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Exercice 22

            Ax :n = 1 − d · ax :n
                            ¨
                    1 − Ax :n     1 − 0, 54312909
                d=              =                         0, 0610328634
                       ¨
                      ax :n         7, 4856542

   Comme d =     i
                1+i
                    ,   on obtient :

                                       i = d(1 + i)
                                       i = d + id
                                i(1 − d) = d
                                             d
                                       i=
                                            1−d
   Donc :
                     0, 0610328634
              i=                          0, 065      →     i = 6, 5%
                   1 − 0, 0610328634

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Ch40 22

  • 1. Exercice 22 Ax :n = 1 − d · ax :n ¨ 1 − Ax :n 1 − 0, 54312909 d= = 0, 0610328634 ¨ ax :n 7, 4856542 Comme d = i 1+i , on obtient : i = d(1 + i) i = d + id i(1 − d) = d d i= 1−d Donc : 0, 0610328634 i= 0, 065 → i = 6, 5% 1 − 0, 0610328634