1. Confidence Intervals for the Mean
1.Assume that a sample is used to estimate a population
mean μμ. Find the margin of error M.E. that corresponds to a
sample of size 11 with a mean of 30.3 and a standard deviation
of 13.8 at a confidence level of 99.5%.
Report ME accurate to one decimal place because the sample
statistics are presented with this accuracy.
M.E. =
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.
2.The effectiveness of a blood-pressure drug is being
investigated. An experimenter finds that, on average, the
reduction in systolic blood pressure is 19.8 for a sample of size
906 and standard deviation 19.6.
Estimate how much the drug will lower a typical patient's
systolic blood pressure (using a 95% confidence level).
Enter your answer as a tri-linear inequality accurate to one
decimal place (because the sample statistics are reported
accurate to one decimal place).
< μ <
Answer should be obtained without any preliminary rounding.
3.You must estimate the mean temperature (in degrees
Fahrenheit) with the following sample temperatures:

2. 62.3
39.4
56.7
57.7
63.5
65.5
53.9
67.7
63.1
56.5
61.7
59.7
Find the 98% confidence interval. Enter your answer as
an open-interval (i.e., parentheses) accurate to two decimal
places (because the sample data are reported accurate to one
decimal place).
98% C.I. =
Answer should be obtained without any preliminary rounding.
4.SAT scores are distributed with a mean of 1,500 and a
standard deviation of 300. You are interested in estimating the
average SAT score of first year students at your college. If you
would like to limit the margin of error of your 95% confidence
interval to 25 points, how many students should you sample?
Make sure to give a whole number answer.
5.For a confidence level of 99% with a sample size of 21, find
the critical t value.
For Question #5 when you are asked to use find the t-value
corresponding to a certain confidence level and degrees of

3. freedom use this link: http://www.usablestats.com/calcs/tinv
Remember that we are only calculating Confidence Intervals
using t!
6.If n=26, ¯xx¯(x-bar)=31, and s=4, find the margin of error at
a 95% confidence level
Give your answer to two decimal places.
7.Assume that a sample is used to estimate a population
mean μμ. Find the margin of error M.E. that corresponds to a
sample of size 13 with a mean of 64.5 and a standard deviation
of 17.9 at a confidence level of 95%.
Report ME accurate to one decimal place because the sample
statistics are presented with this accuracy.
M.E. =
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.
THIS LINKS MIGHT BE USEFUL:
http://onlinestatbook.com/2/estimation/intro.html
http://onlinestatbook.com/2/estimation/characteristics.html
http://onlinestatbook.com/2/estimation/confidence.html
http://onlinestatbook.com/2/estimation/mean.html
http://onlinestatbook.com/2/estimation/t_distribution.html
https://www.learner.org/courses/againstallodds/unitpages/unit26
.html
https://www.youtube.com/watch?v=MuIir6rGNN0&feature=yout
u.be

4. https://docs.google.com/presentation/d/1duKjyZ4ic8xddID8ec0
XqEJBQhlBa8fVKhwZNfzDc7w/edit#slide=id.p3
http://onlinestatbook.com/2/estimation/t_distributionM.html
https://www.youtube.com/watch?v=Zedn1wUS7Aw&feature=yo
utu.be
https://www.youtube.com/watch?v=NB-
lDP63aww&feature=youtu.be
Confidence Intervals for Proportions
1.Express the confidence interval 14.3%±8.1%14.3%±8.1% in
interval form.
Express the answer in decimal format (do not enter as percents).
2.We wish to estimate what percent of adult residents in a
certain county are parents. Out of 100 adult residents sampled,
83 had kids. Based on this, construct a 90% confidence interval
for the proportion, p, of adult residents who are parents in this
county.
Give your answers as decimals, to three places.
< p <
3.Assume that a sample is used to estimate a population
proportion p. Find the margin of error M.E. that corresponds to
a sample of size 344 with 40.1% successes at a confidence level
of 90%.
M.E. = %
Answer should be obtained without any preliminary rounding.
However, the critical value may be rounded to 3 decimal places.

