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Lecture notes on trusses
1.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition TRUSSES-LECTURE NOTES 6 - 1
2.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 2 Contents Introduction Definition of a Truss Simple Trusses Analysis of Trusses by the Method of Joints Joints Under Special Loading Conditions Space Trusses Sample Problem 6.1 Analysis of Trusses by the Method of Sections Trusses Made of Several Simple Trusses Sample Problem 6.3 Analysis of Frames Frames Which Cease to be Rigid When Detached From Their Supports Sample Problem 6.4 Machines
3.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 3 Introduction • For the equilibrium of structures made of several connected parts, the internal forces as well the external forces are considered. • In the interaction between connected parts, Newton’s 3rd Law states that the forces of action and reaction between bodies in contact have the same magnitude, same line of action, and opposite sense. • Three categories of engineering structures are considered: a) Frames: contain at least one one multi-force member, i.e., member acted upon by 3 or more forces. b) Trusses: formed from two-force members, i.e., straight members with end point connections c) Machines: structures containing moving parts designed to transmit and modify forces.
4.
Vector Mechanics for
Engineers: Statics • Most structures are made of several trusses joined together to form a space framework. Each truss carries those loads which act in its plane and may be treated as a two-dimensional structure. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 4 Definition of a Truss • A truss consists of straight members connected at joints. No member is continuous through a joint. • Bolted or welded connections are assumed to be pinned together. Forces acting at the member ends reduce to a single force and no couple. Only two-force members are considered. • When forces tend to pull the member apart, it is in tension. When the forces tend to compress the member, it is in compression.
5.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 5 Definition of a Truss Members of a truss are slender and not capable of supporting large lateral loads. Loads must be applied at the joints.
6.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 6 Definition of a Truss
7.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 7 Simple Trusses • A rigid truss will not collapse under the application of a load. • A simple truss is constructed by successively adding two members and one connection to the basic triangular truss. • In a simple truss, m = 2n - 3 where m is the total number of members and n is the number of joints.
8.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 8 Analysis of Trusses by the Method of Joints • Dismember the truss and create a freebody diagram for each member and pin. • The two forces exerted on each member are equal, have the same line of action, and opposite sense. • Forces exerted by a member on the pins or joints at its ends are directed along the member and equal and opposite. • Conditions of equilibrium on the pins provide 2n equations for 2n unknowns. For a simple truss, 2n = m + 3. May solve for m member forces and 3 reaction forces at the supports. • Conditions for equilibrium for the entire truss provide 3 additional equations which are not independent of the pin equations.
9.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 9 Joints Under Special Loading Conditions • Forces in opposite members intersecting in two straight lines at a joint are equal. • The forces in two opposite members are equal when a load is aligned with a third member. The third member force is equal to the load (including zero load). • The forces in two members connected at a joint are equal if the members are aligned and zero otherwise. • Recognition of joints under special loading conditions simplifies a truss analysis.
10.
Vector Mechanics for
Engineers: Statics • In a simple space truss, m = 3n - 6 where m is the number of members and n is the number of joints. • Conditions of equilibrium for the joints provide 3n equations. For a simple truss, 3n = m + 6 and the equations can be solved for m member forces and 6 support reactions. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 10 Space Trusses • An elementary space truss consists of 6 members connected at 4 joints to form a tetrahedron. • A simple space truss is formed and can be extended when 3 new members and 1 joint are added at the same time. • Equilibrium for the entire truss provides 6 additional equations which are not independent of the joint equations.
11.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 11 Sample Problem 6.1 Using the method of joints, determine the force in each member of the truss. SOLUTION: • Based on a free-body diagram of the entire truss, solve the 3 equilibrium equations for the reactions at E and C. • Joint A is subjected to only two unknown member forces. Determine these from the joint equilibrium requirements. • In succession, determine unknown member forces at joints D, B, and E from joint equilibrium requirements. • All member forces and support reactions are known at joint C. However, the joint equilibrium requirements may be applied to check the results.
