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Enthalpy
Enthalpy
A thermodynamic quantity equivalent to the total heat content of a
system is called enthalpy. Denoted by ‘H’.
Enthalpy change(∆𝐻)
1. Exothermic and
2. Endothermic reactions
Most chemical reactions are accompanied by energy changes.
Some absorbs energy while some releases it.
Exothermic reaction:
An exothermic reaction is a reaction that releases energy to the
surroundings. Therefore the product contain less energy with respect
to the reactants. The energy is released as heat energy, so the
surroundings warm.
Examples see in board
Endothermic reaction:
An endothermic reaction is a reaction that absorbs energy from the
surroundings. Therefore the products contain more energy with
respect to the reactants. The energy is absorbed as heat energy, so the
surroundings cool down.
Examples see in board
An energy level diagram shows the relative
energies of the products and reactants. The
higher its energy, the higher its position.
An exothermic reaction
An endothermic reaction
i. Examples of exothermic reactions are neutralisation, combustion,
dissolving anhydrous salts and the reaction between acids and metal
carbonates.
ii. Examples of endothermic reactions are atomisation, photosynthesis,
dissolving crystalline salts and thermal decomposition.
Standard enthalpy changes:
The standard condition
To make comparison of enthalpy changes a fair comparison, same
conditions
must be used. These are called the standard conditions:
- A pressure of 100 kPa (approximately atmospheric pressure).
- A temperature of 298 K or 25 °C.
- Every substance involved must be in its normal physical state at 100
kPa and 298 K. For example, water is in liquid, not ice or steam.
Standard enthalpy changes can be represented by the symbol ΔH°. This
refers that the reaction is carried out under standard conditions. For
example:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ; ΔH° = -890.3 kJ mol⁻1
Various enthalpy changes:
Enthalpy changes are described according to the type of reaction.
Examples:
1. Standard enthalpy change of reaction, ΔH°r (in general)
2. Standard enthalpy change of formation, ΔH°f
3. Standard enthalpy change of combustion, ΔH°c
4. Standard enthalpy change of neutralisation, ΔH°n
5. Standard enthalpy change of atomisation, ΔH°at
6. Standard enthalpy change of solution, ΔH°sol
7. Standard enthalpy change of hydration, ΔH°hyd
Standard enthalpy change of reaction
Standard enthalpy change of reaction, ΔH°r is the enthalpy change
when the amount of reactants shown in the equation react to give
products under standard condition. The reactants and products must
be in their standard states.
• 2H2(g) + O2(g) → 2H2O(l) ; ΔH°r = -576 kJ mol⁻1
Standard enthalpy change of formation:
Standard enthalpy change of formation, ΔH°f is the enthalpy change
when one mole of a compound is formed from its elements under
standard condition. The reactants and products must be in their
standard states.
2Fe(s) + 1.5O2(g) → Fe2O3(s) ; ΔH°f [ Fe2O3(s) ] = -824.5 kJ mol⁻1
The standard enthalpy change of formation can be exothermic or
endothermic.
Other examples ……………in board.
Standard enthalpy change of combustion:
Standard enthalpy change of combustion, ΔH°c is the enthalpy change
when one mole of a substance is burnt in excess oxygen under
standard conditions. The reactants and products must be in their
standard states.
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ; ΔH°c [ CH4(g) ] = -890.3 kJ mol⁻1
Note : The standard enthalpy change of combustion is always
exothermic.
Standard enthalpy change of neutralisation:
Standard enthalpy change of neutralisation, ΔH°n is the enthalpy
change when one mole of water is formed by the reaction of an acid
with an alkali under standard conditions.
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) ; ΔH°n = -57.1 kJ mol⁻1
For any acid-alkali reaction, the ionic equation is:
H⁺(aq) + OH⁻(aq) → H2O(l)
Note:
• The enthalpy change of neutralisation between strong acids and
strong bases is a constant(-57.1 kJ mol⁻1). This is because all strong
acids and strong bases dissociate completely in water to form
aqueous ions.
