SlideShare a Scribd company logo
1 of 46
Solving Quadratic
    Equations
       PART 2
Solving Quadratic Equations when they
         do NOT equal ZERO
• So far all the quadratic equations we’ve solve have
  been equal to zero but not all are so nice. If they
  don’t equal zero, make them equal to zero!
• View this Cool Math website to how to solve
  Quadratic Equations when the original equation is
  not equal to 0.
• There are 3 pages to view.
• Complete the Your Turn problems in your notebook
  and check your answers on the next slide.
Page 1 - Finish it
• Solve.        2
               x − 3x − 18 = 0
Page 1 - Finish it
• Solve.         2
               x − 3x − 18 = 0

               ( x + 3) ( x − 6 ) = 0
Page 1 - Finish it
• Solve.         2
                x − 3x − 18 = 0

               ( x + 3) ( x − 6 ) = 0
            x+3= 0      or     x−6=0
Page 1 - Finish it
• Solve.         2
                x − 3x − 18 = 0

               ( x + 3) ( x − 6 ) = 0
            x+3= 0      or     x−6=0
             −3 −3               +6     +6
Page 1 - Finish it
• Solve.         2
                x − 3x − 18 = 0

               ( x + 3) ( x − 6 ) = 0
            x+3= 0      or     x−6=0
             −3 −3               +6     +6

             x = −3     or     x=6
Page 1 - Finish it
• Solve.         2
                x − 3x − 18 = 0

               ( x + 3) ( x − 6 ) = 0
            x+3= 0      or     x−6=0
             −3 −3               +6     +6

             x = −3     or     x=6

                                  Answer:    {−3, 6}
Page 1 - Your Turn
              2
• Solve.     x + 7x = 170
Page 1 - Your Turn
              2
• Solve.     x + 7x = 170
              −170   −170
Page 1 - Your Turn
                 2
• Solve.     x + 7x = 170
                 −170   −170
             2
            x + 7x − 170 = 0
Page 1 - Your Turn
                   2
• Solve.        x + 7x = 170
                   −170       −170
               2
              x + 7x − 170 = 0
           ( x + 17 ) ( x − 10 ) = 0
Page 1 - Your Turn
                   2
• Solve.        x + 7x = 170
                   −170       −170
               2
              x + 7x − 170 = 0
           ( x + 17 ) ( x − 10 ) = 0
   x + 17 = 0          or     x − 10 = 0
Page 1 - Your Turn
                   2
• Solve.        x + 7x = 170
                   −170       −170
               2
              x + 7x − 170 = 0
           ( x + 17 ) ( x − 10 ) = 0
   x + 17 = 0          or     x − 10 = 0
     −17 −17                     +10 +10
Page 1 - Your Turn
                   2
• Solve.        x + 7x = 170
                   −170       −170
               2
              x + 7x − 170 = 0
           ( x + 17 ) ( x − 10 ) = 0
   x + 17 = 0          or     x − 10 = 0
     −17 −17                     +10 +10
      x = −17          or      x = 10
Page 1 - Your Turn
                   2
• Solve.        x + 7x = 170
                   −170       −170
               2
              x + 7x − 170 = 0
           ( x + 17 ) ( x − 10 ) = 0
   x + 17 = 0          or     x − 10 = 0
     −17 −17                     +10 +10
      x = −17          or      x = 10
                                           Answer:   {−17,10}
Page 2 - Finish it
• Solve.     2
           2x − 5x − 3 = 0
Page 2 - Finish it
• Solve.        2
             2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
Page 2 - Finish it
• Solve.        2
             2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
Page 2 - Finish it
• Solve.        2
             2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
           −1 −1                +3 +3
Page 2 - Finish it
• Solve.        2
             2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
           −1 −1                +3 +3
           2x = −1     or       x=3
Page 2 - Finish it
• Solve.         2
               2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
           −1 −1                 +3 +3
           2x = −1     or       x=3
           2      2
Page 2 - Finish it
• Solve.         2
               2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
           −1 −1                 +3 +3
           2x = −1     or       x=3
           2      2
           x = − 12
Page 2 - Finish it
• Solve.         2
               2x − 5x − 3 = 0

