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Faculty of Engineering

ENG1040
Engineering Dynamics
Kinematics of a Particle
Dr Lau Ee Von – Sunway

Lecture 4

ENG1040 – Engineering Dynamics
Lecture outline
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

• Concepts of position, displacement, velocity, and
acceleration
• Study particle motion along a straight line
• Erratic motion: the graphical method
• Projectile motion – two dimensional motion
Rectilinear Kinematics:
Continuous Motion
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

RECTILINEAR KINEMATICS

Defines a particle’s position, displacement,
velocity, and acceleration at any instant in time.
Rectilinear Kinematics:
Continuous Motion
Lecture Outline
Revision:
kinematics

Example:
Kinematics

POSITION

• A particle’s position is defined from an origin.
• We must always define a coordinate system to a
problem.

Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

DISPLACEMENT
Rectilinear Kinematics:
Continuous Motion
VELOCITY

Lecture Outline
Revision:
kinematics

•

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

SPEED
Rectilinear Kinematics:
Continuous Motion
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

ACCELERATION
Rectilinear Kinematics:
Continuous Motion
ACCELERATION

Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

+
Rectilinear Kinematics:
Continuous Motion
ACCELERATION

Lecture Outline
Revision:
kinematics

Example:
Kinematics

Example from Lecture 3:
Coordinate system
2
vB

2
vA

Erratic motion:
Graphical
method

2aC ( s B

sA )

-9.81 m/s2

Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

2
vC

2
vB

2aC ( sC
-9.81 m/s2

sB )

+
Kinematics
Lecture Outline

by definition:

Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

by rearranging:

Example:
Projectile
motion

9
9
Kinematics
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method

When do we use

a

dv
dt

and a v dv ?
ds

Example: Find the velocity if s = 2m when t = 0 s
Given a = 20t

Given a = 20s

Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

10
Kinetics/Kinematics problems...
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Analysis procedure
1. Establish a coordinate system
2. Draw Free Body Diagram(s)
•

Graphical representation of all forces acting on
the system.

3. Establish known & unknown quantities
Projectile
motion

Example:
Projectile
motion

4. Apply Equation(s) of Motion in each direction
5. Evaluate kinematics to solve problem
Example 12.4
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A metallic particle travels downward through a
fluid that extends from plate A and plate B under
the influence of magnetic field. If particle is
released from rest at midpoint C, s = 100 mm,
and acceleration, a = (4s) m/s2, where s in
meters, determine velocity when it reaches plate
B and time need to travel from C to B.
Example 12.4
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Step 1: choose a coordinate system
Projectile
motion