• The enthalpy change of neutralisation involving weak acids or weak
bases is less than 57.1 kJ mol⁻1. For example:
CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l) ;ΔH°n = -56.1 kJ
mol⁻1
• NaOH(aq) + HCN(aq) → NaCN(aq) + H2O(l) ; ΔH°n = -11.7 kJ mol⁻1
The standard enthalpy change of
neutralisation is always
exothermic.
Standard enthalpy change of atomisation,
ΔH° at :
Standard enthalpy change of atomisation, ΔH°at is the enthalpy
change when one mole of gases atoms is formed from its element
under standard conditions.
1/2H2(g) → H(g) ; ΔH°at = +218 kJ mol⁻1
Na(s) → Na(g) ; ΔH°at = +107 kJ mol⁻1
By definition, the standard enthalpy change of atomisation of the
noble gases is zero because all of them exist as monoatomic gases at
standard conditions.
The standard enthalpy change of atomisation of diatomic
gases(example: O2, Cl2, N2 and F2) is equal to half the value of their
bond energies.
The standard enthalpy change of atomisation is always endothermic
Standard enthalpy change of solution, ΔH°sol
Standard enthalpy change of solution, ΔH°sol is the enthalpy change
when one mole of solute is dissolved in a solvent to form an infinitely
dilute solution under standard conditions.
NaCl(s) + aq → NaCl(aq) ; ΔH°sol = +6.0 kJ mol⁻1
NaOH(s) + aq → NaOH(aq) ; ΔH°sol = -44.5 kJ mol⁻1
An infinitely dilute solution is one which does not produce any further
enthalpy change when more solvent is added.
The standard enthalpy change of solution can be exothermic or
endothermic.
Standard enthalpy change of hydration of an
anhydrous salt, ΔH°hyd
It is the enthalpy change when one mole of hydrated salt is formed
from one mole of the anhydrous salt under standard conditions.
Example:
Na2S2O3 (s) + 5H2O(l) ⇢ Na2S2O3.5H2O(s) ∆𝐻 𝑜 = −55 𝐾𝐽𝑚𝑜𝑙
− 1
Measuring enthalpy changes:
Measuring the enthalpy change neutralisation i.e. to calculate the
enthalpy change of the reaction between sodium hydroxide, NaOH(aq)
and hydrochloric acid, HCl(aq).
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
1. Pour 25 cm3 of NaOH into 25 cm3 of HCl in a polystyrene
cup(polystyrene cup is used because it is a good heat insulator). Both
solutions have concentrations of 1.0 mol dm⁻3.
ii. Measure the initial and maximum temperature reached.
iii. For example, the mean initial temperature of both solutions is 18.1
°C and the maximum temperature reached is 24.8 °C. Then, ΔT = 6.7 °C.
iv. Mass of both solutions is (25+25) x 1 = 50 g since
density = mass/volume.
v. Therefore heat released = 50 x 4.18 x 6.7 = 1400 J = 1.4 kJ
vi. Number of moles of water(n)=c× v= 1 × 25/1000= 0.025
vii. Therefore ΔH = -(1.4/0.025) = -56 kJ mol⁻1
To calculate the enthalpy change of the reaction of
combustion of ethanol, C2H5OH.
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)
In this experiment, a spirit burner is used to combust the flammable
liquid ethanol. The heat evolved is used to heat up the water, the
maximum temperature reached is then measured.
ii. Mass of water = 250 g
Initial temperature of water = 19.5 °C
Maximum temperature of water = 23.7 °C
Initial mass of ethanol = 41.36 g
Final mass of ethanol = 41.18 g
iii. Therefore, ΔT = 4.2 °C and m = 250 g.
iv. Heat released = 250 x 4.18 x 4.2 = 4389 J = 4.389 kJ
v. Number of moles of ethanol burned = 0.18/46 = 0.0039 mol
vi. Therefore ΔH = -(4.389/0.0039) = -1100 kJ mol⁻1
Enthalpy changes in chemical reactions

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Enthalpy changes in chemical reactions

  • 2. Enthalpy A thermodynamic quantity equivalent to the total heat content of a system is called enthalpy. Denoted by ‘H’.