           ( 2x + 1) ( x − 3) = 0
      2x + 1 = 0       or     x−3= 0
           −1 −1                 +3 +3
           2x = −1     or       x=3
           2      2
           x = − 12
                                            ⎧ 1 ⎫
                                    Answer: ⎨− , 3⎬
                                            ⎩ 2 ⎭
Page 2 - Your Turn
• Solve.                2
            11x + 6 − 10x = 0
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
                    2
                 10x − 11x − 6 = 0
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
                    2
                 10x − 11x − 6 = 0
             ( 5x + 2 ) ( 2x − 3) = 0
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
                    2
                 10x − 11x − 6 = 0
             ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0        or            2x − 3 = 0
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
                    2
                 10x − 11x − 6 = 0
             ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0        or            2x − 3 = 0
             −2 −2                       +3 +3
Page 2 - Your Turn
• Solve.     11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x   2
                                  ) = 0 ⋅ −1
                                  2
              −11x − 6 + 10x = 0
                    2
                 10x − 11x − 6 = 0
             ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0        or            2x − 3 = 0
             −2 −2                       +3 +3
            5x = −2      or           2x = 3
Page 2 - Your Turn
• Solve.        11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x      2
                                     ) = 0 ⋅ −1
                                     2
                −11x − 6 + 10x = 0
                        2
                  10x − 11x − 6 = 0
                ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0            or           2x − 3 = 0
             −2 −2                            +3 +3
            5x = −2         or           2x = 3
            5       5                     2     2
Page 2 - Your Turn
• Solve.        11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x      2
                                     ) = 0 ⋅ −1
                                     2
                −11x − 6 + 10x = 0
                        2
                  10x − 11x − 6 = 0
                ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0            or           2x − 3 = 0
             −2 −2                            +3 +3
            5x = −2         or           2x = 3
            5       5                     2        2
            x = −25         or           x=    3
                                                   2
Page 2 - Your Turn
• Solve.        11x + 6 − 10x = 02


             (
           −1 11x + 6 − 10x      2
                                     ) = 0 ⋅ −1
                                     2
                −11x − 6 + 10x = 0
                        2
                  10x − 11x − 6 = 0
                ( 5x + 2 ) ( 2x − 3) = 0
      5x + 2 = 0            or           2x − 3 = 0
             −2 −2                            +3 +3
            5x = −2         or           2x = 3
            5       5                     2        2           ⎧ 2 3 ⎫
                                                       Answer: ⎨− , ⎬
            x = −25         or           x=    3
                                                   2           ⎩ 5 2 ⎭
Page 3 - Your Turn
                         3
• Solve.    −16x = −4x
Page 3 - Your Turn
                            3
• Solve.      −16x = −4x
           +4x 3    +4x 3
Page 3 - Your Turn
                             3
• Solve.      −16x = −4x
           +4x 3     +4x 3
              3
           4x − 16x = 0
Page 3 - Your Turn
                                   3
• Solve.      −16x = −4x
           +4x 3           +4x 3
              3
           4x − 16x = 0
             (     2
           4x x − 4 = 0)
Page 3 - Your Turn
                                    3
• Solve.       −16x = −4x
            +4x 3           +4x 3
               3
            4x − 16x = 0
              (     2
           4x x − 4 = 0 )
  4x ( x + 2 ) ( x − 2 ) = 0
Page 3 - Your Turn
                                    3
• Solve.       −16x = −4x
            +4x 3           +4x 3
               3
            4x − 16x = 0
              (     2
           4x x − 4 = 0 )
  4x ( x + 2 ) ( x − 2 ) = 0
  4x = 0     or         x+2=0           or   x−2=0
Page 3 - Your Turn
                                     3
• Solve.       −16x = −4x
            +4x 3            +4x 3
               3
            4x − 16x = 0
              (     2
            4x x − 4 = 0)
  4x ( x + 2 ) ( x − 2 ) = 0
  4x = 0     or         x+2=0            or   x−2=0
  4     4                   −2 −2              +2 +2
Page 3 - Your Turn
                                     3
• Solve.       −16x = −4x
            +4x 3            +4x 3
               3
            4x − 16x = 0
              (     2
            4x x − 4 = 0)
  4x ( x + 2 ) ( x − 2 ) = 0
  4x = 0     or         x+2=0            or    x−2=0
  4     4                   −2 −2               +2 +2
   x=0        or            x = −2        or     x=2
Page 3 - Your Turn
                                     3
• Solve.       −16x = −4x
            +4x 3            +4x 3
               3
            4x − 16x = 0
              (     2
            4x x − 4 = 0)
  4x ( x + 2 ) ( x − 2 ) = 0
  4x = 0     or         x+2=0            or    x−2=0
  4     4                   −2 −2               +2 +2
   x=0        or            x = −2        or     x=2
                                                  Answer:   {0, −2, 2}
Do you want to Play a GAME?
• Check your knowledge on solving Quadratic
  Equations by playing Jeopardy. Ok, technically it’s
  called Challenge Board but it’s the same idea!
• You have the option to play alone or against a
  friend or maybe a family member!
• You could even arrange a time with a classmate to
  meet on Pronto to play. Try the App Share feature
  to see the same game board!
• Finding the x-intercepts is the same as solving!
Fantastic Job!
• You’ve finished reviewing Solving Quadratic
  Equations Part 2.

