3. What is Refraction?
Refraction is the bending of light as it
travels from one medium to another.
4. Refraction
In vacuum, light travels with a speed
c = 3.00 x 108 m/s
In a transparent medium, (ex. water or
glass) the speed of light is slower than
its speed in vacuum.
WHY? Ans. interactions between photons
and molecules of the medium
5. Refraction
What EXACTLY is light doing when it reaches a
new medium?
Air
Water
Incident ray Reflected ray
Refracted ray
Angle of
Incidence
Angle of
Reflection
Angle of
Refraction
6. Refraction
Air
Water
Normal
Incident ray
Refracted ray
θi
θr
Normal
is a line drawn
perpendicular to the surface
Incident ray
is the light ray in 1st
medium (air)
Refracted ray
is the light ray in the
2nd medium (water)
Angle of incidence, i
is the angle between the
incident ray & the normal
Angle of refraction, r
is the angle between the
refracted ray & the
normal
Law of Refraction #1
The incident ray, refracted ray, and normal lie in one play.
7. Air
Glass
Normal
Higher speed (lower index of refraction)
Lower speed (higher index of refraction)
Refraction
θi
θr
Refracted ray bends
away from the normal
Original path of
light ray
8. Refraction
Air
Glass
Higher speed (lower index of refraction)
Lower speed (higher index of refraction)
Refracted ray
bends towards the
normal
θi
Normal
θr Original path
of a light ray
9. Refraction
Air
(a) Less dense to denser medium (b) Denser to less dense medium
Air
Glass
Glass
θi
θr
θi
θr
(a) When light ray enters a medium with smaller index of refraction
to a medium with larger index of refraction, it bends TOWARDS the
normal.
(b) When light ray enters a medium with larger index of refraction, it
bends AWAY the normal.
Law of refraction #2
When a ray of light enters a denser medium, it bends TOWARDS the
normal
When a ray of light enters a less dense medium, it bends AWAY from
the normal.
10. What is “index of refraction”?
The index of refraction (n) for a material is
the ratio of the speed of light (c) in vacuum to
that of the speed (v) in the medium.
The ratio of the two speeds can be compared
c
n
v
c
v
c
n
v
Medium Refracted Index (n)
Vacuum 1.00
Air 1.0003
Water 1.33
Ethanol 1.36
Glycerine 1.47
Crown Glass 1.52
Quartz 1.54
Flint Glass 1.61
Diamond 2.42
11. Sample Problem
What is the speed of light in a diamond if
its index of refraction is 2.42?
Light travels from air (n = 1) into glass, where its velocity reduces to
only 2 x 108 m/s.
What is the index of refraction for glass?
vair = c
vG = 2 x 108 m/s
Glass
Air
8
8
3 x 10 m/s
2 x 10 m/s
c
n
v
Solution:
Answer:
n= 1.50
What is the speed of light in quarts (1.54)?
Solution
V= c/n
V=
3.00𝑥108 𝑚/𝑠
1.54
Given
n= 1.54
c= 3.00× 𝟏𝟎 𝟖 m/s
v= ?
Answer
V= 1.95x𝟏𝟎 𝟖
m/s
12. Law of refraction
1. The incident ray, refracted ray, and normal lie in one plane.
2. When a ray of light enters a denser medium, it bends
TOWARDS the normal.
When a ray of light enters a less dense medium,
it bends AWAY from the normal.
3. Snell’s Law is the relationship between the angle of
incidence and angle of refraction and the angle of refraction of
both materials.
How can we figure out the angle of our
refracted ray?
We use Snell’s Law
Willebrord van Roijen Snell
(1580-1626)
Sample Problem
A ray of light traveling through air is
incident on a smooth surface of water
at an angle of 30° to the normal.
Calculate the angle of refraction for the
ray as it enters the water.
Air
Water
𝒏 𝟏sin𝐬𝐢𝐧 𝜽 𝒊 = 𝒏 𝟐 𝐬𝐢𝐧 𝜽 𝒓
Formula
𝐬𝐢𝐧 𝜽 𝒓
𝒏 𝟏 𝐬𝐢𝐧 𝜽 𝒊
𝒏 𝟐
Given
𝒏 𝟏= 1.0003 (air)
𝒏 𝟐= 1.33 (water)
sin 𝜽 𝒊 = 𝟑𝟎°
Find 𝜽𝒓 = ?