Example:
Projectile
motion
Example 12.4
Lecture Outline
Revision:
kinematics

a

v

Example:
Kinematics

dv
dt
ds
dt

a

dv
v
ds

Erratic motion:
Graphical
method
Example:
Graphical
method

Step 2: employ kinematics
Projectile
motion

Example:
Projectile
motion

a = (4s) m/s2
Example 12.4
Lecture Outline
Revision:
kinematics

a

v

Example:
Kinematics

dv
dt
ds
dt

a

dv
v
ds

Erratic motion:
Graphical
method
Example:
Graphical
method

Step 2: employ kinematics
Projectile
motion

Example:
Projectile
motion

a = (4s) m/s2

a

dv
v
ds

4s

dv
v
ds
Example 12.4
Lecture Outline
Revision:
kinematics

a

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

dv
dt

v

ds
dt

a

dv
v
ds

Step 2: employ kinematics

a

dv
v
ds
s

dv
v
ds

4s
v

4sds
sinitial

vdv
vinitial
Example 12.4
Lecture Outline
Revision:
kinematics

a

v

Example:
Kinematics
Erratic motion:
Graphical
method

Example:
Projectile
motion

ds
dt

a

dv
v
ds

Step 2: employ kinematics

Example:
Graphical
method

Projectile
motion

dv
dt

s

v

4sds
sinitial

2s

2 s
sinitial

vdv
vinitial

1 2
v
2

v

vinitial
Example 12.4
Lecture Outline
Revision:
kinematics

a

v

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

dv
dt
ds
dt

a

dv
v
ds

Step 2: employ kinematics
s

v

4sds
sinitial

2s

2 s
0.1

vdv
vinitial

1 2
v
2

v

0

Only put
in initial
limits
Example 12.4
Step 2: employ kinematics

Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method

1 2
v
2
v

2s

2 s

Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

2

2

a

2

0.1
0.01

Leave it in the
general form
of equation

dv
dt

v

ds
dt

a

dv
v
ds

Substitute sb = 200mm = 0.2m to
find vb

vb

0.346 m / s
Example 12.4
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A metallic particle travels downward through a
fluid that extends from plate A and plate B under
the influence of magnetic field. If particle is
released from rest at midpoint C, s = 100 mm,
and acceleration, a = (4s) m/s2, where s in
meters, determine velocity when it reaches plate
B and time need to travel from C to B.
Example 12.4
Time to reach plate B?

Lecture Outline
Revision:
kinematics

a

Example:
Kinematics
Erratic motion:
Graphical
method

a

Example:
Graphical
method

2s

Projectile
motion

Example:
Projectile
motion

v

dv
v
ds

2 s

4s
1 2
v
2

2 s
0.1

2

dv
v
ds

dv
dt

v

ds
dt

a

dv
v
ds

v

0

0.01

Use general
form of
equation!
Example 12.4
Lecture Outline

Time to reach plate B?

Revision:
kinematics

v

Example:
Kinematics

a

dv
dt

v

ds
dt

a

dv
v
ds

ds v dt

Erratic motion:
Graphical
method

2s

Example:
Graphical
method

s
0.1

Projectile
motion

Example:
Projectile
motion

2 s 2 0.01

t

2

0.01

ds
s 2 0.1

t
0.5

0

0.5

dt

2 dt

ln (0.2) 2 0.01 s
2

Only put
in initial
limits

2.303

Leave it in the general form of equation
Example 12.4
Lecture Outline
Revision:
kinematics

Substitute sb = 200mm = 0.2m to
find tb

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

t = 0.658s

a

dv
dt

v

ds
dt

a

dv
v
ds

NOTE:
Why can’t we use

v u at
s

s0 ut

1 2 ?
at
2

Acceleration is NOT a constant
(a = 4s)
Faculty of Engineering

ENG1040
Engineering Dynamics
Erratic motion and graphical methods

Dr Greg Sheard - Clayton
Dr Lau Ee Von - Sunway

Lecture 4

ENG1040 – Engineering Dynamics
Erratic motion and graphical methods
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

25
Erratic motion and graphical methods
Lecture Outline
Revision:
kinematics

•

When particle’s motion is erratic, it is
described graphically using a series of
curves

•

A graph is used to described the
relationship with any 2 of the variables:

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

a, v, s, t
•

a

We use

dv
dt

v

ds
dt

a

dv
v
ds
Example 12.6
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A bicycle moves along a straight road such
that it position is described by the graph as
shown. Construct the v-t and a-t graphs for
0 ≤ t ≤ 30s.
Example 12.6
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A bicycle moves along a straight road such
that it position is described by the graph as
shown. Construct the v-t and a-t graphs for
0 ≤ t ≤ 30s.

a

dv
dt

ds
v
dt
dv
a v
ds
Example 12.6
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

Solution

v-t Graph
By differentiating the equations defining the
s-t graph, we have
ds
v
0.6t
2
0 t 10s;
s 0.3t
dt
ds
10s t 30s; s 6t 30 v
6
dt
Example 12.6
Lecture Outline

