1.
Please answer the question neatly and clearly.
Be as detailed as possible. Show examples if necessary.
Also. ***use the ICE table***. (If applicable)
Initial(M)
Change(M)
Equilibrium (M)
37. The solubility of zinc(Il) phosphate, Zns(PO.), in pure water is 1.5 x 10 moles per liter.
Calculate the value of Ksp for zinc(II) phosphate from this data. A) 2.3 x 10-14 B) 5.1 x 10-28
C) 2.7 x 10-33 D) 8.2 x 10.33 E) 7.6 x 10-35
Solution
Zn3(PO4)2(s) ---------------> 3Zn^2+ (aq) + 2PO4^3- (aq)
IÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -
                                       Â
  0                        0
CÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -
                                       Â
  3s                     2s
EÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â -
                                       Â
    3s                    2s
Ksp     = [Zn^2+]^3[PO4^3-]^2
= (3s)^3(2s)^2

2.
= 108s^5
= 108(1.5*10^-7)^5
= 8.2*10^-33
D. 8.2*10^-33