• Exit and proceed
  to the Homework
  Assignment.

More Related Content

More from Lori Rapp

Normal curve
Normal curveNormal curve
Normal curveLori Rapp
 
Venn diagrams
Venn diagramsVenn diagrams
Venn diagramsLori Rapp
 
Circles notes
Circles notesCircles notes
Circles notesLori Rapp
 
Quadrilateral notes
Quadrilateral notesQuadrilateral notes
Quadrilateral notesLori Rapp
 
Remainder & Factor Theorems
Remainder & Factor TheoremsRemainder & Factor Theorems
Remainder & Factor TheoremsLori Rapp
 
Multiplying polynomials - part 1
Multiplying polynomials - part 1Multiplying polynomials - part 1
Multiplying polynomials - part 1Lori Rapp
 
Develop the Area of a Circle Formula
Develop the Area of a Circle FormulaDevelop the Area of a Circle Formula
Develop the Area of a Circle FormulaLori Rapp
 
Unit 4 hw 8 - pointslope, parallel & perp
Unit 4   hw 8 - pointslope, parallel & perpUnit 4   hw 8 - pointslope, parallel & perp
Unit 4 hw 8 - pointslope, parallel & perpLori Rapp
 
Absolute Value Inequalities Notes
Absolute Value Inequalities NotesAbsolute Value Inequalities Notes
Absolute Value Inequalities NotesLori Rapp
 
Compound Inequalities Notes
Compound Inequalities NotesCompound Inequalities Notes
Compound Inequalities NotesLori Rapp
 
Solving Inequalities Notes
Solving Inequalities NotesSolving Inequalities Notes
Solving Inequalities NotesLori Rapp
 
Solving quadratic equations part 1
Solving quadratic equations part 1Solving quadratic equations part 1
Solving quadratic equations part 1Lori Rapp
 
Introduction to Equations Notes
Introduction to Equations NotesIntroduction to Equations Notes
Introduction to Equations NotesLori Rapp
 
Associative property
Associative propertyAssociative property
Associative propertyLori Rapp
 
Real numbers
Real numbersReal numbers
Real numbersLori Rapp
 
Unit 4 hw 7 - direct variation & linear equation give 2 points
Unit 4   hw 7 - direct variation & linear equation give 2 pointsUnit 4   hw 7 - direct variation & linear equation give 2 points
Unit 4 hw 7 - direct variation & linear equation give 2 pointsLori Rapp
 
Absolute Value Equations
Absolute Value EquationsAbsolute Value Equations
Absolute Value EquationsLori Rapp
 
Unit 3 hw 7 - literal equations
Unit 3   hw 7 - literal equationsUnit 3   hw 7 - literal equations
Unit 3 hw 7 - literal equationsLori Rapp
 
Unit 3 hw 4 - solving equations variable both sides
Unit 3   hw 4 - solving equations variable both sidesUnit 3   hw 4 - solving equations variable both sides
Unit 3 hw 4 - solving equations variable both sidesLori Rapp
 

More from Lori Rapp (20)

Normal curve
Normal curveNormal curve
Normal curve
 
Venn diagrams
Venn diagramsVenn diagrams
Venn diagrams
 
Circles notes
Circles notesCircles notes
Circles notes
 
Quadrilateral notes
Quadrilateral notesQuadrilateral notes
Quadrilateral notes
 
Remainder & Factor Theorems
Remainder & Factor TheoremsRemainder & Factor Theorems
Remainder & Factor Theorems
 
