3. 2) By any point in line n, we draw a segment perpendicular to the line as you can
see in the picture below (work with the set square)
4. 3) Point the compass in B take radius r = 10 millimeters, draw an arch which
brings about point C. In the picture below, point C stands out by means of a
transparent circle, only to make everything clearer. In your drawing, just carry out
a tick
5. 4) By point C draw a line parallel to n (parallelism in technical drawing is
symbolized by two tiny parallel lines). We get point D in the angle bisector
6. 5) Por el punto D, se dibuja de nuevo una perpendicular a n que nos dará el
punto T. Ya tenemos situado el radio de la circunferencia solución.
7. 6) Tomando centro en D y racio DT, trazamos la circunferencia solución, tangente
a m y n y de radio 10 milímetros.
8. What is really useful in this process is that you can delete every extra component
and leave just the connection between the lines and the circle. By the way, you
can also change lines m and n as you like and work with different radius for the
circle as well. As a consequence, you can get thousands of results.
9. The symbol I put here as an example has been carried out by means of this
process. You can work much better things.