Problem 7 write a code that will ask the user to input a vector of val.docx

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Problem 7 write a code that will ask the user to input a vector of values F. Then calculate the number of positive and negative values in that vector. Don\'t use any built-in functions (eag sum, find, abs, max, min, etc Example: (four positive values [3 8 1910 N-3 (three negative values [-2 -4 -7 l) Solution import java.util.Scanner; public class JavaProgram { public static void main(String args[]) { int countp=0, countn=0, countz=0, i; int arr[] = new int[10]; Scanner scan = new Scanner(System.in); System.out.print(\"Enter 10 Numbers : \"); for(i=0; i<10; i++) { arr[i] = scan.nextInt(); } for(i=0; i<10; i++) { if(arr[i] < 0) { countn++; } else if(arr[i] == 0) { countz++; } else { countp++; } } System.out.print(countp + \" Positive Numbers\"); System.out.print(\"\ \" + countn + \" Negative Numbers\"); System.out.print(\"\ \" + countz + \" Zero\"); } } .

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// Problem1 java code import java.util.Scanner; // Java code to print all possible strings of letter L and R class Problem1 { static void print(char set[], int length) { int setLength = set.length; printRecursion(set, \"\", setLength, length); } static void printRecursion(char set[], String prefixset, int setLength, int length) { // Base case: length is 0 if (length == 0) { System.out.println(prefixset); return; } for (int i = 0; i < setLength; ++i) { String newPrefixset = prefixset + set[i]; printRecursion(set, newPrefixset, setLength, length - 1); } } public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter length: \"); int length = scan.nextInt(); char set[] = {\'L\', \'R\'}; print(set, length); } } /* output: Enter length: 3 LLL LLR LRL LRR RLL RLR RRL RRR */ // Problem2 java code import java.util.Scanner; // Java code to print all possible strings of letter L and R class Problem2 { static void print(char set[], int length) { int setLength = set.length; printRecursion(set, \"\", setLength, length); } static void printRecursion(char set[], String prefixset, int setLength, int length) { // Base case: length is 0 if (length == 0) { System.out.print(prefixset + \" \"); return; } for (int i = 0; i < setLength; ++i) { String newPrefixset = prefixset + set[i]; printRecursion(set, newPrefixset, setLength, length - 1); } } public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter length: \"); int length = scan.nextInt(); char set[] = {\'1\', \'3\', \'5\', \'7\', \'9\'}; print(set, length); System.out.println(); } } /* output: Enter length: 3 111 113 115 117 119 131 133 135 137 139 151 153 155 157 159 171 173 175 177 179 191 193 195 197 199 311 313 315 317 319 331 333 335 337 339 351 353 355 357 359 371 373 375 377 379 391 393 395 397 399 511 513 515 517 519 531 533 535 537 539 551 553 555 557 559 571 573 575 577 579 591 593 595 597 599 711 713 715 717 719 731 733 735 737 739 751 753 755 757 759 771 773 775 777 779 791 793 795 797 799 911 913 915 917 919 931 933 935 937 939 951 953 955 957 959 971 973 975 977 979 991 993 995 997 999 */ // Problem3 java code import java.util.Scanner; // Java code to multiply 2 numbers class Problem3 { public static int multiply(int a, int b) { int temp = b; for (int i = 1; i < a; i++ ) { b = b + temp; } return b; } public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter a: \"); int a = scan.nextInt(); System.out.println(\"Enter b: \"); int b = scan.nextInt(); System.out.println(a + \"X\" + b + \" = \" + multiply(a,b)); } } /* output: Enter a: 7 Enter b: 6 7X6 = 42 */ // Problem4 java code import java.util.Scanner; // Java code to find gcd 2 numbers class Problem4 { public static int gcd(int a, int b) { if (b!=0) return gcd(b, a%b); else return a; } public static void main(String[] args) { Scanner scan=new Scanner(System.in); System.out.println(\"Enter a: \"); int a = scan.ne.

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CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print(\"Input num : \"); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print(\"Input num : \"); num=input.nextInt(); } sum=sum+num; System.out.println(\"Sum = \"+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5 Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num : 0 Input num : 13 Sum = 58 Solution CODE: import java.util.*; public class test { public static void main(String args[]) { int num, sum=0; Scanner input=new Scanner(System.in); System.out.print(\"Input num : \"); num=input.nextInt(); while(num != 13) { sum=sum+num; System.out.print(\"Input num : \"); num=input.nextInt(); } sum=sum+num; System.out.println(\"Sum = \"+sum); } } save the above file as test.java Output: javac test.java java test Input num : 1 Input num : 2 Input num : 3 Input num : 4 Input num : 5 Input num : 6 Input num : 7 Input num : 8 Input num : 9 Input num : 0 Input num : 13 Sum = 58.

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The internal rate of return (IRR) refers to the compound annual rate of return that a project generates based on its up-front cost and subsequent cash flows. Consider the case of Blue Llama Mining Company: Blue Llama Mining Company is evaluating a proposed capital budgeting project (project Sigma) that will require an initial investment of $850,000. Blue Llama Mining Company has been basing capital budgeting decisions on a projects NPV; however, its new CFO wants to start using the IRR method for capital budgeting decisions. The CFO says that the IRR is a better method because returns in percentage form are easier to understand and compare to required returns. Blue Llama Mining Companys WACC is 8%, and project Sigma has the same risk as the firms average project. The project is expected to generate the following net cash flows: Which of the following is the correct calculation of project Sigmas IRR? 24.78% 33.04% 27.53% 31.66% If this is an independent project, the IRR method states that the firm should . If the projects cost of capital were to increase, how would that affect the IRR? The IRR would increase. The IRR would decrease. The IRR would not change.YearCash FlowYear 1$300,000Year 2$425,000Year 3$400,000Year 4$425,000.

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import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } } Solution import java.util.Scanner; public class Digits { public static void main(String[] args) { int oddCount = 0, evenCount = 0, zeroCount = 0; //digit counters int value, digit; //stores input value and digit respectively int copy; //stores copy of entry Scanner scan = new Scanner(System.in); //Get value from user System.out.println(\"enter number :\"); int value=scan.nextInt(); copy=value; //Make the value positive value=Math.abs(value); //What if the value is actually zero? if(value==0) zeroCount++; while(value>0) { digit=value10; if(digit==0) zerocount++; if(digit%2==0) evenCount++; else oddCount++; value=value/10; } System.out.println(\"original value:\"+copy); System.out.println(\"zero digits :\"+zeroCount); System.out.println(\"odd digits :\"+oddCount); System.out.println(\"even digits :\"+evenCount) } }.

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An IP datagram has arrived with the following information in the header(hex): 45000054 00030000 2006... A.) What is the header size? B.) Are there any options in the packet? C.)What is the size of the data? D.)Is the packet fragmented? E.)How many more routers can the packet travel to? F.)What is the protocol number of the payload being carried by the packet? Solution Answer: We have given IP datagram derived with the information in Hex : 45000054 00030000 2006 Now , here we divide this information as the following : A) Size of the header = 5 x 4 bytes = 20 Bytes B) No, As you can see above C) Length of the data = Total Length - HLEN = 84 - 20 = 64 Bytes D) Yes E) 32 Hops , so 32 routers . The last router will discard the datagram. .

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