# By binomial expansion, if the 21st and 22nd terms are equal, thenC.pdf

A

By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer Solution By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer.

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### By binomial expansion, if the 21st and 22nd terms are equal, thenC.pdf

• 1. By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer Solution By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer
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