12.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 12 Sample Problem 6.1 SOLUTION: • Based on a free-body diagram of the entire truss, solve the 3 equilibrium equations for the reactions at E and C. 0 2000 lb24 ft 1000 lb12 ft E 6 ft MC E 10,000 lb Fx 0 Cx Cx 0 Fy 0 2000 lb - 1000 lb 10,000 lb Cy Cy 7000 lb
13.
Vector Mechanics for
Engineers: Statics 2000 lb FAB FAD F F DB DA F F © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition F T 1500 lb F T 2500 lb 6 - 13 Sample Problem 6.1 • Joint A is subjected to only two unknown member forces. Determine these from the joint equilibrium requirements. 4 3 5 AB F C AD 2500 lb • There are now only two unknown member forces at joint D. 2 3 DE DA 5 DB F C DE 3000 lb
14.
Vector Mechanics for
Engineers: Statics F F F F F F F F F © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 3 3 0 1500 2500 3750 6 - 14 Sample Problem 6.1 • There are now only two unknown member forces at joint B. Assume both are in tension. 4 0 1000 2500 y BE 3750 lb 4 5 5 BE FBE 3750 lb C x BC 5250 lb 5 5 BC FBC 5250 lb T • There is one unknown member force at joint E. Assume the member is in tension. 3 3 0 3000 3750 x EC 8750 lb 5 5 EC FEC 8750 lb C
15.
Vector Mechanics for
Engineers: Statics x F © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 15 Sample Problem 6.1 • All member forces and support reactions are known at joint C. However, the joint equilibrium requirements may be applied to check the results. 3 5250 8750 0 checks 5 4 7000 8750 0 checks 5 y F
16.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 16 Analysis of Trusses by the Method of Sections • When the force in only one member or the forces in a very few members are desired, the method of sections works well. • To determine the force in member BD, pass a section through the truss as shown and create a free body diagram for the left side. • With only three members cut by the section, the equations for static equilibrium may be applied to determine the unknown member forces, including FBD.
17.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 17 Trusses Made of Several Simple Trusses • Compound trusses are statically determinant, rigid, and completely constrained. m 2n 3 • Truss contains a redundant member and is statically indeterminate. m 2n 3 • Necessary but insufficient condition for a compound truss to be statically determinant, rigid, and completely constrained, m r 2n non-rigid rigid m 2n 3 • Additional reaction forces may be necessary for a rigid truss. m 2n 4
18.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 18 Sample Problem 6.3 Determine the force in members FH, GH, and GI. SOLUTION: • Take the entire truss as a free body. Apply the conditions for static equilib-rium to solve for the reactions at A and L. • Pass a section through members FH, GH, and GI and take the right-hand section as a free body. • Apply the conditions for static equilibrium to determine the desired member forces.
19.
Vector Mechanics for
Engineers: Statics 0 5 m 6 kN 10 m 6 kN 15 m 6 kN 7.5 kN A L F L A 0 20 kN © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 19 Sample Problem 6.3 SOLUTION: • Take the entire truss as a free body. Apply the conditions for static equilib-rium to solve for the reactions at A and L. 12.5 kN 20 m 1 kN 25 m 1 kN 25 m A L M y
20.
Vector Mechanics for
Engineers: Statics • Apply the conditions for static equilibrium to determine the desired member forces. 7.50 kN 10 m 1 kN 5 m 5.33 m 0 © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 20 Sample Problem 6.3 • Pass a section through members FH, GH, and GI and take the right-hand section as a free body. 13.13 kN 0 GI GI H F F M FGI 13.13 kN T
21.
