Resistance Series Parallel Circuits Explained Under 40 Characters

Chapter 17 D.C Electric Circuit Part 1 – Resistance in Series & Parallel Circuits

[object Object],[object Object],[object Object],[object Object],Learning Objectives

[object Object],Electric Circuits ,[object Object],[object Object]

Electric Circuit Resistors Arrangement

Resistors and Resistance ,[object Object],[object Object],[object Object]

Resistors in Series ,[object Object],[object Object]

Resistors in Parallel ,[object Object]

Resistors in Parallel ,[object Object],R 2 R 1 I 1 I 2

Summary (Resistance) ,[object Object],[object Object],[object Object],[object Object],[object Object]

Chapter 17: D.C Circuit Part 2 : Current in Series & Parallel Circuits

[object Object],[object Object],[object Object],Learning Objectives

[object Object],[object Object],Current in Series Circuits R R R Battery Switch I I 1 I 2 I 3

[object Object],Current in Series Circuits Answer: The rest of the lamps will not light up.

[object Object],Pause and Think … What will happen if they are connected in series? How then do you think the lights should be connected? WHY?

Current in Parallel Circuit ,[object Object],R 1 R 2 R 3 Switch I I 1 I 2 I 3 I The main current is equal to the sum of the sub-currents. ( I = I 1 +I 2 +I 3 )

Current in Parallel Circuit ,[object Object],Answer: Apart from the lamp that was being removed, the rest of the lamp will continue to light up.

Short Circuit ,[object Object],[object Object],[object Object],[object Object],A B

[object Object],[object Object],[object Object],[object Object],Summary

Chapter 17: D.C Circuit Part 3 : P.D/Voltage in Series & Parallel Circuits

Learning Objectives ,[object Object],[object Object],[object Object]

[object Object],P.D. in Series Circuits Switch I V 1 V 2 V 3 V 4 L 1 L 2 L 3

[object Object],[object Object],P.D. in Series Circuits

P.D. in Parallel Circuit V 1 = V 2 = V 3 I 1 I 2 V 3 Switch I V 1 V 2

Summary ,[object Object],[object Object]

Series & Parallel Circuits ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Worked Example ,[object Object],[object Object],[object Object],[object Object],Solution (a) combined resistor = 6 + 2 = 8  (b) since V= RI, 4 = 8 x I, I = 0.5 A (c) V 6  = 6 x 0.5 = 3 V I 6  2  4V

Worked Example ,[object Object],[object Object],[object Object],[object Object],Solution (a) combined resistor = (R 1 R 2) / (R 1 +R 2 ) = (3 x 6) / (3+6) = 2  (b) since V= RI, 12 = 2 x I, I = 6 A (c) current through 3  = 12 / 3 = 4 A 3  6  12 V

Worked Example ,[object Object],[object Object],[object Object],[object Object],Solution (a) combined resistor = [(R 1 R 2) / (R 1 +R 2 )] + R 3 = [(36x18) / (36+18)] + 8 = 20  (b) since V= RI, 16 = 20 x I, I = 0.8 A hence, current through 8  resistor is 0.8 A R2 R1 R3 16V 8  36  18 

Resistance Series Parallel Circuits Explained Under 40 Characters

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Resistance Series Parallel Circuits Explained Under 40 Characters