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Mathematics 8 Worksheet Algebra 1st
Quarter Mr. Carlo Justino J. Luna
Republic of the Philippines | DEPARTMENT OF EDUCATION
Region III | Division of City Schools | West District
Tamarind St., Clarkview Subd., Malabanias, Angeles City
School Year 2018-2019
NAME: ________________________________________ SCORE: __________________
GRADE & SECTION: _____________________________ DATE: ____________________
1st Quarter Worksheet #7
Worksheet on factoring the difference of two squares will help us to factorize an algebraic expression
using the following identity: 𝒙 𝟐
βˆ’ π’š 𝟐
= (𝒙 + π’š)(𝒙 βˆ’ π’š)
Find the factors of each expression.
1. π‘₯2
βˆ’ 25
2. 4𝑦2
βˆ’ 9
3. 9π‘Ž2
βˆ’ 1
4. 36𝑏2
βˆ’ 1
5. 4𝑐2
βˆ’ 49
6. 𝑑2
βˆ’ 36
7. 16𝑒2
βˆ’ 25
8. 25π‘š2
βˆ’ 4
9. 9𝑛2
βˆ’ 100
10.49𝑝2
βˆ’ 81
11.4π‘₯2
βˆ’ 9
12.25𝑦2
βˆ’ 𝑧2
13. π‘Ž2
βˆ’ 25𝑏2
14.16π‘š2
βˆ’ 81𝑛2
15.25π‘₯6
βˆ’ 16𝑦8
16.36𝑝4
βˆ’ 9π‘ž6
17. π‘Ž10
βˆ’ 4𝑏8
18.2π‘₯2
βˆ’ 18
19.3𝑏2
βˆ’ 75
20.8𝑦2
βˆ’ 50
Mathematics 8 Worksheet Algebra 1st
Quarter Mr. Carlo Justino J. Luna
Republic of the Philippines | DEPARTMENT OF EDUCATION
Region III | Division of City Schools | West District
Tamarind St., Clarkview Subd., Malabanias, Angeles City
School Year 2018-2019
NAME: ________________________________________ SCORE: __________________
GRADE & SECTION: _____________________________ DATE: ____________________
1st Quarter Worksheet #7
Worksheet on factoring the difference of two squares will help us to factorize an algebraic expression
using the following identity: 𝒙 𝟐
βˆ’ π’š 𝟐
= (𝒙 + π’š)(𝒙 βˆ’ π’š)
Find the factors of each expression.
1. π‘₯2
βˆ’ 25
= (π‘₯ + 5)(π‘₯ βˆ’ 5)
2. 4𝑦2
βˆ’ 9
= (2𝑦 + 3)(2𝑦 βˆ’ 3)
3. 9π‘Ž2
βˆ’ 1
= (3π‘Ž + 1)(3π‘Ž βˆ’ 1)
4. 36𝑏2
βˆ’ 1
= (6𝑏 + 1)(6𝑏 βˆ’ 1)
5. 4𝑐2
βˆ’ 49
= (2𝑐 + 7)(2𝑐 βˆ’ 7)
6. 𝑑2
βˆ’ 36
= (𝑑 + 6)(𝑑 βˆ’ 6)
7. 16𝑒2
βˆ’ 25
= (4𝑒 + 5)(4𝑒 βˆ’ 5)
8. 25π‘š2
βˆ’ 4
= (5π‘š + 2)(5π‘š βˆ’ 2)
9. 9𝑛2
βˆ’ 100
= (3𝑛 + 10)(3𝑛 βˆ’ 10)
10.49𝑝2
βˆ’ 81
= (7𝑝 + 9)(7𝑝 βˆ’ 9)
11.4π‘₯2
βˆ’ 9
= (2π‘₯ + 3)(2π‘₯ βˆ’ 3)
12.25𝑦2
βˆ’ 𝑧2
= (5𝑦 + 𝑧)(5𝑦 βˆ’ 𝑧)
13. π‘Ž2
βˆ’ 25𝑏2
= (π‘Ž + 5𝑏)(π‘Ž βˆ’ 5𝑏)
14.16π‘š2
βˆ’ 81𝑛2
= (4π‘š + 9𝑛)(4π‘š βˆ’ 9𝑛)
15.25π‘₯6
βˆ’ 16𝑦8
= (5π‘₯3
+ 4𝑦4
)(5π‘₯3
βˆ’ 4𝑦4
)
16.36𝑝4
βˆ’ 9π‘ž6
= (6𝑝2
+ 3π‘ž3)(6𝑝2
βˆ’ 3π‘ž3
)
17. π‘Ž10
βˆ’ 4𝑏8
= (π‘Ž5
+ 2𝑏4
)(π‘Ž5
βˆ’ 2𝑏4
)
18.2π‘₯2
βˆ’ 18
= 2(π‘₯2
βˆ’ 9)
= 2(π‘₯ + 3)(π‘₯ βˆ’ 3)
19.3𝑏2
βˆ’ 75
= 3(𝑏2
βˆ’ 25)
= 3(𝑏 + 5)(𝑏 βˆ’ 5)
20.8𝑦2
βˆ’ 32
= 2(4𝑦2
βˆ’ 16)
= 2(2𝑦 + 4)(2𝑦 βˆ’ 4)

