(1 ) ...n n n n n n
nx C C x C x C x     
2
0 1 2(1 ) .. ( 1)n n n n n n n
nx C C x C x C x      
0 1 21 (1 1) ...n n n n n
nx C C C C        
0 1 2 3 41 0 . . .n n n n n
x C C C C C       
0 2 4 1 3 5( . . . ) ( . . . )n n n n n n
C C C C C C      
 Sum of odd coefficients = Sum of even coefficients
0
2
n
n n
r
r
C

 
Binomial Theorem 1
Physics Helpline
L K Satapathy
1 2 2
0 1 2( ) ...n n n n n n n n n
na b C a C a b C a b C b 
     
 ( r + 1)th term 1 . .n n r r
r rt C a b
 
Subscript of C = r
Power of a = n – r
Power of b = r
1st term = 0
0. .n n
C a b
2nd term = 1 1
1. .n n
C a b
3rd term = 2 2
2. .n n
C a b
The General Term
Binomial Theorem 1
Physics Helpline
L K Satapathy
m terms on either side of the middle term
 ( 1) 1
2
th
th nThe middle term m term term    
Middle Term (s)
1 2 1 ( )Number of terms n m odd     
Power of (a + x) = n  Number of terms = n +1
When n is even : 2
2
nWe put n m m  
1We get middle term
Illustration
n = 12  13 terms : 1 2 3 4 5 6 7 8 9 10 11 12 13
6 Terms
on Left
6 Terms
on RightMiddle term
Binomial Theorem 1
Physics Helpline
L K Satapathy
2 ( 1) ( 2)th th
The middle terms m and m terms   
When n is odd : 12 1
2
nWe put n m m    
1 2 2 ( )Number of terms n m even     
2We get middle terms
2m terms on either side of the middle terms
   1 3,
2 2
th th
n n terms 
Illustration
n = 13  14 terms : 1 2 3 4 5 6 7 8 9 10 11 12 13 14
6 Terms
on Left
6 Terms
on Right2 Middle terms
Physics Helpline
L K Satapathy
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Binomial Theorem Explained in 40 Characters

  • 1. Physics Helpline L K Satapathy Binomial Theorem 1
  • 2. Binomial Theorem 1 Physics Helpline L K Satapathy 1 2 2 0 1 2( ) ...n n n n n n n a b C a C a b C a b       1 2 2 0 1 2( ) ...n n n n n n n a b C a C a b C a b        Subscript of C increases from 0 to n  Power of a decreases from n to 0  Power of b increases from 0 to n  Sum of the powers of a and b = n ...n n r r n n r nC a b C b    ( 1) .. ( 1)r n n r r n n n r nC a b C b     
  • 3. Binomial Theorem 1 Physics Helpline L K Satapathy 2 0 1 2(1 ) ...n n n n n n nx C C x C x C x      2 0 1 2(1 ) .. ( 1)n n n n n n n nx C C x C x C x       0 1 21 (1 1) ...n n n n n nx C C C C         0 1 2 3 41 0 . . .n n n n n x C C C C C        0 2 4 1 3 5( . . . ) ( . . . )n n n n n n C C C C C C        Sum of odd coefficients = Sum of even coefficients 0 2 n n n r r C   
  • 4. Binomial Theorem 1 Physics Helpline L K Satapathy 1 2 2 0 1 2( ) ...n n n n n n n n n na b C a C a b C a b C b         ( r + 1)th term 1 . .n n r r r rt C a b   Subscript of C = r Power of a = n – r Power of b = r 1st term = 0 0. .n n C a b 2nd term = 1 1 1. .n n C a b 3rd term = 2 2 2. .n n C a b The General Term
  • 5. Binomial Theorem 1 Physics Helpline L K Satapathy m terms on either side of the middle term  ( 1) 1 2 th th nThe middle term m term term     Middle Term (s) 1 2 1 ( )Number of terms n m odd      Power of (a + x) = n  Number of terms = n +1 When n is even : 2 2 nWe put n m m   1We get middle term Illustration n = 12  13 terms : 1 2 3 4 5 6 7 8 9 10 11 12 13 6 Terms on Left 6 Terms on RightMiddle term
  • 6. Binomial Theorem 1 Physics Helpline L K Satapathy 2 ( 1) ( 2)th th The middle terms m and m terms    When n is odd : 12 1 2 nWe put n m m     1 2 2 ( )Number of terms n m even      2We get middle terms 2m terms on either side of the middle terms    1 3, 2 2 th th n n terms  Illustration n = 13  14 terms : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 6 Terms on Left 6 Terms on Right2 Middle terms
  • 7. Physics Helpline L K Satapathy For More details: www.physics-helpline.com Subscribe our channel: youtube.com/physics-helpline Follow us on Facebook and Twitter: facebook.com/physics-helpline twitter.com/physics-helpline