Multiplying polynomials - part 1
Multiplying polynomials - part 1Multiplying polynomials - part 1
Multiplying polynomials - part 1
 
Develop the Area of a Circle Formula
Develop the Area of a Circle FormulaDevelop the Area of a Circle Formula
Develop the Area of a Circle Formula
 
Unit 4 hw 8 - pointslope, parallel & perp
Unit 4   hw 8 - pointslope, parallel & perpUnit 4   hw 8 - pointslope, parallel & perp
Unit 4 hw 8 - pointslope, parallel & perp
 
Sets Notes
Sets NotesSets Notes
Sets Notes
 
Absolute Value Inequalities Notes
Absolute Value Inequalities NotesAbsolute Value Inequalities Notes
Absolute Value Inequalities Notes
 
Compound Inequalities Notes
Compound Inequalities NotesCompound Inequalities Notes
Compound Inequalities Notes
 
Solving Inequalities Notes
Solving Inequalities NotesSolving Inequalities Notes
Solving Inequalities Notes
 
Solving quadratic equations part 1
Solving quadratic equations part 1Solving quadratic equations part 1
Solving quadratic equations part 1
 
Introduction to Equations Notes
Introduction to Equations NotesIntroduction to Equations Notes
Introduction to Equations Notes
 
Associative property
Associative propertyAssociative property
Associative property
 
Real numbers
Real numbersReal numbers
Real numbers
 
Unit 4 hw 7 - direct variation & linear equation give 2 points
Unit 4   hw 7 - direct variation & linear equation give 2 pointsUnit 4   hw 7 - direct variation & linear equation give 2 points
Unit 4 hw 7 - direct variation & linear equation give 2 points
 
Absolute Value Equations
Absolute Value EquationsAbsolute Value Equations
Absolute Value Equations
 
Unit 3 hw 7 - literal equations
Unit 3   hw 7 - literal equationsUnit 3   hw 7 - literal equations
Unit 3 hw 7 - literal equations
 
Unit 3 hw 4 - solving equations variable both sides
Unit 3   hw 4 - solving equations variable both sidesUnit 3   hw 4 - solving equations variable both sides
Unit 3 hw 4 - solving equations variable both sides
 

Recently uploaded

Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingTechSoup
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdfQucHHunhnh
 
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Sapana Sha
 
Employee wellbeing at the workplace.pptx
Employee wellbeing at the workplace.pptxEmployee wellbeing at the workplace.pptx
Employee wellbeing at the workplace.pptxNirmalaLoungPoorunde1
 
Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)eniolaolutunde
 
1029-Danh muc Sach Giao Khoa khoi 6.pdf
1029-Danh muc Sach Giao Khoa khoi  6.pdf1029-Danh muc Sach Giao Khoa khoi  6.pdf
1029-Danh muc Sach Giao Khoa khoi 6.pdfQucHHunhnh
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3JemimahLaneBuaron
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptxVS Mahajan Coaching Centre
 
Arihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfArihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfchloefrazer622
 
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...RKavithamani
 
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptx
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptxContemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptx
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptxRoyAbrique
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxpboyjonauth
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdfSoniaTolstoy
 
Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104misteraugie
 
Separation of Lanthanides/ Lanthanides and Actinides
Separation of Lanthanides/ Lanthanides and ActinidesSeparation of Lanthanides/ Lanthanides and Actinides
Separation of Lanthanides/ Lanthanides and ActinidesFatimaKhan178732
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionSafetyChain Software
 
Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfciinovamais
 

Recently uploaded (20)

Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1Código Creativo y Arte de Software | Unidad 1
Código Creativo y Arte de Software | Unidad 1
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
 
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111Call Girls in Dwarka Mor Delhi Contact Us 9654467111
Call Girls in Dwarka Mor Delhi Contact Us 9654467111
 
Employee wellbeing at the workplace.pptx
Employee wellbeing at the workplace.pptxEmployee wellbeing at the workplace.pptx
Employee wellbeing at the workplace.pptx
 
Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)Software Engineering Methodologies (overview)
Software Engineering Methodologies (overview)
 
