Please give me some instrcations to follow to get the output of this C cods? #include<stdio.h> int cal1 (int p, double q){ int w; w = p -q / 4 *( p % 5); return (w-1); } double cal2 (double t){ int i; double tt; tt = 0.0; for (i=1; i <= t; ++i) tt = tt + cal1(i,t); return (tt*t); } int main (void){ printf (\"%.4f\ \", cal2(4.0)); return (0);} Solution * Declare the function in header // Example program #include <iostream> #include <string> //function prototype also called function declaration int cal1 (int p, double q); double cal2 (double t); int cal1 (int p, double q){ int w; w = p -q / 4 *( p % 5); return (w-1); } double cal2 (double t){ int i; double tt; tt = 0.0; for (i=1; i <= t; ++i) tt = tt + cal1(i,t); return (tt*t); } int main() { printf (\"%.4f\ \", cal2(2.0)); return (0); } .

1. Please give me some instrcations to follow to get the output of this C cods?
#include<stdio.h>
int cal1 (int p, double q){
int w;
w = p -q / 4 *( p % 5);
return (w-1);
}
double cal2 (double t){
int i;
double tt;
tt = 0.0;
for (i=1; i <= t; ++i)
tt = tt + cal1(i,t);
return (tt*t);
}
int main (void){
printf ("%.4f ", cal2(4.0));
return (0);}
Solution
* Declare the function in header
// Example program
#include <iostream>
#include <string>
//function prototype also called function declaration
int cal1 (int p, double q);
double cal2 (double t);
int cal1 (int p, double q){
int w;
w = p -q / 4 *( p % 5);

2. return (w-1);
}
double cal2 (double t){
int i;
double tt;
tt = 0.0;
for (i=1; i <= t; ++i)
tt = tt + cal1(i,t);
return (tt*t);
}
int main()
{
printf ("%.4f ", cal2(2.0));
return (0);
}