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LMCP 2502
PENGANGKUTAN BANDAR
TUGASAN HUBUNGAN SOSIOEKONOMI
DENGAN PENGANGKUTAN
DISEDIAKAN OLEH :
AISYAH SYAFIKA BINTI YUSRI
(A170969)
DISEDIAKAN UNTUK:
PROF. DATO. IR. DR. RIZA ATIQ BIN O.K
RAHMAT
P = 0.00005x - 0.0067
0
0.2
0.4
0.6
0.8
1
1.2
0 2000 4000 6000 8000 10000 12000 14000 16000 18000 20000
Pecahanmenaikikereta(P)
Pendapatan bulanan isi rumah
Graf pecahan menaiki kereta MELAWAN pendapatan
bulanan isi rumah
1. Graf pecahan menaiki kereta (paksi y) melawan pendatapan bulanan (paksi x)
2. y = 5X – 0.5X – 0.0067
3.
Pendapatan
bulanan isi
rumah
Pecahan
menaiki kereta
(P)
In [( 1 – P ) / P]
1000 0.05 2.9444
2000 0.06 2.7515
3000 0.10 2.1972
4000 0.15 1.7346
5000 0.25 1.0986
6000 0.31 0.8001
7000 0.39 0.4473
8000 0.48 0.0800
9000 0.52 -0.0800
10000 0.60 -0.4055
12000 0.75 -1.0986
14000 0.85 -1.7346
16000 0.89 -2.0907
18000 0.93 -2.5867
20000 0.95 -2.9444
y = -0.0003x + 2.9233
R² = 0.9789
-4
-3
-2
-1
0
1
2
3
4
0 5000 10000 15000 20000 25000
ln[(1–P)/P]
PENDAPATAN BULANAN ISI RUMAH
ln[( 1 – P ) / P]
ln[( 1 – P ) / P]
Linear (ln[( 1 – P ) / P])
4.
5) α= -0.0003 β= 2.9233
6)(a) 2.3 orang x 2100 unit kondominium = 4830 jumlah penduduk
(b) RM17000
(0.89) + (0.93)/2 = 0.91
ln(1-0.91)/0.91 = 2.31
(c) 1 - 0.91 = 0.09
(d)7-8 bas

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LMCP 2502- Pengakutan Bandar

  • 1. LMCP 2502 PENGANGKUTAN BANDAR TUGASAN HUBUNGAN SOSIOEKONOMI DENGAN PENGANGKUTAN DISEDIAKAN OLEH : AISYAH SYAFIKA BINTI YUSRI (A170969) DISEDIAKAN UNTUK: PROF. DATO. IR. DR. RIZA ATIQ BIN O.K RAHMAT
  • 2. P = 0.00005x - 0.0067 0 0.2 0.4 0.6 0.8 1 1.2 0 2000 4000 6000 8000 10000 12000 14000 16000 18000 20000 Pecahanmenaikikereta(P) Pendapatan bulanan isi rumah Graf pecahan menaiki kereta MELAWAN pendapatan bulanan isi rumah 1. Graf pecahan menaiki kereta (paksi y) melawan pendatapan bulanan (paksi x) 2. y = 5X – 0.5X – 0.0067
  • 3. 3. Pendapatan bulanan isi rumah Pecahan menaiki kereta (P) In [( 1 – P ) / P] 1000 0.05 2.9444 2000 0.06 2.7515 3000 0.10 2.1972 4000 0.15 1.7346 5000 0.25 1.0986 6000 0.31 0.8001 7000 0.39 0.4473 8000 0.48 0.0800 9000 0.52 -0.0800 10000 0.60 -0.4055 12000 0.75 -1.0986 14000 0.85 -1.7346 16000 0.89 -2.0907 18000 0.93 -2.5867 20000 0.95 -2.9444
  • 4. y = -0.0003x + 2.9233 R² = 0.9789 -4 -3 -2 -1 0 1 2 3 4 0 5000 10000 15000 20000 25000 ln[(1–P)/P] PENDAPATAN BULANAN ISI RUMAH ln[( 1 – P ) / P] ln[( 1 – P ) / P] Linear (ln[( 1 – P ) / P]) 4. 5) α= -0.0003 β= 2.9233 6)(a) 2.3 orang x 2100 unit kondominium = 4830 jumlah penduduk (b) RM17000 (0.89) + (0.93)/2 = 0.91 ln(1-0.91)/0.91 = 2.31 (c) 1 - 0.91 = 0.09 (d)7-8 bas