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  • 1. Mathematics 8 Worksheet Algebra 1st Quarter Mr. Carlo Justino J. Luna Republic of the Philippines | DEPARTMENT OF EDUCATION Region III | Division of City Schools | West District Tamarind St., Clarkview Subd., Malabanias, Angeles City School Year 2018-2019 NAME: ________________________________________ SCORE: __________________ GRADE & SECTION: _____________________________ DATE: ____________________ 1st Quarter Worksheet #7 Worksheet on factoring the difference of two squares will help us to factorize an algebraic expression using the following identity: 𝒙 𝟐 βˆ’ π’š 𝟐 = (𝒙 + π’š)(𝒙 βˆ’ π’š) Find the factors of each expression. 1. π‘₯2 βˆ’ 25 2. 4𝑦2 βˆ’ 9 3. 9π‘Ž2 βˆ’ 1 4. 36𝑏2 βˆ’ 1 5. 4𝑐2 βˆ’ 49 6. 𝑑2 βˆ’ 36 7. 16𝑒2 βˆ’ 25 8. 25π‘š2 βˆ’ 4 9. 9𝑛2 βˆ’ 100 10.49𝑝2 βˆ’ 81 11.4π‘₯2 βˆ’ 9 12.25𝑦2 βˆ’ 𝑧2 13. π‘Ž2 βˆ’ 25𝑏2 14.16π‘š2 βˆ’ 81𝑛2 15.25π‘₯6 βˆ’ 16𝑦8 16.36𝑝4 βˆ’ 9π‘ž6 17. π‘Ž10 βˆ’ 4𝑏8 18.2π‘₯2 βˆ’ 18 19.3𝑏2 βˆ’ 75 20.8𝑦2 βˆ’ 50
  • 2. Mathematics 8 Worksheet Algebra 1st Quarter Mr. Carlo Justino J. Luna Republic of the Philippines | DEPARTMENT OF EDUCATION Region III | Division of City Schools | West District Tamarind St., Clarkview Subd., Malabanias, Angeles City School Year 2018-2019 NAME: ________________________________________ SCORE: __________________ GRADE & SECTION: _____________________________ DATE: ____________________ 1st Quarter Worksheet #7 Worksheet on factoring the difference of two squares will help us to factorize an algebraic expression using the following identity: 𝒙 𝟐 βˆ’ π’š 𝟐 = (𝒙 + π’š)(𝒙 βˆ’ π’š) Find the factors of each expression. 1. π‘₯2 βˆ’ 25 = (π‘₯ + 5)(π‘₯ βˆ’ 5) 2. 4𝑦2 βˆ’ 9 = (2𝑦 + 3)(2𝑦 βˆ’ 3) 3. 9π‘Ž2 βˆ’ 1 = (3π‘Ž + 1)(3π‘Ž βˆ’ 1) 4. 36𝑏2 βˆ’ 1 = (6𝑏 + 1)(6𝑏 βˆ’ 1) 5. 4𝑐2 βˆ’ 49 = (2𝑐 + 7)(2𝑐 βˆ’ 7) 6. 𝑑2 βˆ’ 36 = (𝑑 + 6)(𝑑 βˆ’ 6) 7. 16𝑒2 βˆ’ 25 = (4𝑒 + 5)(4𝑒 βˆ’ 5) 8. 25π‘š2 βˆ’ 4 = (5π‘š + 2)(5π‘š βˆ’ 2) 9. 9𝑛2 βˆ’ 100 = (3𝑛 + 10)(3𝑛 βˆ’ 10) 10.49𝑝2 βˆ’ 81 = (7𝑝 + 9)(7𝑝 βˆ’ 9) 11.4π‘₯2 βˆ’ 9 = (2π‘₯ + 3)(2π‘₯ βˆ’ 3) 12.25𝑦2 βˆ’ 𝑧2 = (5𝑦 + 𝑧)(5𝑦 βˆ’ 𝑧) 13. π‘Ž2 βˆ’ 25𝑏2 = (π‘Ž + 5𝑏)(π‘Ž βˆ’ 5𝑏) 14.16π‘š2 βˆ’ 81𝑛2 = (4π‘š + 9𝑛)(4π‘š βˆ’ 9𝑛) 15.25π‘₯6 βˆ’ 16𝑦8 = (5π‘₯3 + 4𝑦4 )(5π‘₯3 βˆ’ 4𝑦4 ) 16.36𝑝4 βˆ’ 9π‘ž6 = (6𝑝2 + 3π‘ž3)(6𝑝2 βˆ’ 3π‘ž3 ) 17. π‘Ž10 βˆ’ 4𝑏8 = (π‘Ž5 + 2𝑏4 )(π‘Ž5 βˆ’ 2𝑏4 ) 18.2π‘₯2 βˆ’ 18 = 2(π‘₯2 βˆ’ 9) = 2(π‘₯ + 3)(π‘₯ βˆ’ 3) 19.3𝑏2 βˆ’ 75 = 3(𝑏2 βˆ’ 25) = 3(𝑏 + 5)(𝑏 βˆ’ 5) 20.8𝑦2 βˆ’ 32 = 2(4𝑦2 βˆ’ 16) = 2(2𝑦 + 4)(2𝑦 βˆ’ 4)