  • 3. Enthalpy change(∆𝐻) 1. Exothermic and 2. Endothermic reactions Most chemical reactions are accompanied by energy changes. Some absorbs energy while some releases it.
  • 4. Exothermic reaction: An exothermic reaction is a reaction that releases energy to the surroundings. Therefore the product contain less energy with respect to the reactants. The energy is released as heat energy, so the surroundings warm. Examples see in board
  • 5. Endothermic reaction: An endothermic reaction is a reaction that absorbs energy from the surroundings. Therefore the products contain more energy with respect to the reactants. The energy is absorbed as heat energy, so the surroundings cool down. Examples see in board
  • 6. An energy level diagram shows the relative energies of the products and reactants. The higher its energy, the higher its position.
  • 9. i. Examples of exothermic reactions are neutralisation, combustion, dissolving anhydrous salts and the reaction between acids and metal carbonates. ii. Examples of endothermic reactions are atomisation, photosynthesis, dissolving crystalline salts and thermal decomposition.
  • 10. Standard enthalpy changes: The standard condition To make comparison of enthalpy changes a fair comparison, same conditions must be used. These are called the standard conditions: - A pressure of 100 kPa (approximately atmospheric pressure). - A temperature of 298 K or 25 °C. - Every substance involved must be in its normal physical state at 100 kPa and 298 K. For example, water is in liquid, not ice or steam.
  • 11. Standard enthalpy changes can be represented by the symbol ΔH°. This refers that the reaction is carried out under standard conditions. For example: CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ; ΔH° = -890.3 kJ mol⁻1
  • 12. Various enthalpy changes: Enthalpy changes are described according to the type of reaction. Examples: 1. Standard enthalpy change of reaction, ΔH°r (in general) 2. Standard enthalpy change of formation, ΔH°f 3. Standard enthalpy change of combustion, ΔH°c 4. Standard enthalpy change of neutralisation, ΔH°n 5. Standard enthalpy change of atomisation, ΔH°at 6. Standard enthalpy change of solution, ΔH°sol 7. Standard enthalpy change of hydration, ΔH°hyd
  • 13. Standard enthalpy change of reaction Standard enthalpy change of reaction, ΔH°r is the enthalpy change when the amount of reactants shown in the equation react to give products under standard condition. The reactants and products must be in their standard states. • 2H2(g) + O2(g) → 2H2O(l) ; ΔH°r = -576 kJ mol⁻1
  • 14. Standard enthalpy change of formation: Standard enthalpy change of formation, ΔH°f is the enthalpy change when one mole of a compound is formed from its elements under standard condition. The reactants and products must be in their standard states. 2Fe(s) + 1.5O2(g) → Fe2O3(s) ; ΔH°f [ Fe2O3(s) ] = -824.5 kJ mol⁻1 The standard enthalpy change of formation can be exothermic or endothermic. Other examples ……………in board.
  • 15. Standard enthalpy change of combustion: Standard enthalpy change of combustion, ΔH°c is the enthalpy change when one mole of a substance is burnt in excess oxygen under standard conditions. The reactants and products must be in their standard states. CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ; ΔH°c [ CH4(g) ] = -890.3 kJ mol⁻1 Note : The standard enthalpy change of combustion is always exothermic.
  • 16. Standard enthalpy change of neutralisation: Standard enthalpy change of neutralisation, ΔH°n is the enthalpy change when one mole of water is formed by the reaction of an acid with an alkali under standard conditions. HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) ; ΔH°n = -57.1 kJ mol⁻1 For any acid-alkali reaction, the ionic equation is: H⁺(aq) + OH⁻(aq) → H2O(l)
  • 17. Note: • The enthalpy change of neutralisation between strong acids and strong bases is a constant(-57.1 kJ mol⁻1). This is because all strong acids and strong bases dissociate completely in water to form aqueous ions. • The enthalpy change of neutralisation involving weak acids or weak bases is less than 57.1 kJ mol⁻1. For example: CH3COOH(aq) + NaOH(aq) → CH3COONa(aq) + H2O(l) ;ΔH°n = -56.1 kJ mol⁻1 • NaOH(aq) + HCN(aq) → NaCN(aq) + H2O(l) ; ΔH°n = -11.7 kJ mol⁻1
  • 18. The standard enthalpy change of neutralisation is always exothermic.
