To get 0-5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0-1 Mole i.docx
To get 0.5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0.1 Mole i mixed 1ml of 1 mole NaCl + 9mL h2o to get 0.01 mole i mixed 1ml of 0.1 mole nacl + 9ml of H2O how do i get to 0.1 Mole from 0.5 mole NaCl? with an explanation would be appreciated Solution For solving this we need the equation, M 1 V 1 = M 2 V 2 M 1 = Molarity of NaCl solution V 1 = Volume of NaCl solution M 2 = Molarity of final solution V 2 = Volume of final solution Given, M 1 = 1 M V 1 = 5 mL = 0.005 L M 2 = Unknown V 2 = 5 mL H 2 O + 5 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.005 = M 2 x 0.01 M 2 = 0.5 M Given, M 1 = 1 M V 1 = 1 mL = 0.001 L M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.001 = M 2 x 0.01 M 2 = 0.1 M Given, M 1 = 0.1 M V 1 = 1 mL = 0.001 L M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 0.1 x 0.001 = M 2 x 0.01 M 2 = 0.01 M ? Given, M 1 = 0.5 M V 1 = Unknown M 2 = 0.1 M V 2 = Say I prepare 10 mL solution = 0.01 L Putting the values in the above equation, V 2 x 0.5 = 0.1 x 0.01 V 2 = 0.002 L = 2 mL Hence to prepare a 10 mL 0.1 M NaCl solution, mix 8 mL H 2 O with 2 mL of 0.5 M NaCl. ? .
To get 0-5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0-1 Mole i.docx
To get 0.5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0.1 Mole i mixed 1ml of 1 mole NaCl + 9mL h2o to get 0.01 mole i mixed 1ml of 0.1 mole nacl + 9ml of H2O how do i get to 0.1 Mole from 0.5 mole NaCl? with an explanation would be appreciated Solution For solving this we need the equation, M 1 V 1 = M 2 V 2 M 1 = Molarity of NaCl solution V 1 = Volume of NaCl solution M 2 = Molarity of final solution V 2 = Volume of final solution Given, M 1 = 1 M V 1 = 5 mL = 0.005 L M 2 = Unknown V 2 = 5 mL H 2 O + 5 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.005 = M 2 x 0.01 M 2 = 0.5 M Given, M 1 = 1 M V 1 = 1 mL = 0.001 L M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.001 = M 2 x 0.01 M 2 = 0.1 M Given, M 1 = 0.1 M V 1 = 1 mL = 0.001 L M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 0.1 x 0.001 = M 2 x 0.01 M 2 = 0.01 M ? Given, M 1 = 0.5 M V 1 = Unknown M 2 = 0.1 M V 2 = Say I prepare 10 mL solution = 0.01 L Putting the values in the above equation, V 2 x 0.5 = 0.1 x 0.01 V 2 = 0.002 L = 2 mL Hence to prepare a 10 mL 0.1 M NaCl solution, mix 8 mL H 2 O with 2 mL of 0.5 M NaCl. ? .
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To get 0-5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0-1 Mole i.docx
- 1. To get 0.5 mole i mixed 5ml of 1 mole NaCl + 5ml H20 To get 0.1 Mole i mixed 1ml of 1 mole NaCl + 9mL h2o to get 0.01 mole i mixed 1ml of 0.1 mole nacl + 9ml of H2O how do i get to 0.1 Mole from 0.5 mole NaCl? with an explanation would be appreciated Solution For solving this we need the equation, M 1 V 1 = M 2 V 2 M 1 = Molarity of NaCl solution V 1 = Volume of NaCl solution M 2 = Molarity of final solution V 2 = Volume of final solution Given, M 1 = 1 M V 1 = 5 mL = 0.005 L M 2 = Unknown V 2 = 5 mL H 2 O + 5 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.005 = M 2 x 0.01 M 2 = 0.5 M Given, M 1 = 1 M V 1 = 1 mL = 0.001 L
- 2. M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 1 x 0.001 = M 2 x 0.01 M 2 = 0.1 M Given, M 1 = 0.1 M V 1 = 1 mL = 0.001 L M 2 = Unknown V 2 = 9 mL H 2 O + 1 mL NaCl solution = 10 mL = 0.01 L Putting the values in the above equation, 0.1 x 0.001 = M 2 x 0.01 M 2 = 0.01 M ? Given, M 1 = 0.5 M V 1 = Unknown M 2 = 0.1 M V 2 = Say I prepare 10 mL solution = 0.01 L Putting the values in the above equation, V 2 x 0.5 = 0.1 x 0.01 V 2 = 0.002 L = 2 mL Hence to prepare a 10 mL 0.1 M NaCl solution, mix 8 mL H 2 O with 2 mL of 0.5 M NaCl. ?