5. Round final answer to one decimal place
4.Giving a test to a group of students, the grades and gender are
summarized below
A
B
C
Total
Male
13
6
9
28
Female
7
16
5
28
Total
20
22
14
56
Let ππ represent the percentage of all male students who would
receive a grade of B on this test. Use a 90% confidence interval
to estimate p to three decimal places.
Enter your answer as a tri-linear inequality using decimals (not
percents).
< p <

6. 5.You want to obtain a sample to estimate a population
proportion. At this point in time, you have no reasonable
estimate for the population proportion. You would like to be
98% confident that you esimate is within 0.5% of the true
population proportion. How large of a sample size is required?
n =
Do not round mid-calculation. However, use a critical value
accurate to three decimal places.
6.A political candidate has asked you to conduct a poll to
determine what percentage of people support her.
If the candidate only wants a 10% margin of error at a 95%
confidence level, what size of sample is needed?
Give your answer in whole people.
7.If n=310 and ˆpp^ (p-hat) =0.22, find the margin of error at a
95% confidence level
Give your answer to three decimals
8.Out of 600 people sampled, 450 had kids. Based on this,
construct a 95% confidence interval for the true population
proportion of people with kids.

7. Give your answers as decimals, to three places
< p <
9.Express the confidence
interval (67.5%,74.3%)(67.5%,74.3%) in the form
of ˆp±MEp^±ME.
% ± %
10.Express the confidence
interval 61.7%<p<77.3%61.7%<p<77.3% in the form
of ˆp±MEp^±ME.
% ±± %
You want to obtain a sample to estimate a population
proportion. Based on previous evidence, you believe the
population proportion is approximately p∗ =72%p∗ =72%. You
would like to be 90% confident that your estimate is within 3%
of the true population proportion. How large of a sample size is
required?
n =
Do not round mid-calculation. However, use a critical value
accurate to three decimal places.
THIS LINKS MIGHT BE USEFUL:
https://www.youtube.com/watch?v=3ReWri_jh3M&feature=yout
u.be
https://www.youtube.com/watch?v=FCxPxAWToJk&feature=yo
utu.be

8. https://ohm-website-
data.s3.amazonaws.com/cfiles/2408/ModelCIProp.pdf
https://ohm-website-
data.s3.amazonaws.com/cfiles/2408/ReadingE10.pdf
OTHER QUESTIONS
1.We wish to estimate what percent of adult residents in a
certain county are parents. Out of 500 adult residents sampled,
355 had kids. Based on this, construct a 95% confidence
interval for the proportion, p, of adult residents who are parents
in this county.
Give your answers as decimals, to three places.
< p <
2. Giving a test to a group of students, the grades and gender
are summarized below
A
B
C
Total
Male
12
7
9
28
Female
16
19
11
46
Total

9. 28
26
20
74
Let ππ represent the percentage of all male students who would
receive a grade of A on this test. Use a 98% confidence interval
to estimate p to three decimal places.
Enter your answer as a tri-linear inequality using decimals (not
percents).
< p <
3. If n=340 and ˆpp^ (p-hat) =0.69, find the margin of error at a
90% confidence level
Give your answer to three decimals
4.You want to obtain a sample to estimate a population
proportion. Based on previous evidence, you believe the
population proportion is approximately p∗ =58%p∗ =58%. You
would like to be 99.9% confident that your esimate is within 5%
of the true population proportion. How large of a sample size is
required?
n =

10. Do not round mid-calculation. However, use a critical value
accurate to three decimal places.
5.For a confidence level of 98% with a sample size of 17, find
the critical t value.
6.If n=20, ¯xx¯(x-bar)=34, and s=4, find the margin of error at
a 95% confidence level
Give your answer to two decimal places.
7.Karen wants to advertise how many chocolate chips are in
each Big Chip cookie at her bakery. She randomly selects a
sample of 52 cookies and finds that the number of chocolate
chips per cookie in the sample has a mean of 16.8 and a
standard deviation of 2.6. What is the 80% confidence interval
for the number of chocolate chips per cookie for Big Chip
cookies? Enter your answers accurate to one decimal place
(because the sample statistics are reported accurate to one
decimal place).
< μ <