  • 19. Standard enthalpy change of atomisation, ΔH° at : Standard enthalpy change of atomisation, ΔH°at is the enthalpy change when one mole of gases atoms is formed from its element under standard conditions. 1/2H2(g) → H(g) ; ΔH°at = +218 kJ mol⁻1 Na(s) → Na(g) ; ΔH°at = +107 kJ mol⁻1
  • 20. By definition, the standard enthalpy change of atomisation of the noble gases is zero because all of them exist as monoatomic gases at standard conditions. The standard enthalpy change of atomisation of diatomic gases(example: O2, Cl2, N2 and F2) is equal to half the value of their bond energies. The standard enthalpy change of atomisation is always endothermic
  • 21. Standard enthalpy change of solution, ΔH°sol Standard enthalpy change of solution, ΔH°sol is the enthalpy change when one mole of solute is dissolved in a solvent to form an infinitely dilute solution under standard conditions. NaCl(s) + aq → NaCl(aq) ; ΔH°sol = +6.0 kJ mol⁻1 NaOH(s) + aq → NaOH(aq) ; ΔH°sol = -44.5 kJ mol⁻1
  • 22. An infinitely dilute solution is one which does not produce any further enthalpy change when more solvent is added. The standard enthalpy change of solution can be exothermic or endothermic.
  • 23. Standard enthalpy change of hydration of an anhydrous salt, ΔH°hyd It is the enthalpy change when one mole of hydrated salt is formed from one mole of the anhydrous salt under standard conditions. Example: Na2S2O3 (s) + 5H2O(l) ⇢ Na2S2O3.5H2O(s) ∆𝐻 𝑜 = −55 𝐾𝐽𝑚𝑜𝑙 − 1
  • 24. Measuring enthalpy changes: Measuring the enthalpy change neutralisation i.e. to calculate the enthalpy change of the reaction between sodium hydroxide, NaOH(aq) and hydrochloric acid, HCl(aq). NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) 1. Pour 25 cm3 of NaOH into 25 cm3 of HCl in a polystyrene cup(polystyrene cup is used because it is a good heat insulator). Both solutions have concentrations of 1.0 mol dm⁻3.
  • 25. ii. Measure the initial and maximum temperature reached.
  • 26. iii. For example, the mean initial temperature of both solutions is 18.1 °C and the maximum temperature reached is 24.8 °C. Then, ΔT = 6.7 °C. iv. Mass of both solutions is (25+25) x 1 = 50 g since density = mass/volume. v. Therefore heat released = 50 x 4.18 x 6.7 = 1400 J = 1.4 kJ vi. Number of moles of water(n)=c× v= 1 × 25/1000= 0.025 vii. Therefore ΔH = -(1.4/0.025) = -56 kJ mol⁻1
  • 27. To calculate the enthalpy change of the reaction of combustion of ethanol, C2H5OH. C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g) In this experiment, a spirit burner is used to combust the flammable liquid ethanol. The heat evolved is used to heat up the water, the maximum temperature reached is then measured. ii. Mass of water = 250 g Initial temperature of water = 19.5 °C Maximum temperature of water = 23.7 °C Initial mass of ethanol = 41.36 g Final mass of ethanol = 41.18 g
  • 28.
  • 29. iii. Therefore, ΔT = 4.2 °C and m = 250 g. iv. Heat released = 250 x 4.18 x 4.2 = 4389 J = 4.389 kJ v. Number of moles of ethanol burned = 0.18/46 = 0.0039 mol vi. Therefore ΔH = -(4.389/0.0039) = -1100 kJ mol⁻1