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Perimeter, Circumference
and Area
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Perimeter and Circumference
 Perimeter : The distance around a geometric
figure.
 Circumference: The distance around a circle.
Perimeter
 To find perimeter add the lengths of all the
sides.
– Example: Find the perimeter of the polygon
8 in
6 in
8 in
6 in
P = 8 + 8 + 6 + 6
P = 28
The perimeter is 28 in
Perimeter
– Example : Find the perimeter of the triangle
12 in
12 in
16 in
P = 12 + 12 + 16
P = 40
The perimeter is 40 in
Your Turn…. Find the perimeter
 pg. 426 #1-3 ( 3 minutes)
 Make sure that there are no naked numbers.
1. P = 6 + 4 + 8
P = 18m
2. P = 7 + 5 + 5 + 7
P = 24in
3. P = 8 + 8 + 8 + 8
P = 32 ft
Circumference
 To find the circumference multiply times
diameter, where is 3.14
C = d
Diameter
π
π
π
Definitions
 Diameter (d): a line that passes through the
center of a circle
 Radius (r): half the diameter
 d = 20, then r = 10
 r = 15, then d = 30
Circumference
 Example: Find the
circumference
Diameter = 8 in
Circumference = d
C = 3.14(8)
C = 25.12
The circumference is 25.12 in
π
Circumference
Example: Find the circumference
radius = 10 cm
Circumference = d
Diameter = 2r = 2 (10) = 20
C = 3.14(20)
C = 62.8
The circumference is 62.8 cm
π
Your Turn…. Find the circumference
 pg. 426 # 7-9
 No naked numbers.
7. C = d 8. C = d
C = 3.14(12) C = 3.14(3)
C = 37.7m C = 9.4 ft
9. C = d
C = 3.14 (16)
C = 50. 2 in
π π
π
Area of Rectangles
 The area of a rectangle is the product of its length
and width.
A = ω
ω

Area of Rectangles
 Find the area of the rectangle
10 ft
7.5 in
A = ω
A = 10(7.5)
A = 75 ft²
The area is 75 ft²

Area of Triangles
 The area of a triangle is half the product of its
base b and its height h.
A = bh
height
base
2
1
Area of Triangles
 Example: Find the area of the triangle
2
1
6 in
5 in
A = bh
A = 5(6)
A = 15 in²
2
1
Area of Circles
 The area of a circle is the product of and the
square of the circle’s radius r.
A = r²
radius
π
π
Area of Circles
 Example: Find the area
of the circle
r = 3 m
A = r²
A = 3.14(3)²
A = 3.14(9)
A = 28.26 m²
The area of the circle is
28.26m²
π
Area of Circles
d = 8 in
A = r²
Radius = 4 in
A = 3.14(4)²
A = 3.14(16)
A = 50.24 in²
The area of the
circle is 50.24in²
π
Lets Review
 Perimeter = Sum of all sides
 Circumference = d
 Area of a Rectangle = ω
 Area of a Triangle = bh
 Area of a Circle = r²
π

2
1
π

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Perimeter area circumference

  • 2. Perimeter and Circumference  Perimeter : The distance around a geometric figure.  Circumference: The distance around a circle.
  • 3. Perimeter  To find perimeter add the lengths of all the sides. – Example: Find the perimeter of the polygon 8 in 6 in 8 in 6 in P = 8 + 8 + 6 + 6 P = 28 The perimeter is 28 in
  • 4. Perimeter – Example : Find the perimeter of the triangle 12 in 12 in 16 in P = 12 + 12 + 16 P = 40 The perimeter is 40 in
  • 5. Your Turn…. Find the perimeter  pg. 426 #1-3 ( 3 minutes)  Make sure that there are no naked numbers. 1. P = 6 + 4 + 8 P = 18m 2. P = 7 + 5 + 5 + 7 P = 24in 3. P = 8 + 8 + 8 + 8 P = 32 ft
  • 6. Circumference  To find the circumference multiply times diameter, where is 3.14 C = d Diameter π π π
  • 7. Definitions  Diameter (d): a line that passes through the center of a circle  Radius (r): half the diameter  d = 20, then r = 10  r = 15, then d = 30
  • 8. Circumference  Example: Find the circumference Diameter = 8 in Circumference = d C = 3.14(8) C = 25.12 The circumference is 25.12 in π
  • 9. Circumference Example: Find the circumference radius = 10 cm Circumference = d Diameter = 2r = 2 (10) = 20 C = 3.14(20) C = 62.8 The circumference is 62.8 cm π
  • 10. Your Turn…. Find the circumference  pg. 426 # 7-9  No naked numbers. 7. C = d 8. C = d C = 3.14(12) C = 3.14(3) C = 37.7m C = 9.4 ft 9. C = d C = 3.14 (16) C = 50. 2 in π π π
  • 11. Area of Rectangles  The area of a rectangle is the product of its length and width. A = ω ω 
  • 12. Area of Rectangles  Find the area of the rectangle 10 ft 7.5 in A = ω A = 10(7.5) A = 75 ft² The area is 75 ft² 
  • 13. Area of Triangles  The area of a triangle is half the product of its base b and its height h. A = bh height base 2 1
  • 14. Area of Triangles  Example: Find the area of the triangle 2 1 6 in 5 in A = bh A = 5(6) A = 15 in² 2 1
  • 15. Area of Circles  The area of a circle is the product of and the square of the circle’s radius r. A = r² radius π π
  • 16. Area of Circles  Example: Find the area of the circle r = 3 m A = r² A = 3.14(3)² A = 3.14(9) A = 28.26 m² The area of the circle is 28.26m² π
  • 17. Area of Circles d = 8 in A = r² Radius = 4 in A = 3.14(4)² A = 3.14(16) A = 50.24 in² The area of the circle is 50.24in² π
  • 18. Lets Review  Perimeter = Sum of all sides  Circumference = d  Area of a Rectangle = ω  Area of a Triangle = bh  Area of a Circle = r² π  2 1 π