By binomial expansion, if the 21st and 22nd terms are equal, thenC.pdf

By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer Solution By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer.

By binomial expansion, if the 21st and 22nd terms are equal, then
C(44, 20) x^24 = C(44, 21) x^23
Solve for x,
x = C(44, 21)/C(44, 20) = 8/7 <==Answer
Solution
By binomial expansion, if the 21st and 22nd terms are equal, then
C(44, 20) x^24 = C(44, 21) x^23
Solve for x,
x = C(44, 21)/C(44, 20) = 8/7 <==Answer

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By binomial expansion, if the 21st and 22nd terms are equal, thenC.pdf

  • 1. By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer Solution By binomial expansion, if the 21st and 22nd terms are equal, then C(44, 20) x^24 = C(44, 21) x^23 Solve for x, x = C(44, 21)/C(44, 20) = 8/7 <==Answer