Rewrite the function fx-2x2+8x+7 in standard form and find the followi.docx

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Rewrite the function fx=2x2+8x+7 in standard form and find the following: 1.) Standard form 2.) the vertex 3.) the x intercepts 4.) the y intercepts 5.) the maximum or minimum Solution fx=2x^2 + 8x +7....let fx=y.. so , y=2x^2+8x+7 y-7=2(x^2+4x+4-4) y-7=2((x+2)^2)-8 y+1=2(x+2)^2....................standard form....... vertex is (-2,-1)..... x intercepts= -2 - 1/2 and -2 + 1/2............. y intercepts= 7.............. now, y\'= 4x + 8=0..... so, x=-2...which is point of minima....as y\'\' is positive.... therefore minimum valu is f(-2)= -1............and max value is .............. .

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Rewrite the function fx-2x2+8x+7 in standard form and find the followi.docx

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