how do I do all of number 4 me Oetermine the equstion. Determine which (T in the anid ) of reaction took place 111 ots) a. Molecular Equation b. Complete lonic Equation C. Net lonic Equation s. Determine the products formed in the following reaction and write the complete ionic equation, and ne enuation netermine which type(s) of reaction took place. (11 pts Solution 4 .Sol:- The given reaction is a type of precipitation reaction in which BaSO 4 forms white precipitates . (a) Molecular balanced equation is :- Ba(NO 3 ) 2 (aq) + K 2 SO 4 (aq) -------------> BaSO 4 (s) + 2 KNO 3 (aq) white ppt. (b) Complete ionic equation is :- Ba(NO 3 ) 2 (aq) , K 2 SO 4 (aq) and KNO 3 (aq) are strong electrolytes therefore they are completely dissociated into ions in aqueous solution while BaSO 4 (s) is weak electrolyte which forms white precipitates and does not dissociated into ions as : Ba 2+ (aq) + 2NO 3 - (aq) + 2K + (aq) + SO 4 2- (aq) ---------> BaSO 4 (s) + 2 K + (aq) + 2NO 3 - (aq) (c) Net ionic equation is :- Remove the spectator ions i.e 2K + and 2NO 3 - in order to write net balanced equation as : Ba 2+ (aq) + SO 4 2- (aq) ---------> BaSO 4 (s) .

1. how do I do all of number 4
me Oetermine the equstion. Determine which (T in the anid ) of reaction took place 111 ots) a.
Molecular Equation b. Complete lonic Equation C. Net lonic Equation s. Determine the products
formed in the following reaction and write the complete ionic equation, and ne enuation
netermine which type(s) of reaction took place. (11 pts
Solution
4 .Sol:- The given reaction is a type of precipitation reaction in which BaSO 4 forms white
precipitates .
(a) Molecular balanced equation is :-
Ba(NO 3 ) 2 (aq) + K 2 SO 4 (aq) -------------> BaSO 4 (s) + 2 KNO 3 (aq)
white ppt.
(b) Complete ionic equation is :- Ba(NO 3 ) 2 (aq) , K 2 SO 4 (aq) and KNO 3 (aq) are strong
electrolytes therefore they are completely dissociated into ions in aqueous solution while BaSO 4
(s) is weak electrolyte which forms white precipitates and does not dissociated into ions as :
Ba 2+
(aq) + 2NO 3
-
(aq) + 2K +
(aq) + SO 4
2-
(aq) ---------> BaSO 4 (s) + 2 K +
(aq) + 2NO 3
-
(aq)
(c) Net ionic equation is :- Remove the spectator ions i.e 2K +
and 2NO 3
-
in order to write net
balanced equation as :
Ba 2+
(aq) + SO 4
2-
(aq) ---------> BaSO 4 (s)