1029-Danh muc Sach Giao Khoa khoi 6.pdf
1029-Danh muc Sach Giao Khoa khoi  6.pdf1029-Danh muc Sach Giao Khoa khoi  6.pdf
1029-Danh muc Sach Giao Khoa khoi 6.pdf
 
Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3Q4-W6-Restating Informational Text Grade 3
Q4-W6-Restating Informational Text Grade 3
 
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions  for the students and aspirants of Chemistry12th.pptxOrganic Name Reactions  for the students and aspirants of Chemistry12th.pptx
Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
 
Arihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdfArihant handbook biology for class 11 .pdf
Arihant handbook biology for class 11 .pdf
 
Staff of Color (SOC) Retention Efforts DDSD
Staff of Color (SOC) Retention Efforts DDSDStaff of Color (SOC) Retention Efforts DDSD
Staff of Color (SOC) Retention Efforts DDSD
 
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...
Privatization and Disinvestment - Meaning, Objectives, Advantages and Disadva...
 
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptx
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptxContemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptx
Contemporary philippine arts from the regions_PPT_Module_12 [Autosaved] (1).pptx
 
Introduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptxIntroduction to AI in Higher Education_draft.pptx
Introduction to AI in Higher Education_draft.pptx
 
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdfTataKelola dan KamSiber Kecerdasan Buatan v022.pdf
TataKelola dan KamSiber Kecerdasan Buatan v022.pdf
 
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdfBASLIQ CURRENT LOOKBOOK  LOOKBOOK(1) (1).pdf
BASLIQ CURRENT LOOKBOOK LOOKBOOK(1) (1).pdf
 
Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104Nutritional Needs Presentation - HLTH 104
Nutritional Needs Presentation - HLTH 104
 
Separation of Lanthanides/ Lanthanides and Actinides
Separation of Lanthanides/ Lanthanides and ActinidesSeparation of Lanthanides/ Lanthanides and Actinides
Separation of Lanthanides/ Lanthanides and Actinides
 
Mastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory InspectionMastering the Unannounced Regulatory Inspection
Mastering the Unannounced Regulatory Inspection
 
Activity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdfActivity 01 - Artificial Culture (1).pdf
Activity 01 - Artificial Culture (1).pdf
 

