Based on how the value in some array position i compares to the value.docx
Balance the following redox equation using the half-reaction method- a.docx
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Balance the following redox equation using the half-reaction method, assuming acidic conditions: (4) Solution oxidation half reation reduction half reaction V^2+ (aq) -----------> VO3^- (aq) Cd^2+ (aq) ---------------> Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) Cd^2+ (aq) ---------------> Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) +6H^+(aq) Cd^2+ (aq) ---------------> Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) +6H^+(aq) +3e^- Cd^2+ (aq) +2e^- ---------------> Cd(s) 2V^2+ (aq)+6H2O(l) -----------> 2VO3^- (aq) +12H^+(aq) +6e^- 3Cd^2+ (aq) +6e^- ---------------> 3Cd(s) ---------------------------------------------------------------------------------------------------------------- 2V^2+ (aq)+6H2O(l)+ 3Cd^2+ (aq) -----------------> 2VO3^- (aq) +12H^+(aq) + 3Cd(s) .
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Balance the following redox equation using the half-reaction method- a.docx
- Balance the following redox equation using the half-reaction method, assuming acidic conditions: (4) Solution oxidation half reation reduction half reaction V^2+ (aq) -----------> VO3^- (aq) Cd^2+ (aq) ------------- --> Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) Cd^2+ (aq) --------------- > Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) +6H^+(aq) Cd^2+ (aq) --------------- > Cd(s) V^2+ (aq)+3H2O(l) -----------> VO3^- (aq) +6H^+(aq) +3e^- Cd^2+ (aq) +2e^- ------- --------> Cd(s) 2V^2+ (aq)+6H2O(l) -----------> 2VO3^- (aq) +12H^+(aq) +6e^- 3Cd^2+ (aq) +6e^- ---------------> 3Cd(s) ---------------------------------------------------------------------------------------------------------------- 2V^2+ (aq)+6H2O(l)+ 3Cd^2+ (aq) -----------------> 2VO3^- (aq) +12H^+(aq) + 3Cd(s)