Solution

Revision:
kinematics

Example:
Kinematics

a-t Graph

Erratic motion:
Graphical
method

By differentiating the eqns defining the lines
of the v-t graph,

Example:
Graphical
method

Example:
Projectile
motion

0.6t

a

10
Projectile
motion

0 t 10 s; v

6

a

t

30 s; v

dv
dt
dv
dt

0.6
0

a

dv
v
ds

a

dv
dt
Example 12.7
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A test car starts from rest and travels along a
straight track such that it accelerates at a constant
rate for 10 s and then decelerates at a constant
rate. Draw the v-t and s-t graphs and determine the
time t’ needed to stop the car. How far has the car
traveled?
Example 12.7
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A test car starts from rest and travels along a
straight track such that it accelerates at a constant
rate for 10 s and then decelerates at a constant
rate. Draw the v-t and s-t graphs and determine the
time t’ needed to stop the car. How far has the car
traveled?

a

dv
dt

v

ds
dt

a

dv
v
ds
Example 12.7
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Solution

v-t Graph
Using initial condition v = 0 when t = 0,
v

0 t 10s a 10;

0

dv

t
0

10 dt , v 10 t

When t = 10s, v = 100m/s,
10s t

t; a

v

2;

100

v

dv

t
10

2 dt ,

2t 120

Example:
Projectile
motion

a

dv
dt
Example 12.7
Solution

Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

s-t Graph.
Using initial conditions s = 0 when t = 0,
s

0 t 10s; v 10t;

0

t

ds

0

5t 2

When t = 10s, s = 500m,
10s t

60s; v

s

2t 120;

ds

500

Projectile
motion

10 t dt , s

s

t
10

2t 120 dt

t 2 120 t 600

Example:
Projectile
motion

v

ds
dt
Example 12.7
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A test car starts from rest and travels along a
straight track such that it accelerates at a constant
rate for 10 s and then decelerates at a constant
rate. Draw the v-t and s-t graphs and determine the
time t’ needed to stop the car. How far has the car
traveled?

a

dv
dt

v

ds
dt

a

dv
v
ds
Example 12.7
Lecture Outline
Revision:
kinematics

Time needed to stop the car?
Solution

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

10s t

t; v

2t 120

When t = t’, v = 0  t’ = 60 s
Example 12.7
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

A test car starts from rest and travels along a
straight track such that it accelerates at a constant
rate for 10 s and then decelerates at a constant
rate. Draw the v-t and s-t graphs and determine the
time t’ needed to stop the car. How far has the car
traveled?

a

dv
dt

v

ds
dt

a

dv
v
ds
Example 12.7
Lecture Outline
Revision:
kinematics

Total distance travelled?
Solution

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

10 s

t

60 s; s

t 2 120 t 600

When t = t’ = 60s, s = 3000m
Faculty of Engineering

ENG1040
Engineering Dynamics
Projectile motion
Dr Greg Sheard – Clayton
Dr Lau Ee Von – Sunway

Lecture 4

ENG1040 – Engineering Dynamics
Projectile motion
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

40
Projectile motion
Lecture Outline
Revision:
kinematics

Example:
Kinematics

We can resolve the velocity or
acceleration to its x and y directions,
and vice versa.

a

dv
dt

v

ds
dt

a

dv
v
ds

Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

41
Projectile motion
Lecture Outline

Some simplifications (for ENG1040)

Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

•
•
•
•
•

Projectile’s acceleration always acts vertically
Projectile launched at (x0, y0) and path is defined in the x-y
plane
Fluid resistance is neglected
Only force is its weight downwards
ac = g = 9.81 m/s2 (constant downwards acceleration)
12.6 Motion of Projectile
Lecture Outline
Revision:
kinematics

Horizontal Motion
• Since ax = 0,

Example:
Kinematics

•

Erratic motion:
Graphical
method

v

Example:
Graphical
method

x

Projectile
motion

Example:
Projectile
motion

We can use the constant acceleration
equations

v2

•

v0

ac t ;

1 2
x0 v0t
ac t ;
2
2
v0 2ac ( s s0 );

vx (v0 ) x
x x0 (v0 ) x t
vx (v0 ) x

Horizontal component of velocity remain
constant during the motion
12.6 Motion of Projectile
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