Solving quadratic equations part 2

  • 1. Solving Quadratic Equations PART 2
  • 2. Solving Quadratic Equations when they do NOT equal ZERO • So far all the quadratic equations we’ve solve have been equal to zero but not all are so nice. If they don’t equal zero, make them equal to zero! • View this Cool Math website to how to solve Quadratic Equations when the original equation is not equal to 0. • There are 3 pages to view. • Complete the Your Turn problems in your notebook and check your answers on the next slide.
  • 3. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0
  • 4. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0 ( x + 3) ( x − 6 ) = 0
  • 5. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0 ( x + 3) ( x − 6 ) = 0 x+3= 0 or x−6=0
  • 6. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0 ( x + 3) ( x − 6 ) = 0 x+3= 0 or x−6=0 −3 −3 +6 +6
  • 7. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0 ( x + 3) ( x − 6 ) = 0 x+3= 0 or x−6=0 −3 −3 +6 +6 x = −3 or x=6
  • 8. Page 1 - Finish it • Solve. 2 x − 3x − 18 = 0 ( x + 3) ( x − 6 ) = 0 x+3= 0 or x−6=0 −3 −3 +6 +6 x = −3 or x=6 Answer: {−3, 6}
  • 9. Page 1 - Your Turn 2 • Solve. x + 7x = 170
  • 10. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170
  • 11. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0
  • 12. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0 ( x + 17 ) ( x − 10 ) = 0
  • 13. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0 ( x + 17 ) ( x − 10 ) = 0 x + 17 = 0 or x − 10 = 0
  • 14. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0 ( x + 17 ) ( x − 10 ) = 0 x + 17 = 0 or x − 10 = 0 −17 −17 +10 +10
  • 15. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0 ( x + 17 ) ( x − 10 ) = 0 x + 17 = 0 or x − 10 = 0 −17 −17 +10 +10 x = −17 or x = 10
  • 16. Page 1 - Your Turn 2 • Solve. x + 7x = 170 −170 −170 2 x + 7x − 170 = 0 ( x + 17 ) ( x − 10 ) = 0 x + 17 = 0 or x − 10 = 0 −17 −17 +10 +10 x = −17 or x = 10 Answer: {−17,10}
  • 17. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0
  • 18. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0
  • 19. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0
  • 20. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0 −1 −1 +3 +3
  • 21. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0 −1 −1 +3 +3 2x = −1 or x=3
  • 22. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0 −1 −1 +3 +3 2x = −1 or x=3 2 2
  • 23. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0 −1 −1 +3 +3 2x = −1 or x=3 2 2 x = − 12
  • 24. Page 2 - Finish it • Solve. 2 2x − 5x − 3 = 0 ( 2x + 1) ( x − 3) = 0 2x + 1 = 0 or x−3= 0 −1 −1 +3 +3 2x = −1 or x=3 2 2 x = − 12 ⎧ 1 ⎫ Answer: ⎨− , 3⎬ ⎩ 2 ⎭
  • 25. Page 2 - Your Turn • Solve. 2 11x + 6 − 10x = 0
  • 26. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1
  • 27. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0
  • 28. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0
  • 29. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0
  • 30. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0
  • 31. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0 −2 −2 +3 +3
  • 32. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0 −2 −2 +3 +3 5x = −2 or 2x = 3
  • 33. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0 −2 −2 +3 +3 5x = −2 or 2x = 3 5 5 2 2
  • 34. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0 −2 −2 +3 +3 5x = −2 or 2x = 3 5 5 2 2 x = −25 or x= 3 2
  • 35. Page 2 - Your Turn • Solve. 11x + 6 − 10x = 02 ( −1 11x + 6 − 10x 2 ) = 0 ⋅ −1 2 −11x − 6 + 10x = 0 2 10x − 11x − 6 = 0 ( 5x + 2 ) ( 2x − 3) = 0 5x + 2 = 0 or 2x − 3 = 0 −2 −2 +3 +3 5x = −2 or 2x = 3 5 5 2 2 ⎧ 2 3 ⎫ Answer: ⎨− , ⎬ x = −25 or x= 3 2 ⎩ 5 2 ⎭
  • 36. Page 3 - Your Turn 3 • Solve. −16x = −4x
  • 37. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3
  • 38. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0
  • 39. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0)
  • 40. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0 ) 4x ( x + 2 ) ( x − 2 ) = 0
  • 41. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0 ) 4x ( x + 2 ) ( x − 2 ) = 0 4x = 0 or x+2=0 or x−2=0
  • 42. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0) 4x ( x + 2 ) ( x − 2 ) = 0 4x = 0 or x+2=0 or x−2=0 4 4 −2 −2 +2 +2
  • 43. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0) 4x ( x + 2 ) ( x − 2 ) = 0 4x = 0 or x+2=0 or x−2=0 4 4 −2 −2 +2 +2 x=0 or x = −2 or x=2
  • 44. Page 3 - Your Turn 3 • Solve. −16x = −4x +4x 3 +4x 3 3 4x − 16x = 0 ( 2 4x x − 4 = 0) 4x ( x + 2 ) ( x − 2 ) = 0 4x = 0 or x+2=0 or x−2=0 4 4 −2 −2 +2 +2 x=0 or x = −2 or x=2 Answer: {0, −2, 2}
  • 45. Do you want to Play a GAME? • Check your knowledge on solving Quadratic Equations by playing Jeopardy. Ok, technically it’s called Challenge Board but it’s the same idea! • You have the option to play alone or against a friend or maybe a family member! • You could even arrange a time with a classmate to meet on Pronto to play. Try the App Share feature to see the same game board! • Finding the x-intercepts is the same as solving!
  • 46. Fantastic Job! • You’ve finished reviewing Solving Quadratic Equations Part 2. • Exit and proceed to the Homework Assignment.

Editor's Notes

  1. \n
  2. \n
  3. \n
  4. \n
  5. \n
  6. \n
  7. \n
  8. \n
  9. \n
  10. \n
  11. \n
  12. \n
  13. \n
  14. \n
  15. \n
  16. \n
  17. \n
  18. \n
  19. \n
  20. \n
  21. \n
  22. \n
  23. \n
  24. \n
  25. \n
  26. \n
  27. \n
  28. \n
  29. \n
  30. \n
  31. \n
  32. \n
  33. \n
  34. \n
  35. \n
  36. \n
  37. \n
  38. \n
  39. \n
  40. \n
  41. \n