Vector Mechanics for
Engineers: Statics 8 m FG 7.5 kN 15 m 1 kN 10 m 1 kN 5 m F FH GI 0 5 m 2 1 kN 10 m 1 kN 5 m cos 10 m 0 © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 21 Sample Problem 6.3 cos 8 m 0 13.82 kN 0 0.5333 28.07 15 m tan FH G F M GL FFH 13.82 kN C 1.371 kN 0.9375 43.15 8 m tan 3 GH GH L F F M HI FGH 1.371 kN C
22.
Vector Mechanics for
Engineers: Statics • Forces on two force members have known lines of action but unknown magnitude and sense. • Forces on multiforce members have unknown magnitude and line of action. They must be represented with two unknown components. © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 22 Analysis of Frames • Frames and machines are structures with at least one multiforce member. Frames are designed to support loads and are usually stationary. Machines contain moving parts and are designed to transmit and modify forces. • A free body diagram of the complete frame is used to determine the external forces acting on the frame. • Internal forces are determined by dismembering the frame and creating free-body diagrams for each component. • Forces between connected components are equal, have the same line of action, and opposite sense.
23.
Vector Mechanics for
Engineers: Statics Frames Which Cease To Be Rigid When Detached © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 23 From Their Supports • Some frames may collapse if removed from their supports. Such frames can not be treated as rigid bodies. • A free-body diagram of the complete frame indicates four unknown force components which can not be determined from the three equilibrium conditions. • The frame must be considered as two distinct, but related, rigid bodies. • With equal and opposite reactions at the contact point between members, the two free-body diagrams indicate 6 unknown force components. • Equilibrium requirements for the two rigid bodies yield 6 independent equations.
24.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 24 Sample Problem 6.4 Members ACE and BCD are connected by a pin at C and by the link DE. For the loading shown, determine the force in link DE and the components of the force exerted at C on member BCD. SOLUTION: • Create a free-body diagram for the complete frame and solve for the support reactions. • Define a free-body diagram for member BCD. The force exerted by the link DE has a known line of action but unknown magnitude. It is determined by summing moments about C. • With the force on the link DE known, the sum of forces in the x and y directions may be used to find the force components at C. • With member ACE as a free-body, check the solution by summing moments about A.
25.
Vector Mechanics for
Engineers: Statics 1 80 © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 25 Sample Problem 6.4 SOLUTION: • Create a free-body diagram for the complete frame and solve for the support reactions. Fy 0 Ay 480 N Ay 480 N MA 0 480 N100 mm B160 mm B 300 N Fx 0 B Ax Ax 300 N tan 28.07 150 Note:
26.
Vector Mechanics for
Engineers: Statics M F 0 sin 250 mm 300 N 60 mm 480 N 100 mm C DE F F C F 0 cos 300 N x x DE F C F 0 sin 480 N y y DE © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 26 Sample Problem 6.4 • Define a free-body diagram for member BCD. The force exerted by the link DE has a known line of action but unknown magnitude. It is determined by summing moments about C. 561 N DE FDE 561 N C • Sum of forces in the x and y directions may be used to find the force components at C. 0 561 Ncos 300 N x C Cx 795 N 0 561 Nsin 480 N y C Cy 216 N
27.
Vector Mechanics for
Engineers: Statics MA FDE FDE Cx © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 27 Sample Problem 6.4 • With member ACE as a free-body, check the solution by summing moments about A. cos 300 mm sin 100 mm 220 mm 561cos 300 mm 561sin 100 mm 795220 mm 0 (checks)
28.
Vector Mechanics for
Engineers: Statics © 2007 The McGraw-Hill Companies, Inc. All rights reserved. Eighth Edition 6 - 28 Machines • Machines are structures designed to transmit and modify forces. Their main purpose is to transform input forces into output forces. • Given the magnitude of P, determine the magnitude of Q. • Create a free-body diagram of the complete machine, including the reaction that the wire exerts. • The machine is a nonrigid structure. Use one of the components as a free-body. • Taking moments about A, a P b MA 0 aP bQ Q
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Vector Mechanics for
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