Solution
sin 𝜽 𝒓 =
𝟏. 𝟎𝟎𝟎𝟑 sin 𝟑𝟎°
𝟏. 𝟑𝟑
𝐬𝐢𝐧 𝜽𝒓 = 𝟎. 𝟑𝟕𝟔𝟎𝟓𝟐𝟔𝟑𝟏𝛉𝐫 = 𝐬𝐢𝐧−𝟏
𝟎. 𝟑𝟕𝟔𝟎𝟓𝟐𝟔𝟑𝟏
Answer:
𝜽𝒓 = 𝟐𝟐. 𝟎𝟗°
13. Mmmm..…….
Fish and
Chips!!!
Normal
Effects of Refraction
Real depth
Apparent
depth
To an observer standing at
the side of a swimming
pool, objects under the
water appear to be nearer
the surface than they really
are.
It can be shown mathematically that index of refraction is the ratio
of real depth to apparent depth.
Formula:
n=
𝑹𝒆𝒂𝒍 𝒅𝒆𝒑𝒕𝒉
𝑨𝒑𝒑𝒂𝒓𝒆𝒏𝒕 𝒅𝒆𝒑𝒕𝒉
Sample Problem
A grizzley bear is seating on a rock in the middle of a calm river,
when she observes a fish directly below. If the apparent deep of a fis
is 0.40m, what is the actual depth of a fish?
Given
n= 1.33 (water)
App. Depth= 0.40m
Find Actual depth=??
Solution
Real Depth= n* apparent depth
Real depth= (1.33)(0.40m)
Real depth= 0.53m
14. Total Internal Reflection
When light passes at an angle from a medium of higher index to
one of lower index, the emerging ray bends away from the normal.
Water
Air
light
i = r
Critical
angle
qc
900
When the angle reaches a certain
maximum, it will be reflected
internally.
The critical angle is defined
as the angle of incidence in
the optically denser medium
for which the angle of
refraction in the optically less
dense medium is 90°.
n
So the question is , how can
you calculate the critical
angle?
Remember, it is when the
refracted ray is equal to 90
degrees
ɵc = sin-1 (𝒏 𝟐/𝒏 𝟏)
Sample Problem
What is the critical angle for
water-air interface
Given
n1= (water) 1.33
n2= (air) 1.0003
𝜽𝒄 = sin−𝟏
𝟏. 𝟎𝟎𝟎𝟑
𝟏. 𝟑𝟑
𝜽𝒄 = 𝟒𝟖. 𝟕𝟕°
Notas do Editor
Refraction is based on the idea that LIGHT is passing through one MEDIUM into another.
It is the change in direction of a wave due to a change in its speed.
It is most commonly observed when a wave passes from one medium to another.
At the boundary between the media, the wave's phase velocity is altered, usually causing a change in direction
The wavelength of the wave changes but its frequency remains constant.
What does this have to do with refraction?
The difference in speed causes light rays to bend (refracted ) when traveling across different transparent materials!!!
So lets say for instance we have here a two medium (Click2) which is the air and water, and to see the boundary between the two medium we need to put a horizonal line and a vertical line to have or make a simple plane.
Accordng to the law of reflecion Angle of incidence = Angle of Reflection
Law of refraction
Angle of Incidence > or < the Angle of refraction depending on the direction of the light
Some of the light REFLECTS off the boundary and some of the light REFRACTS through the boundary
So we have here plane where in we have two meduim whch are the glass and air.
The glass can lower the speed of light because It has a higher index of refracion compare with air that has a higher spedd of light but lower index of refraction.
Other problem!! Animaion
An
A scientist by the name of Willebrord Snell discovered that the ratios of the index’s and the ratio of the sine of the angles are the same value!
The fundamental law that governs the refraction of light is Snell's Law
Ok…… so how is knowing about refraction useful?
An object seen in the water will usually appear to be at a different depth than it actually is, this is due to the refraction of light rays as they travel from the water into the air.
The depth that the water appears to be when viewed from above is known as the apparent depth. While real depth it the actual depth.
The apparent depth is less than the real depth because rays of light are refracted from the normal as they leave the water
The eye, believing that light travels in straight lines, sees objects closer to the surface due to refraction. Such distortions are common.
There is a special type of refraction that can occur ONLY when traveling from a HIGH “n” medium to a LOW “n” medium.
The angle of incidence is small therefore, it has a both reflected and refracted ray
bThe angle of incidence is equal to the critical angle C. So the angle of refraction will be 90° and it also has a strong reflected ray
The angle of incidence is larger than the critical angel. The angle of refraction will become smaller again. There will be no refracted ray. The light ray will be reflected the
same way back.
Summary:
Total internal reflection takes place when light rays are travelling from an optically denser region to a less dense region, and
the angle of incidence is greater than the critical angle.