Explain this code, please.
Code
public class Question8
{
public static void main(String[] args)
{
int[] nums = {2, 4, 6, 8};
for (int i = 0; i < nums.length; ++i)
System.out.println(\"nums[\" + i + \"] = \" + nums[i]);
System.out.println();
fun(nums);
for (int i = 0; i < nums.length; ++i)
System.out.println(\"nums[\" + i + \"] = \" + nums[i]);
}
public static void fun(int[] arr)
{
for (int i = 0; i < arr.length; i+=2)
arr[i] -= 1;
}
}
Run
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8
Solution
In the first loop i start at value 0 and in each iteration we are printing (\"nums[\" + i + \"] = \" + nums[i]). So for i = 0 this becomes nums[0] = 2. Next the value of i becomes 1 and then 2 and then 3 and the loop breaks.
Now we call the function fun in which there is a loop. The value of i initially is 0 and we are subtracting one from it. So the value of nums[0] becomes 1 and now the value of i becomes 2 and nums[2] becomes 5 and then the value of i becomes 4 and the loop exits. That explain the first set of output.
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
So now with the loop the values of nums will be 1,4,5,8. Because the values are changed in the function. That explain the second set of output.
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8
.
Explain this code- please- Code public class Question8 { public stati.docx
1. Explain this code, please.
Code
public class Question8
{
public static void main(String[] args)
{
int[] nums = {2, 4, 6, 8};
for (int i = 0; i < nums.length; ++i)
System.out.println("nums[" + i + "] = " + nums[i]);
System.out.println();
fun(nums);
for (int i = 0; i < nums.length; ++i)
System.out.println("nums[" + i + "] = " + nums[i]);
}
public static void fun(int[] arr)
{
for (int i = 0; i < arr.length; i+=2)
arr[i] -= 1;
}
}
Run
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8
Solution
2. In the first loop i start at value 0 and in each iteration we are printing ("nums[" + i + "] = " +
nums[i]). So for i = 0 this becomes nums[0] = 2. Next the value of i becomes 1 and then 2 and
then 3 and the loop breaks.
Now we call the function fun in which there is a loop. The value of i initially is 0 and we are
subtracting one from it. So the value of nums[0] becomes 1 and now the value of i becomes 2
and nums[2] becomes 5 and then the value of i becomes 4 and the loop exits. That explain the
first set of output.
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
So now with the loop the values of nums will be 1,4,5,8. Because the values are changed in the
function. That explain the second set of output.
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8
![Explain this code, please.
Code
public class Question8
{
public static void main(String[] args)
{
int[] nums = {2, 4, 6, 8};
for (int i = 0; i < nums.length; ++i)
System.out.println("nums[" + i + "] = " + nums[i]);
System.out.println();
fun(nums);
for (int i = 0; i < nums.length; ++i)
System.out.println("nums[" + i + "] = " + nums[i]);
}
public static void fun(int[] arr)
{
for (int i = 0; i < arr.length; i+=2)
arr[i] -= 1;
}
}
Run
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8
Solution](https://image.slidesharecdn.com/explainthiscode-please-codepublicclassquestion8publicstati-230131184829-4b7f3e7e/85/explain-this-code-please-code-public-class-question8-public-statidocx-1-320.jpg)
![In the first loop i start at value 0 and in each iteration we are printing ("nums[" + i + "] = " +
nums[i]). So for i = 0 this becomes nums[0] = 2. Next the value of i becomes 1 and then 2 and
then 3 and the loop breaks.
Now we call the function fun in which there is a loop. The value of i initially is 0 and we are
subtracting one from it. So the value of nums[0] becomes 1 and now the value of i becomes 2
and nums[2] becomes 5 and then the value of i becomes 4 and the loop exits. That explain the
first set of output.
nums[0] = 2
nums[1] = 4
nums[2] = 6
nums[3] = 8
So now with the loop the values of nums will be 1,4,5,8. Because the values are changed in the
function. That explain the second set of output.
nums[0] = 1
nums[1] = 4
nums[2] = 5
nums[3] = 8](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)