Vertical Motion
• Positive y axis is upward, thus ay = - g
Once again, we can use the constant
acceleration equations:
v v0 ac t ;
y
v

2

y0
2
0

v

1 2
v0t
ac t ;
2
2ac ( y y0 );

vy
y
2
vy

(v0 ) y

gt

1 2
y0 (v0 ) y t
gt
2
(v0 ) 2 2 g ( y y0 )
y
12.6 Motion of Projectile
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

PROCEDURE FOR ANALYSIS
1. Establish a coordinate system
2. Sketch the trajectory of the particle
3. Specify 3 unknowns and data between any two
points on the path
4. Employ the equations of motion
5. Acceleration of gravity always acts downwards
6. Express the particle initial and final velocities in
the x, y components
Note: Positive and negative position, velocity and
acceleration components always act in accordance with
their associated coordinate directions
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

The chipping machine is designed to eject wood
chips vO = 7.5 m/s. If the tube is oriented at 30° from
the horizontal, determine how high, h, a chip is
when it is 6 metres away (horizontally) from the
tube.
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method

The chipping machine is designed to eject wood
chips at vO = 7.5 m/s. If the tube is oriented at 30°
from the horizontal, determine how high a chip is
when it is 6 metres away (horizontally) from the
tube.
Step 1: Establish a coordinate system:

Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

y

x
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

The chipping machine is designed to eject wood
chips at vO = 7.5 m/s. If the tube is oriented at 30°
from the horizontal, determine how high a chip is
when it is 6 metres away (horizontally) from the
tube.
Step 2: Determine the vertical and horizontal components
of initial velocity

(vO ) x

(7.5 cos30 )

(vO ) y

(7.5 sin 30 ) 3.75m / s

6.5m / s
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

The chipping machine is designed to eject wood
chips at vO = 7.5 m/s. If the tube is oriented at 30°
from the horizontal, determine how high a chip is
when it is 6 metres away (horizontally) from the
tube.
Step 3: Apply the (relevant) equations of motion

yA

yO

(v0 ) y tOA

1 2
gtOA
2

 1 equation, 2 unknowns

Vertical motion

vy

(v0 ) y

y

y0 (v0 ) y t

2
vy

(v0 ) 2
y

gt
1 2
gt
2
2 g ( y y0 )

Remember: these are
just simplified
constant acceleration
equations
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method

The chipping machine is designed to eject wood
chips at vO = 7.5 m/s. If the tube is oriented at 30°
from the horizontal, determine how high a chip is
when it is 6 metres away (horizontally) from the
tube.
Step 3: Apply the (relevant) equations of motion

Example:
Graphical
method

vx

xA
Projectile
motion

Example:
Projectile
motion

Horizontal motion

x0 (v0 ) x tOA
tOA

0.923s

(v0 ) x

x

x0 (v0 ) x t

vx

(v0 ) x

Remember: these are
just simplified
constant acceleration
equations
Example
Lecture Outline
Revision:
kinematics

Example:
Kinematics
Erratic motion:
Graphical
method
Example:
Graphical
method

Projectile
motion

Example:
Projectile
motion

The chipping machine is designed to eject wood
chips at vO = 7.5 m/s. If the tube is oriented at 30°
from the horizontal, determine how high a chip is
when it is 6 metres away (horizontally) from the
tube.
Step 3: Apply the (relevant) equations of motion

tOA
yA

0.9231 s
yO

h 1.38m

(v0 ) y tOA

Vertical motion

vy

1 2
gtOA
2

(v0 ) y

y

y0 (v0 ) y t

2
vy

(v0 ) 2
y

gt
1 2
gt
2
2 g ( y y0 )

Remember: these are
just simplified
constant acceleration
equations
Conclusions
• We have considered the rectilinear equations for
kinematics in three situations:
• 1 dimensional motion – rectilinear, continuous
motion
• 1 dimensional motion – erratic motion
• The ‘Graphical’ method

• 2 dimensional motion
• Projectile motion

52

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